/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q44E Using equation (23), find the en... [FREE SOLUTION] | 91影视

91影视

Using equation (23), find the energy of a particle confined to a finite well whose walls are half the height of the ground-state infinite well energy, . (A calculator or computer able to solve equations numerically may be used, but this happens to be a case where an exact answer can be deduced without too much trouble.)

Short Answer

Expert verified

The energy of a particle confined to a finite well whose walls are half the height of the ground-state infinite well energy is 228mL2.

Step by step solution

01

Given data

There is a finite well whose walls are half the height of the ground-state infinite well energy, E1.

02

Ground state energy of infinite potential well and height of the finite potential well

The ground state energy of a particle of mass in an infinite well of width L is

E=222mL2 .....(I)

Here is the reduced Planck's constant.

The height of the finite potential well is

U0=2k22msec2kL2n-1<kL<nn=1,3,5...2k22mcsc2kL2n-1<kL<nn=2,4,6... .....(II)

03

Determining the energy of the finite well

The height of the well is half the ground state energy of an infinite potential well. Thus for n = 1

U0=E12

Substitute from equations (I) and (II) to get

2k22msec2kL2=224mL2k2sec2kL2=22L2cos2kL2=2k2L22

This has a solution for

k=2L

The corresponding energy is

E=2k22m=22m24L2=228mL2

Thus the required energy is 228mL2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.