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Assuming an interatomic spacing of 0.15 nm, obtain a rough value for the width (in eV) of then=2 band in a one-dimensional crystal.

Short Answer

Expert verified

The estimated value of the band width is 50鈥塭痴.

Step by step solution

01

Determine the formulas

Consider the relation between the wave numbers and the energy as follows:

E=h2k22m

Here, E is the energy, m is the effective mass, h is the planck鈥檚 constant and k is the wave number.

02

Determine the value of the width as:

Consider the formula for the change in energy as:

E=E2E1=h22m(k22k12)

Substitute the values and solve as:

E=h22m((2a2)(a2))=h22m(3a2)=3h222ma2

Solve further as:

E=3(1.0551034鈥塉蝉)(2)2(9.111031鈥塳驳)(0.15109鈥尘)2=50鈥塭痴

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