91影视

Local minimum is at x = a.

The expression for rotational energy is, ${\mathit{E}}_{\mathbf{r}\mathbf{o}\mathbf{t}}\mathbf{=}\frac{{\mathbf{鈩�}}^{\mathbf{2}}\mathbf{l}\mathbf{(}\mathbf{l}\mathbf{+}\mathbf{1}\mathbf{)}}{\mathbf{2}\mathbf{渭}{\mathbf{a}}^{\mathbf{2}}}$.

Where,$\mathrm{鈩�}鈫�$reduced Planck's constant,$I鈫�$rotational quantum number,$渭鈫�$reduced mass and$a鈫�$bond length in meters.

The reduced mass $\mathit{渭}$ is, $\mathit{渭}\mathbf{=}\frac{{\mathbf{m}}_{\mathbf{1}}{\mathbf{m}}_{\mathbf{2}}}{{\mathbf{m}}_{\mathbf{1}}\mathbf{+}{\mathbf{m}}_{\mathbf{3}}}$.

The expression for vibration energy is, ${\mathit{E}}_{\mathbf{\text{vib}}}\mathbf{=}\left(n+\frac{1}{2}\right)\mathit{鈩�}\sqrt{\frac{\mathbf{k}}{\mathbf{渭}}}$.

Where, $\mathrm{鈩�}鈫�$ Reduced Planck's constant, $n鈫�$ vibration quantum number and $渭鈫�$ Reduced mass.

(a)

The reduced mass$渭$is,$渭=\frac{m_1{m}_2}{m_1+m_3}$.

The rotational energy is expressed as$E_{rot}=\frac{{\mathrm{鈩�}}^{2}l(l+1)}{2渭a^2}$ .

In the above expression$\mathrm{鈩�},l$are constant, anddepends on the mass.

Therefore, the quantitywill affect the rotational energy$E_{rot}$.

The separation of the two atoms is equivalent to the orbital radius in a planetary system, which determines the rotational energy.

Therefore,Will affect the rotational energy$E_{rot}$.