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An electron moving to the lefi at \(0.8 c\) collides with an incoming photon moving to the right. Afuer the collision, the elactron is moving to the right at \(0.6 c\) and an outgoing photon moves to the lefi. What was the wavelength of the incoming photon?

Short Answer

Expert verified
The wavelength of the incoming photon is calculated by solving the system of equations derived from conservation of momentum and energy principles. The exact value will depend on the given values for the velocity of electrons and the speed of light, as well as Planck's constant and the mass of the electron.

Step by step solution

01

Calculate initial and final momentum

The initial momentum was \(p_{initial} = m \cdot v_{electron} - h/\lambda_{incoming}\) and the final momentum was \(p_{final} = m \cdot v'_{electron} + h/\lambda_{outgoing}\). Here, minus is used for the incoming photon because it's moving in the opposite direction to the direction convention (i.e., right direction). By conservation of momentum, we equate the initial and final momentum.
02

Calculate initial and final energy

The initial energy consisted of the kinetic energy of the electron and the energy of the incoming photon \(E_{initial} = \gamma m c^2 + h \cdot c/\lambda_{incoming}\). The final energy consisted of the kinetic energy of the electron after collision and the energy of the outgoing photon \(E_{final} = \gamma' m c^2 + h \cdot c/\lambda_{outgoing}\). Here gamma and gamma prime represent the Lorentz factor before and after the collision respectively. By conservation of energy, we equate the initial and final energy.
03

Solve for the Unknown

From the conservation of momentum and conservation of energy, we can solve the resulting equations to find the wavelength of the incoming photon. We substitute the given values into these equations to calculate the value of \(\lambda_{incoming}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
Momentum is a fundamental concept in physics that describes the quantity of motion an object possesses. It's important to understand the momentum in a photon-electron collision scenario. Momentum is conserved in isolated systems, meaning that the total momentum before the event is equal to the total momentum after the event.

In the described problem, the electron initially moves at 0.8c, and there’s an incoming photon. They have opposite directions, affecting how we calculate the momentum. The formula for initial momentum is:
  • Initial momentum (\(p_{initial}\)) = \(m imes v_{electron} - \frac{h}{\lambda_{incoming}}\).
The negative sign indicates the photon's opposite direction to our positive convention (chosen as right).

After the collision, the electron changes its direction, moving to the right at 0.6c, resulting in a different calculation for the final momentum:
  • Final momentum (\(p_{final}\)) = \(m imes v'_{electron} + \frac{h}{\lambda_{outgoing}}\).
Setting the initial momentum equal to the final momentum helps solve for unknowns, like the incoming photon’s wavelength.
Conservation of Energy
Energy conservation is a cornerstone of physics, stating that energy cannot be created or destroyed, only transformed. In a photon-electron collision, we equate the total energy before and after the collision to conserve energy.

Initially, the energy includes the kinetic energy of the electron and the energy of the incoming photon:
  • Initial energy (\(E_{initial}\)) = \(\gamma m c^2 + \frac{h \cdot c}{\lambda_{incoming}}\).
The term \(\gamma m c^2\) represents the relativistic kinetic energy using the Lorentz factor (\(\gamma\)).

After the collision, the electron's kinetic energy changes as it moves right, and the outgoing photon's energy is considered:
  • Final energy (\(E_{final}\)) = \(\gamma' m c^2 + \frac{h \cdot c}{\lambda_{outgoing}}\).
Conservation of energy ensures that \(E_{initial} = E_{final}\), helping to solve for the unknown \(\lambda_{incoming}\) when combined with momentum conservation equations.
Lorentz Factor
The Lorentz factor is a crucial element in relativity and quantum mechanics problems, especially in scenarios involving high velocities close to the speed of light. It adjusts calculations for time, length, and, importantly, energy.

Defined as:
  • \(\gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^2}}\)
It accounts for relativistic effects due to the electron's velocity. For example, in our photon-electron collision, the electron's speeds, both initial (0.8c) and final (0.6c), require using the Lorentz factor in energy calculations.

Changes in the Lorentz factor (\(\gamma\) for before collision and \(\gamma'\) after) reflect the shifted velocities and are crucial for determining precise energy alterations. Through factoring in these relativistic effects, one can accurately calculate energies and solve for the incoming photon's wavelength.

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Most popular questions from this chapter

Consider two separate objects of unequal temperature. What would you do with them and what would have to happen thereafter to enable them to reach the same common temperature? Use this idea to explain why the electromagnetic radiation enclosed in a cavity has a temperature that is the same as that of the cavity walls.

A photon scatters off of a free electron. (a) What is the maximum possible change in wavelength? (b) Suppose a photon scarters off of a free proton. What is the maximum possible change in wavelength now? (c) Which more clearly demonstrates the particle nature of electromagnetic radiation- - collision with an electron or collision with a proton?

According to the energy-lime uncertainty principle. the lifetime \(\Delta f\) of a state and the uncertainty \(\Delta E\) in its energy are inversely proportional. Hydrogen's \(656 \mathrm{~nm}\) red spectral line is the result of an electron making a transition "downward" from a quantum state whose lifetime is about \(10^{-8} s\) (a) What inherent uncertainty in the energy of the emitted photon docs this imply? (Note: Unfortunately. we might use the symbol \(\Delta E\) for the energy difference - i.e., the energy of the photon - but here if means the uncertain in that energy difference.) (b) To what range in wavelengths does this correspond? (As noted in Exercise \(2.57\). the uncertainty principle is one contributor to the broadening of spectral lines.) (c) Obtain a general formula relating \(\Delta \lambda\) to \(\Delta t\).

You are an early 20th-century experimental physicist and do not know the value of Planck's constant. By a suitable plot of the following data, and using Einstein's explanation of the photoelectic effect \((\mathrm{K} \mathrm{C})=h f-\phi\) where \(h\) is not known), determine Planck's constant. $$\begin{array}{cc}\begin{array}{c}\text { Wavelength of Lighe } \\\\(\text { nm })\end{array} & \begin{array}{c}\text { Stopping Potential } \\\\(\mathrm{V})\end{array} \\\\\hline 550 & 0.060 \\\\\hline 500 & 0.286 \\\\\hline 450 & 0.563 \\\\\hline 400 & 0.908 \\\\\hline\end{array}$$

A particle is described by $$ \psi(x)=\left\\{\begin{array}{ll} C & |x| \leq+\frac{1}{2} w \\ 0 & |x|>\frac{1}{2} w \end{array}\right. $$ What momenta can never be measured?

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