Chapter 8: Problem 8
Differentiate the function \(f\) where \(f(x)\) is (a) \((5 x+3)^{9}\) (b) \((4 x-2)^{7}\) (c) \((1-3 x)^{6}\) (d) \(\left(3 x^{2}-x+1\right)^{3}\) (e) \(\left(4 x^{3}-2 x+1\right)^{6}\) (f) \(\left(1+x-x^{4}\right)^{5}\)
Short Answer
Expert verified
\(f'(x)\) for each part: (a) 45(5x+3)^8, (b) 28(4x-2)^6, (c) -18(1-3x)^5, (d) (9x-3)(3x^2-x+1)^2, (e) 6(12x^2-2)(4x^3-2x+1)^5, (f) 5(1-4x^3)(1+x-x^4)^4.
Step by step solution
01
Differentiate (5x + 3)^9
Use the chain rule \(\frac{d}{dx}[u^n] = n \, u^{n-1} \, \frac{du}{dx}\) to differentiate. Here, \(u = 5x + 3\) and \(n = 9\). Thus, the derivative is \[9(5x + 3)^{8} \cdot 5 = 45(5x + 3)^8.\]
02
Differentiate (4x - 2)^7
Similarly, use the chain rule. Set \(u = 4x - 2\) and \(n = 7\). The derivative is \[7(4x - 2)^{6} \cdot 4 = 28(4x - 2)^6.\]
03
Differentiate (1 - 3x)^6
Using the chain rule, let \(u = 1 - 3x\) and \(n = 6\). The derivative is \[6(1 - 3x)^{5} \cdot (-3) = -18(1 - 3x)^5.\]
04
Differentiate (3x^2 - x + 1)^3
Apply the chain rule, where \(u = 3x^2 - x + 1\) and \(n = 3\). First, find \(\frac{du}{dx} = 6x - 1\). Then the derivative is \[3(3x^2 - x + 1)^{2} \cdot (6x - 1) = (9x - 3)(3x^2 - x + 1)^{2}.\]
05
Differentiate (4x^3 - 2x + 1)^6
With \(u = 4x^3 - 2x + 1\) and \(n = 6\), find \(\frac{du}{dx} = 12x^2 - 2\). The derivative is \[6(4x^3 - 2x + 1)^{5} \cdot (12x^2 - 2) = 6(12x^2 - 2)(4x^3 - 2x + 1)^5.\]
06
Differentiate (1 + x - x^4)^5
For \(u = 1 + x - x^4\) and \(n = 5\), compute \(\frac{du}{dx} = 1 - 4x^3\). The derivative is \[5(1 + x - x^4)^{4} \cdot (1 - 4x^3) = 5(1 - 4x^3)(1 + x - x^4)^4.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental technique in calculus used for differentiating composite functions. When you have a function within another function, the chain rule helps to find the derivative by breaking down the problem into simpler parts.
For a composite function where one function, say \( u \), is raised to a power \( n \), you can use the chain rule formula:
For a composite function where one function, say \( u \), is raised to a power \( n \), you can use the chain rule formula:
- Find the derivative of the outer function considering the inner function as a single variable, which is \( n \times u^{n-1} \).
- Multiply it by the derivative of the inner function \( \frac{du}{dx} \).
Polynomial Functions
Polynomial functions are a type of algebraic expression that consist of variables raised to whole number powers, combined using addition, subtraction, and multiplication. They can be as simple as a single term like \( x^2 \) or more complex, like \( 4x^3 - 2x + 1 \).
Each term in a polynomial function is made up of:
Each term in a polynomial function is made up of:
- A coefficient, which is a constant number multiplied by the variable.
- A variable raised to a power (the exponent).
Exponentiation
Exponentiation is a fundamental operation in mathematics where a number, known as the base, is raised to the power of an exponent. This process represents repeated multiplication of the base.
For example:
For example:
- \( x^2 \) means \( x \) multiplied by itself.
- \( x^3 \) equals \( x \times x \times x \).
Derivative Calculation
Derivative calculation is a core aspect of calculus that allows us to determine the rate at which a function changes at any given point. This concept is the backbone of both differential calculus and many real-world applications, such as calculating velocity or understanding trends.
Here is a basic approach to computing a derivative:
Here is a basic approach to computing a derivative:
- Identify the function type and the rules needed to differentiate. For example, use the chain rule for composite functions or the power rule for simple power functions.
- Apply the appropriate rule and simplify as you calculate. For example, when differentiating \((4x^3 - 2x + 1)^6\), identify \( u = 4x^3 - 2x + 1 \) and \( n = 6 \), leading to a derivative of \( 6(4x^3 - 2x + 1)^5 \cdot (12x^2 - 2) \).