Chapter 8: Problem 3
Consider the function \(f(x)=2 x^{3}-3 x^{2}+x+3\). Find (a) the derivative of \(f(x)\) from first principles; (b) the rate of change of \(f(x)\) at \(x=1\); (c) the points at which the line through \((1,3)\) with slope \(m\) cuts the graph of \(f(x)\); (d) the values of \(m\) such that two of the points of intersection found in (c) are coincident; (e) the equations of the tangents to the graph of \(f(x)\) at \(x=1\) and \(x=\frac{1}{4}\).
Short Answer
Step by step solution
Derivative from First Principles
Rate of Change at x=1
Points of Intersection
Coincident Points
Equations of Tangents
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative from First Principles
To apply this, consider a function like \( f(x) = 2x^3 - 3x^2 + x + 3 \). The derivative from first principles involves the formula:
- \( f'(x) = \lim_{{h \to 0}} \frac{f(x+h) - f(x)}{h} \)
Expanding the Expression
Begin by finding \( f(x+h) \) by substituting \( x+h \) into the function. You'll expand and simplify terms like \((x+h)^3 \) and \((x+h)^2 \) to find the difference \( f(x+h) - f(x) \).Limit and Simplification
After simplifying this difference, divide by \( h \) and take the limit as \( h \to 0 \). In our function, this method ultimately reveals that \( f'(x) = 6x^2 - 6x + 1 \). This result gives the exact rate of how the function \( f(x) \) changes at any point \( x \). It’s a precise snapshot of the function’s behavior.Rate of Change
Using the derivative we’ve obtained from first principles, analyzing the rate of change becomes simple. Substituting \( x=1 \) into the derivative \( f'(x) = 6x^2 - 6x + 1 \) gives:
- \( f'(1) = 6 \times 1^2 - 6 \times 1 + 1 \)
- Which simplifies to \( 1 \).
Why It's Important
The rate of change is crucial for understanding real-world phenomena modeled by polynomial functions. Whether it's how fast a car accelerates or how a population grows, the derivative at a point shows the instantaneous rate of change - a powerful insight for decision-making and predictions.Tangent Lines
To find a tangent line at a given point on a graph of a function, you need two things:
- The point of tangency \((x_0, f(x_0))\)
- The slope of the tangent line \( f'(x_0) \)
Equation of the Tangent
Using the point-slope form of a line \( y - y_1 = m(x - x_1) \), where \( m \) is the slope:- At \( x = 1 \), the equation is \( y - 3 = 1(x - 1) \).
- This simplifies to \( y = x + 2 \).
Polynomial Functions
In the function \( f(x) = 2x^3 - 3x^2 + x + 3 \), we have a cubic polynomial.
- The term \( 2x^3 \) dominates the function's shape as \( x \) becomes very large or very small.
- The other terms \(-3x^2, x,\) and \(3\) adjust the curve's overall form and position.