Chapter 8: Problem 18
Find the radius of curvature at \((x, y)\) of the curve $$ y=\tanh ^{-1} x \quad(|x|<1) $$
Short Answer
Expert verified
The radius of curvature is \( R = \left| \frac{(1 + x^2)^{3/2}}{2x} \right| \).
Step by step solution
01
Differentiate the Curve
Given the curve \( y = \tanh^{-1} x \), we need to find the first derivative \( \frac{dy}{dx} \). It is known that \( \frac{d}{dx}[\tanh^{-1} x] = \frac{1}{1-x^2} \). Thus, the first derivative is \( \frac{dy}{dx} = \frac{1}{1-x^2} \).
02
Differentiate Again for the Second Derivative
To find the radius of curvature, we also need the second derivative \( \frac{d^2y}{dx^2} \). Differentiate \( \frac{1}{1-x^2} \) with respect to \( x \):\[\frac{d^2y}{dx^2} = \frac{d}{dx} \left( \frac{1}{1-x^2} \right) = \frac{2x}{(1-x^2)^2}\]
03
Apply the Radius of Curvature Formula
The radius of curvature \( R \) is given by:\[R = \left| \frac{(1 + (\frac{dy}{dx})^2)^{3/2}}{\frac{d^2y}{dx^2}} \right|\]Substitute the derivatives found:\[R = \left| \frac{(1 + (\frac{1}{1-x^2})^2)^{3/2}}{\frac{2x}{(1-x^2)^2}} \right|\]
04
Simplify the Expression
Simplify the expression for \( R \):\[R = \left| \frac{(1 + \frac{1}{(1-x^2)^2})^{3/2}}{\frac{2x}{(1-x^2)^2}} \right| = \left| \frac{((1-x^2)^2 + 1)^{3/2}}{2x} \right|\]
05
Final Expression for Radius of Curvature
This simplifies further to:\[R = \left| \frac{(1 + x^2)^{3/2}}{2x} \right|\]This is the radius of curvature at any point \((x, y)\) on the curve \(y = \tanh^{-1} x\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Radius of Curvature
The radius of curvature is a measure that represents the curve's "bending" at a particular point. Imagine driving on a winding road. The radius of curvature would be like the size of the circle that best fits the bend of the road at any point.
For a curve described by the equation \(y = f(x)\), we use a specific formula to find the radius of curvature:
This formula requires both the first \(\frac{dy}{dx}\) and the second derivatives \(\frac{d^2y}{dx^2}\). Remember, the more sharply the curve bends, the smaller the radius of curvature. Conversely, a gentle curve would have a larger radius as it approximates more of a straight line. To find it for a given curve, like \(y = \tanh^{-1} x\) in this case, we substitute the derivatives into the formula and simplify.
For a curve described by the equation \(y = f(x)\), we use a specific formula to find the radius of curvature:
- \(R = \left| \frac{(1 + (\frac{dy}{dx})^2)^{3/2}}{\frac{d^2y}{dx^2}} \right| \)
This formula requires both the first \(\frac{dy}{dx}\) and the second derivatives \(\frac{d^2y}{dx^2}\). Remember, the more sharply the curve bends, the smaller the radius of curvature. Conversely, a gentle curve would have a larger radius as it approximates more of a straight line. To find it for a given curve, like \(y = \tanh^{-1} x\) in this case, we substitute the derivatives into the formula and simplify.
Derivatives
Derivatives are a fundamental concept in calculus that represent the rate of change. For a function \(y = f(x)\), the first derivative \(\frac{dy}{dx}\) measures how \(y\) changes with a small change in \(x\).
This is essentially the slope of the tangent line to the curve at any given point. If \(\frac{dy}{dx}\) is positive, the function is increasing; if negative, the function is decreasing. When calculating the radius of curvature, the first and second derivatives are both necessary
In our exercise, the first derivative of \(y = \tanh^{-1} x\) is \(\frac{dy}{dx} = \frac{1}{1-x^2}\). The second derivative tells us how the slope is changing, giving deeper insight into the curve's "bending." For \(y = \tanh^{-1} x\), the second derivative is \(\frac{d^2y}{dx^2} = \frac{2x}{(1-x^2)^2}\). These derivatives were used to calculate the radius of curvature.
This is essentially the slope of the tangent line to the curve at any given point. If \(\frac{dy}{dx}\) is positive, the function is increasing; if negative, the function is decreasing. When calculating the radius of curvature, the first and second derivatives are both necessary
In our exercise, the first derivative of \(y = \tanh^{-1} x\) is \(\frac{dy}{dx} = \frac{1}{1-x^2}\). The second derivative tells us how the slope is changing, giving deeper insight into the curve's "bending." For \(y = \tanh^{-1} x\), the second derivative is \(\frac{d^2y}{dx^2} = \frac{2x}{(1-x^2)^2}\). These derivatives were used to calculate the radius of curvature.
Inverse Hyperbolic Functions
Inverse hyperbolic functions, like \(\tanh^{-1} x\), are interesting counterparts to the inverse trigonometric functions. They are representations of the inverse functions of hyperbolic functions such as hyperbolic sine and hyperbolic cosine.
The notation \(\tanh^{-1} x\) specifically represents the inverse of the hyperbolic tangent function. Its domain is \(|x| < 1\), which ensures that the function behaves nicely and is well-defined. Hyperbolic functions themselves originate from a hyperbola, similar to how trigonometric functions originate from a circle.
This connection to hyperbolas makes them useful in various applications, including calculus, where modelling of real-world situations often occurs using these functions due to their natural appearance in the solutions of certain differential equations. Understanding inverse hyperbolic functions helps streamline working with functions like \(y = \tanh^{-1} x\) in calculus, especially when calculating derivatives and curvatures.
The notation \(\tanh^{-1} x\) specifically represents the inverse of the hyperbolic tangent function. Its domain is \(|x| < 1\), which ensures that the function behaves nicely and is well-defined. Hyperbolic functions themselves originate from a hyperbola, similar to how trigonometric functions originate from a circle.
This connection to hyperbolas makes them useful in various applications, including calculus, where modelling of real-world situations often occurs using these functions due to their natural appearance in the solutions of certain differential equations. Understanding inverse hyperbolic functions helps streamline working with functions like \(y = \tanh^{-1} x\) in calculus, especially when calculating derivatives and curvatures.