Chapter 5: Problem 58
Given $$ \boldsymbol{A}=\left[\begin{array}{lll} 1 & 0 & 2 \\ 6 & 4 & 0 \\ 6 & -2 & 1 \end{array}\right] \text { and } \boldsymbol{B}=\left[\begin{array}{ccc} 5 & 2 & 4 \\ 3 & -1 & 2 \\ 1 & 4 & -3 \end{array}\right] $$ find \(\boldsymbol{A}^{-1}\) and \(\boldsymbol{B}^{-1}\). Verify that \((\boldsymbol{A} \boldsymbol{B})^{-1}=\boldsymbol{B}^{-1} \mathbf{A}^{-1}\).
Short Answer
Step by step solution
Calculate the determinant of A
Compute inverse of A
Calculate the determinant of B
Compute inverse of B
Calculate AB and (AB)^{-1}
Verify (AB)^{-1} = B^{-1}A^{-1}
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant Calculation
Adjugate Matrix
- **Cofactor matrix:** Each element is the determinant of a smaller matrix, called a minor, obtained by deleting the current row and column.
- **Transpose:** Flip the matrix over its diagonal.
Matrix Multiplication
Inverse of a Product of Matrices
- First compute \(\boldsymbol{A}\boldsymbol{B}\).
- Find the inverse \((\boldsymbol{A}\boldsymbol{B})^{-1}\).
- Separately calculate \(\boldsymbol{B}^{-1}\) and \(\boldsymbol{A}^{-1}\), then multiply them.
- Compare \((\boldsymbol{A}\boldsymbol{B})^{-1}\) with \(\boldsymbol{B}^{-1}\boldsymbol{A}^{-1}\).