Chapter 2: Problem 9
A function \(f\) is defined by $$ f(x)=\left\\{\begin{array}{cl} 0 & (x<-1) \\ x+1 & (-1 \leqslant x<0) \\ 1-x & (0 \leqslant x \leqslant 1) \\ 0 & (x>1) \end{array}\right. $$ Sketch on separate diagrams the graphs of \(f(x)\) \(f\left(x+\frac{1}{2}\right), f(x+1), f(x+2), f\left(x-\frac{1}{2}\right), f(x-1)\) and \(f(x-2)\).
Short Answer
Step by step solution
Understand the Base Function
Graph the Base Function \( f(x) \)
Graph \( f(x + \frac{1}{2}) \)
Graph \( f(x+1) \)
Graph \( f(x+2) \)
Graph \( f(x - \frac{1}{2}) \)
Graph \( f(x-1) \)
Graph \( f(x-2) \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Transformation
For example, if you add or subtract a value inside the function's brackets (e.g., replacing \( f(x) \) with \( f(x + 1) \)), you're horizontally shifting the graph. This transformation does not change the function's boundaries vertically but moves it left or right.
Consider each shift as a way to explore how different inputs may impact outputs visually. The piecewise function given in the problem serves as a base that undergoes these transformations to help understand how shifts affect the function graphically.
Graph Sketching
To sketch, meticulously plot each segment one at a time:
- For \( x < -1 \), the function is \( f(x) = 0 \).
- From \( -1 \leq x < 0 \), use \( f(x) = x + 1 \), a linear function creating a line passing through \( (-1,0) \) to \( (0,1) \).
- Within \( 0 \leq x \leq 1 \), use \( f(x) = 1 - x \), another line decreasing from \( (0,1) \) to \( (1,0) \).
- Finally, for \( x > 1 \), return to \( f(x) = 0 \).
Horizontal Shifts
For shifts to the right, the inside of the function involves a subtraction, such as \( f(x-1) \) or \( f(x-2) \). Conversely, adding inside moves the function to the left, as with \( f(x+1) \).The horizontal shift impacts every interval in the function definition; thus, understanding the transformation involves adjusting these intervals respectively:
- \( f(x + 1) \): Shift left by 1 unit.
- \( f(x-1) \): Shift right by 1 unit.
- \( f(x-2) \): Shift right by 2 units.
- Adjust your graph's points to reflect these new positions while keeping the overall structure of each segment unchanged.
Interval Analysis
For example, in the given function, \( f(x) = 0 \) for intervals \( x < -1 \) and \( x > 1 \). As you've seen, these intervals determine when each formula in the piecewise definition applies.
When conducting interval analysis, you:
- Recognize boundaries of each interval felt by the function expression inside it.
- Account for different behavior when transforming and shifting, reassessing each function section.