/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Plot the curve whose parametric ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Plot the curve whose parametric equations are \(x=t(t+4), y=t+1\). Show that it is a parabola.

Short Answer

Expert verified
The curve is a parabola: \(x = y^2 + 2y - 3\).

Step by step solution

01

Understanding the Parametric Equations

The given parametric equations are:\[x = t(t + 4)\]\[y = t + 1\].In these equations, \(t\) is the parameter that defines the relationship between \(x\) and \(y\). Our goal is to eliminate \(t\) to express \(x\) as a function of \(y\). This will help determine the type of curve represented by these equations.
02

Express t in terms of y

From the second parametric equation, solve for \(t\):\[y = t + 1\]\[t = y - 1\].This expression allows us to substitute \(t\) in the first parametric equation to eliminate the parameter.
03

Substitute t in the x equation

Substitute \(t = y - 1\) into the parametric equation for \(x\):\[x = (y - 1)((y - 1) + 4)\]\[x = (y - 1)(y + 3)\].Simplify this expression to find \(x\) in terms of \(y\).
04

Simplify the expression

Simplify the expression from the previous step:\[x = (y - 1)(y + 3)\]\[x = y^2 + 3y - y - 3\]\[x = y^2 + 2y - 3\].This quadratic equation represents \(x\) in terms of \(y\).
05

Identify the type of curve

The equation obtained, \(x = y^2 + 2y - 3\), is a quadratic equation in \(y\), indicating a parabola. The general form of a parabolic equation is \(x = ay^2 + by + c\), which matches the form we have here. Thus, the curve described by the parametric equations is a parabola.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Parametric Equations
Parametric equations are a way to represent a curve by expressing the coordinates of the points on the curve as functions of a variable, typically denoted by \( t \). This variable is known as the parameter. In the problem, we have the parametric equations \( x = t(t+4) \) and \( y = t+1 \). Here, \( t \) acts as the parameter which helps describe both \( x \) and \( y \) in terms of a third variable instead of directly relating \( x \) and \( y \).

Using parametric equations is beneficial because:
  • They can simplify complex curves which may be difficult to represent with a single function.
  • They allow for precise control over the path traced by the curve as \( t \) changes.
  • They are instrumental in computer graphics and simulations for creating motion trajectories.
In this particular exercise, the steps involve eliminating \( t \) to find a direct relationship between \( x \) and \( y \), effectively translating the parametric form into a standard equation.
Basics of Curve Plotting
Curve plotting is the process of graphically representing the relationship between two or more variables on a coordinate system. When it comes to parametric equations, the plot requires evaluating the equations over a range of values for the parameter \( t \). As \( t \) varies, the corresponding values of \( x \) and \( y \) define points on the curve.

Here’s a simple way to approach curve plotting with parametric equations:
  • Choose a range for \( t \), considering negative, zero, and positive values if applicable.
  • Calculate corresponding values of \( x \) and \( y \) using the parametric equations.
  • Plot these \( (x, y) \) coordinate pairs on the graph.
This hands-on approach helps in visualizing the shape and direction of the curve. In the case of the provided parametric equations, by eliminating \( t \), we obtained a quadratic equation indicating a parabolic shape. Hence, the plot of this curve is a parabola, showcasing a characteristic symmetric arch.
Exploring Quadratic Equations
A quadratic equation is any equation that can be rearranged into the standard form \( ax^2 + bx + c = 0 \). It’s characterized by the squared term \( x^2 \), which defines the fundamental parabolic shape.

Key properties of quadratic equations include:
  • The graph of a quadratic equation is typically a parabola.
  • A parabola has an "axis of symmetry," which is a vertical line that passes through its vertex (the highest or lowest point).
  • The shape and direction of the parabola (opening upwards or downwards) are determined by the sign of the \( a \) coefficient in the equation.
For example, in the exercise, transforming \( t \) from the parametric form to eliminate it led to \( x = y^2 + 2y - 3 \), a quadratic equation in \( y \), thus confirming that the curve is a parabola. This process showcases the flexibility of quadratic equations in representing different shapes and understanding their visual characteristics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.