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An advertising agency notes that approximately one in fifty potential buyers of a product sees a given magazine advertisement and one in five sees the corresponding advertisement on television. One in a hundred sees both. One in three of those who have seen the advertisement purchase the product, and one in ten of those who have not seen it also purchase the product. What is the probability that a randomly selected potential customer will purchase the product?

Short Answer

Expert verified
The probability is 14.9%.

Step by step solution

01

Define Probabilities

Let's define the probabilities given in the exercise using the events: \( A \) is the event that a potential buyer sees the magazine ad, \( B \) is the event that the buyer sees the TV ad. We know that \( P(A) = \frac{1}{50} \), \( P(B) = \frac{1}{5} \), and \( P(A \cap B) = \frac{1}{100} \). These represent the probabilities of seeing the advertisements.
02

Apply the Inclusion-Exclusion Principle

Since some potential buyers see both ads, we use the inclusion-exclusion principle to find the probability of a buyer seeing at least one ad: \( P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{1}{50} + \frac{1}{5} - \frac{1}{100} \). Calculate this to find \( P(A \cup B) \).
03

Simplify the Probability Calculation

Perform the arithmetic: \( \frac{1}{50} = 0.02 \), \( \frac{1}{5} = 0.20 \), and \( \frac{1}{100} = 0.01 \). Thus, \( P(A \cup B) = 0.02 + 0.20 - 0.01 = 0.21 \). This gives the probability of a buyer seeing at least one advertisement.
04

Calculate Conditional Probabilities

Two situations occur: either the buyer has seen at least one ad or they haven't. For those who have seen at least one ad, the probability of purchasing is \( \frac{1}{3} \). For those who haven't seen any ad, the probability is \( \frac{1}{10} \).
05

Calculate Total Purchase Probability

Using the law of total probability, compute the total probability of purchase: \( P(Purchase) = P(Purchase | A \cup B) \cdot P(A \cup B) + P(Purchase | (A \cup B)^c) \cdot P((A \cup B)^c) \), where \( P(A \cup B)^c = 1 - P(A \cup B) = 0.79 \).
06

Perform Calculation and Result

Substitute the known values into the formula: \( P(Purchase) = \frac{1}{3} \times 0.21 + \frac{1}{10} \times 0.79 \). Calculate this expression: \( P(Purchase) = 0.07 + 0.079 = 0.149 \).
07

Conclusion

The final probability that a randomly selected potential customer will purchase the product is 0.149, or 14.9%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inclusion-Exclusion Principle
Understanding the Inclusion-Exclusion Principle is crucial when dealing with overlapping probabilities in probability theory. In many situations, events in a probability problem are not mutually exclusive; thus, the probabilities need adjustments to account for overlaps.

Take for example the problem of determining how many potential buyers see at least one advertisement, whether it is in a magazine or on television. If we directly added the probabilities of seeing each ad separately, we'd count those who see both ads twice. Therefore, the Inclusion-Exclusion Principle helps us correctly calculate this probability by subtracting the overlap. Here’s how it works:
  • Start by finding the probability of each event happening individually, like seeing the magazine ad or the TV ad.
  • Sum these probabilities.
  • Subtract the probability that both events happen simultaneously, which is counted twice initially.
This adjustment ensures that the calculated probability of the buyer seeing at least one advertisement is accurate and avoids overcounting.
Conditional Probability
Conditional probability is vital when we want to calculate the probability of an event occurring, given that another event has already happened. In our problem, two types of conditional probabilities help us measure the likelihood of a purchase:

First, consider those who have seen at least one advertisement. Here, the conditional probability looks at what fraction of these viewers proceed to make a purchase. A given factor of interest, in this case, is \(\frac{1}{3}\), the probability that viewers of at least one ad purchase the product.
  • Event A is viewing at least one ad, while the purchase is the conditionally dependent event.
  • Expressed mathematically, it is written as \(P(Purchase | A) \), which evaluates to \(\frac{1}{3}\).
Another considered probability involves those who have not seen any ad. For these individuals, the conditional probability of purchasing the product is significantly lower. It is given as \(\frac{1}{10}\). By considering both scenarios, we factor in both types of customers when evaluating the overall purchase probability.
Law of Total Probability
The Law of Total Probability is a powerful tool used to calculate the overall probability of an event based on several mutually exclusive scenarios. In the advertising exercise, it helps to determine the probability that a randomly selected customer will purchase the product.

The principle is applied by dividing the entire sample space into distinct parts (buyers who see ads and those who don't) and summing up the probabilities from these sections. Here's how it works in this context:
  • Calculate the probability of a purchase given that the buyer saw at least one ad, then multiply it by the probability of seeing at least one ad.
  • Similarly, compute for buyers who saw no ads by multiplying their purchase probability by the probability of seeing no ads.
  • Sum these products to get the total purchase probability: \(P(Purchase) = P(Purchase | A \cup B) \cdot P(A \cup B) + P(Purchase | (A \cup B)^c) \cdot P((A \cup B)^c)\).
This comprehensive approach leads to a complete overview of the likelihood of a purchase, considering all potential scenarios.

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Most popular questions from this chapter

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