Chapter 1: Problem 67
The cubic equation \(x^{3}+2 x-2=0\) can be written as(a) \(x=1-\frac{1}{2} x^{3}\) (b) \(x=\frac{2}{2+x^{2}}\) (c) \(x=(2-2 x)^{1 / 3}\) Determine which of the corresponding iteration processes converges most rapidly to find the real root of the equation. Hence calculate the root to \(3 \mathrm{dp}\).
Short Answer
Step by step solution
Understand the Problem
Examine Iterative Formulas
Test Convergence of Each Method
Evaluate Derivatives Near Root
Iteratively Compute the Root
Verify the Iterative Process
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Iterative Methods
There are several iterative methods, but for cubic equations, common techniques include Fixed Point Iteration and Newton-Raphson. The examples in the exercise represent different forms of Fixed Point Iteration. Each option reformulates the original equation into a form, i.e., \(x = g(x)\), suitable for such an approach.
- Begin with an initial guess, \(x_0\).
- Apply the iteration formula: \(x_{n+1} = g(x_n)\).
- Repeat until the sequence stabilizes, indicating convergence to the actual root.
Convergence
For a method to converge, the sequence generated must become increasingly accurate. This is typically assessed using derivatives. In our context, convergence is examined by evaluating \(g'(x)\), the derivative of the iteration formula:
- A method converges if \(|g'(x)| < 1\) at the approximate root.
- The closer \(|g'(x)|\) is to zero, the faster the convergence.
Root Finding
For this specific exercise, each iterative formula represents a pathway to uncover this root by restructuring the equation. The main goal is to simplify the problem into a sequence that closes in on the correct \(x\):
- Choose an appropriate iterative method.
- Initialize with an educated guess.
- Refine this guess through repeated application of the iteration formula.
Derivative Evaluation
In this exercise, calculating derivatives for each iteration method allowed us to gauge their suitability:
- Option (a) has \(g'(x) = -\frac{3}{2}x^2\).
- Option (b) has \(g'(x) = -\frac{4x}{(2+x^2)^2}\).
- Option (c) has \(g'(x) = -\frac{2}{3}(2-2x)^{-2/3}\).