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Discuss the convergence of (a) \(\frac{2}{1^{2}}+\frac{3}{2^{2}}+\frac{4}{3^{2}}+\frac{5}{4^{2}}+\ldots\) (b) \(\sum_{l=1}^{-} \frac{k^{p}}{k !} \quad(a l l p)\) (c) \(\frac{1}{11}-\frac{2}{13}+\frac{3}{15}-\frac{4}{17}+\ldots\) (d) \(1-\frac{1}{3}+\frac{1}{5}-\frac{1}{7}+\ldots\)

Short Answer

Expert verified
(a) Divergent, (b) Convergent for all \( p \), (c) Convergent, (d) Convergent.

Step by step solution

01

Analyze the series in (a)

The series is given as \( \frac{2}{1^2} + \frac{3}{2^2} + \frac{4}{3^2} + \frac{5}{4^2} + \ldots \). Each term of the series is in the form \( \frac{n+1}{n^2} \) and as \( n \to \infty \), \( \frac{n+1}{n^2} \to 0 \).To determine convergence, consider that for large \( n \), \( \frac{n+1}{n^2} \approx \frac{1}{n} \). The harmonic series \( \sum \frac{1}{n} \) is known to diverge. Therefore, by comparison test, \( \sum \frac{n+1}{n^2} \) also diverges.
02

Examine series in (b)

The series is \( \sum_{k=1}^{\infty} \frac{k^p}{k!} \) for all \( p \).We use the Ratio Test for convergence. Compute the terms:\[ a_k = \frac{k^p}{k!}, \quad a_{k+1} = \frac{(k+1)^p}{(k+1)!}. \]The ratio is:\[ \frac{a_{k+1}}{a_k} = \frac{(k+1)^p}{(k+1)k^p}. \]Simplifying give us:\[ \frac{a_{k+1}}{a_k} = \frac{(k+1)^p}{(k+1)k^p} = \left(\frac{k+1}{k}\right)^p \frac{1}{k+1} \to \frac{1}{k} \text{ as } k \to \infty. \]The limit of this ratio as \( k \to \infty \) is \( 0 \), indicating the series converges for all \( p \).
03

Consider series in (c)

The series is \( \frac{1}{11} - \frac{2}{13} + \frac{3}{15} - \frac{4}{17} + \ldots \).This is an alternating series. The term in the \( n \)-th position is given by:\[ a_n = (-1)^{n+1} \cdot \frac{n}{2n+9}. \]The series converges if the absolute value of the terms \( |a_n| = \frac{n}{2n+9} \to 0 \), which it does. Thus, by the Alternating Series Test, the series converges.
04

Analyze series in (d)

The series is \( 1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \ldots \).This is the alternating harmonic series, which is known to converge conditionally because the absolute value of the terms monotonically decreases to zero:\[ \left| \frac{1}{2n-1} \right| \to 0 \text{ as } n \to \infty. \]By the Alternating Series Test, this series converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Harmonic Series
The harmonic series is a fascinating example when discussing series convergence in calculus. It takes the form \( \sum \frac{1}{n} \) where \( n \) is a natural number starting from 1. An interesting property of the harmonic series is that, although the terms \( \frac{1}{n} \) become smaller as \( n \) increases, the entire series itself diverges. This means that as more terms are added, the total sum grows without bounds.
To understand this better, consider the comparison with a simpler series like \( \sum \frac{1}{2^n} \), which does converge because each term halves each time, thus not allowing the sum to grow infinitely. This distinct nature of the harmonic series—having terms that decrease slowly—results in divergence. The harmonic series plays a crucial role in understanding series behavior in calculus.
Alternating Series
Alternating series are series whose terms alternate in sign. An example is \( 1 - \frac{1}{3} + \frac{1}{5} - \frac{1}{7} + \ldots \), where the positive and negative terms occur alternately. This setup can lead to the series exhibiting special convergence properties.
The essential idea behind alternating series is the back-and-forth summing, which can lead to a converging behavior even when the non-alternating counterpart (like the harmonic) diverges. Such series often converge to a finite sum even if each term's absolute value decreases slower.
The alternating series test helps determine this convergence by checking if the absolute value of terms lessens steadily to zero. In many naturally occurring mathematical patterns, alternating series come up, showcasing their importance in analysis.
Ratio Test
The ratio test is a powerful tool for determining the convergence or divergence of infinite series. Utilized often when the series terms involve factorials or exponentials, it entails calculating the limit of the absolute value of the ratio of successive terms.
To apply the ratio test, for a series \( a_k \), compute \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \). If this limit is less than 1, the series converges absolutely. If the limit is greater than 1 (or infinity), the series diverges. If it equals 1, the test is inconclusive.
The elegance of the ratio test lies in its simplicity and power to deliver quick insight into the behavior of complex series, particularly where exponential growth or decay decides the fate of convergence.
Alternating Series Test
The alternating series test is a simple yet effective method for investigating the convergence of series with alternating positive and negative terms. To use this test, the series must satisfy two conditions:
  • The absolute value of the terms must decrease monotonically.
  • The absolute value of the terms should approach zero as \( n \) approaches infinity.
If both conditions are met, the alternating series converges.
An example, as examined in one of the problems, is the series \( \frac{1}{11} - \frac{2}{13} + \frac{3}{15} - \ldots \). This series passes the alternating series test, showcasing convergence due to its decreasing term magnitude and the alternating nature.
The practicality of this test makes it indispensable for mathematicians and students alike when confronting series with alternating signs, allowing quick and efficient conclusions on convergence behavior.

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