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(a) If \(x_{r}=r(r-1)(2 r-5)\), calculate \(\sum_{r=0}^{4} x_{r}\) (b) If \(x_{r}=r^{r+1}+3(-1)^{r}, \quad\) calculate \(\sum_{r=1}^{5} x_{r}\) (c) If \(x_{r}=r^{2}-3 r+1, \quad\) calculate \(\sum_{r=2}^{6} x_{r}\)

Short Answer

Expert verified
(a) 12; (b) 16636; (c) 35.

Step by step solution

01

Calculate Each Term for Part (a)

We have the expression \(x_{r}=r(r-1)(2r-5)\). Calculate each term from \(r=0\) to \(r=4\). - For \(r=0\): \(x_{0}=0(0-1)(2*0-5)=0\)- For \(r=1\): \(x_{1}=1(1-1)(2*1-5)=0\)- For \(r=2\): \(x_{2}=2(2-1)(2*2-5)=-6\)- For \(r=3\): \(x_{3}=3(3-1)(2*3-5)=6\)- For \(r=4\): \(x_{4}=4(4-1)(2*4-5)=12\)
02

Sum the Terms for Part (a)

Now that we have calculated each term, sum them up: \(\sum_{r=0}^{4} x_{r} = x_{0} + x_{1} + x_{2} + x_{3} + x_{4} = 0 + 0 - 6 + 6 + 12 = 12\)
03

Calculate Each Term for Part (b)

We have the expression \(x_{r}=r^{r+1}+3(-1)^{r}\). Calculate each term from \(r=1\) to \(r=5\). - For \(r=1\): \(x_{1}=1^{2}+3(-1)^{1}=1-3=-2\)- For \(r=2\): \(x_{2}=2^{3}+3(-1)^{2}=8+3=11\)- For \(r=3\): \(x_{3}=3^{4}+3(-1)^{3}=81-3=78\)- For \(r=4\): \(x_{4}=4^{5}+3(-1)^{4}=1024+3=1027\)- For \(r=5\): \(x_{5}=5^{6}+3(-1)^{5}=15625-3=15622\)
04

Sum the Terms for Part (b)

Sum the calculated terms:\(\sum_{r=1}^{5} x_{r} = x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = -2 + 11 + 78 + 1027 + 15622 = 16636\)
05

Calculate Each Term for Part (c)

We have the expression \(x_{r}=r^{2}-3r+1\). Calculate each term from \(r=2\) to \(r=6\).- For \(r=2\): \(x_{2}=2^{2}-3*2+1=4-6+1=-1\)- For \(r=3\): \(x_{3}=3^{2}-3*3+1=9-9+1=1\)- For \(r=4\): \(x_{4}=4^{2}-3*4+1=16-12+1=5\)- For \(r=5\): \(x_{5}=5^{2}-3*5+1=25-15+1=11\)- For \(r=6\): \(x_{6}=6^{2}-3*6+1=36-18+1=19\)
06

Sum the Terms for Part (c)

Sum the calculated terms:\(\sum_{r=2}^{6} x_{r} = x_{2} + x_{3} + x_{4} + x_{5} + x_{6} = -1 + 1 + 5 + 11 + 19 = 35\)
07

Conclusion: Final Answers for All Parts

The sums for each part are as follows: - Part (a): 12 - Part (b): 16636 - Part (c): 35

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Summation Techniques
In mathematics, summation techniques are key skills that help to determine the sum of a sequence of numbers. Summation, denoted by the symbol \( \Sigma \), allows us to add together terms that follow a specific pattern or sequence. This is extremely useful in both algebra and calculus. One common technique is calculating each term of a sequence individually, then adding them all together as done in the problems above.
When faced with an expression like \( x_{r} = r(r-1)(2r-5) \), it’s essential to recognize patterns or simplify the expression for easier calculation. For computational efficiency, especially with larger ranges, understanding arithmetic series or geometric series formulations can streamline the summation process.
Summation can also be handled using different properties such as:
  • Linearity of summation: The sum of constants times functions can be separately summed and then multiplied.
  • Summation interchange: Allows rearranging nested sums, often seen in complex expressions.
  • Splitting sums: Large sums can be broken into smaller, more manageable pieces.
Using these techniques effectively simplifies calculations dramatically, particularly when applying them to problems in coursework or professional settings.
Discrete Mathematics
Discrete Mathematics is the study of mathematical structures that are fundamentally discrete rather than continuous. In calculus of finite sums, discrete mathematics is essential because it deals directly with summing sequences and series that are not continuous. This connects the work through counting theory, graph theory, and logic.
For example, the task of calculating \( \sum_{r=0}^{4} x_{r} \) where \( x_{r} \) follows a discrete function demonstrates how discrete mathematics helps organize and manipulate finite sums and measure changes over a defined range.
The applications of discrete sums are vast:
  • They are used in algorithms for counting operations in computing.
  • They play a significant role in understanding arithmetic and geometric sequences.
  • They contribute to cryptography and network security by calculating the finite operations involved.
By mastering finite sums in discrete mathematics, students arm themselves with mathematical tools that have value across diverse technical fields.
Mathematical Series
Mathematical series involve adding up the elements of a sequence to achieve a single total. This concept is particularly useful when dealing with sums over a given range, such as \( \sum_{r=1}^{5} x_{r} \). Series can be finite or infinite, but in calculus of finite sums, we focus primarily on finite series.
There are different types of series such as arithmetic series where each term increases by a constant, or geometric series where each term is multiplied by a constant factor. In problems like the ones given, each term is calculated separately based on the rule provided, and summed to produce a total.
Understanding the nature of the series provides insight into the pattern and behavior of sums:
  • Arithmetic series: In an arithmetic series, like \( a, a+d, a+2d, \ldots \), the sum can be found using the formula \( S_n = \frac{n}{2} (2a + (n-1)d) \).
  • Geometric series: These follow \( ar^0, ar^1, ar^2, \ldots \), and the sum is \( S_n = a \frac{(r^n - 1)}{r-1} \) for \( r eq 1 \).
Interpreting the series correctly allows simplification of complex problems, making solutions clearer and more accessible.

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