/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Evaluate the expression \(2 x_{n... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the expression \(2 x_{n+2}-7 x_{n+1}+3 x_{n}\) when \(x_{n}\) is defined for all \(n \geqslant 0\) by (a) \(x_{n}=3^{n}\) (b) \(x_{n}=2^{n}\) (c) \(x_{n}=2^{-n}\) (d) \(x_{n}=3(-2)^{n}\) Which of (a) to (d) are solutions of the following recurrence relation? $$ 2 x_{n+2}-7 x_{n+1}+3 x_{n}=0 $$

Short Answer

Expert verified
Sequence (a) and (d) satisfy the recurrence relation.

Step by step solution

01

Substitute sequence in (a)

Given \( x_n = 3^n \), calculate \( x_{n+1} = 3^{n+1} \) and \( x_{n+2} = 3^{n+2} \). Substitute these into the expression: \[ 2(3^{n+2}) - 7(3^{n+1}) + 3(3^n). \]Simplify the expression:\[ 2 \cdot 9 \cdot 3^n - 7 \cdot 3 \cdot 3^n + 3 \cdot 3^n = 18 \cdot 3^n - 21 \cdot 3^n + 3 \cdot 3^n. \]Combine terms:\[ (18 - 21 + 3) \cdot 3^n = 0 \cdot 3^n = 0. \]Thus, (a) satisfies the recurrence relation.
02

Substitute sequence in (b)

Given \( x_n = 2^n \), calculate \( x_{n+1} = 2^{n+1} \) and \( x_{n+2} = 2^{n+2} \). Substitute these into the expression: \[ 2(2^{n+2}) - 7(2^{n+1}) + 3(2^n). \]Simplify the expression:\[ 2 \cdot 4 \cdot 2^n - 7 \cdot 2 \cdot 2^n + 3 \cdot 2^n = 8 \cdot 2^n - 14 \cdot 2^n + 3 \cdot 2^n. \]Combine terms:\[ (8 - 14 + 3) \cdot 2^n = -3 \cdot 2^n. \]Since the expression does not equal zero, (b) does not satisfy the recurrence relation.
03

Substitute sequence in (c)

Given \( x_n = 2^{-n} \), calculate \( x_{n+1} = 2^{-(n+1)} \) and \( x_{n+2} = 2^{-(n+2)} \). Substitute into the expression: \[ 2(2^{-(n+2)}) - 7(2^{-(n+1)}) + 3(2^{-n}). \]Simplify:\[ 2 \cdot 2^{-n} \cdot 2^{-2} - 7 \cdot 2^{-n} \cdot 2^{-1} + 3 \cdot 2^{-n} = 2^{-n-1} - \ \frac{7}{2} \cdot 2^{-n} + 3 \cdot 2^{-n}. \]Combine terms:\[ 2^{-n} \left( \frac{1}{2} - \frac{7}{2} + 3 \right) = 2^{-n} \left( -\frac{3}{2} \right) eq 0. \]The expression does not equal zero, so (c) does not satisfy the recurrence relation.
04

Substitute sequence in (d)

Given \( x_n = 3(-2)^n \), compute \( x_{n+1} = 3(-2)^{n+1} = 3(-2)(-2)^n \) and \( x_{n+2} = 3(-2)^{n+2} = 3(-2)^2(-2)^n \). Substitute:\[ 2(3(-2)^{n+2}) - 7(3(-2)^{n+1}) + 3(3(-2)^n). \]Simplify:\[ 2 \cdot 3 \cdot 4 \cdot (-2)^n - 7 \cdot 3 \cdot (-2) \cdot (-2)^n + 3 \cdot 3 \cdot (-2)^n \]\[ = 24 (-2)^n - 42 (-2)^n + 9 (-2)^n. \]Combine:\[ (-2)^n (24 - 42 + 9) = (-2)^n \cdot (-9) = 0. \]Thus, (d) also satisfies the recurrence relation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence Evaluation
In mathematics, a sequence is an ordered list of numbers that follow a particular rule. When evaluating a sequence, you analyze these numbers using the rule to find patterns or predict future values. Understanding sequence evaluation is crucial as it helps in identifying the behavior of complex functions in mathematics and computer science.
In the given exercise, you are required to evaluate sequences like:\[ x_n = 3^n, 2^n, 2^{-n}, \text{ and } 3(-2)^n. \]
You substitute these into the expression \(2 x_{n+2} - 7 x_{n+1} + 3 x_n\). For each sequence option given, such as \(x_n = 3^n\), you calculate subsequent terms \(x_{n+1} = 3^{n+1}\) and \(x_{n+2} = 3^{n+2}\), and plug them into the expression. This step illustrates sequence evaluation by simplification and substitution. Using basic arithmetic rules, you process the expressions to see if they resolve to zero, as required by the recurrence relation\( 2 x_{n+2} - 7 x_{n+1} + 3 x_n = 0 \), which defines the valid sequences.
Homogeneous Equations
A homogeneous recurrence relation is a type of recurrence relation where each term is a linear combination of earlier terms, without a constant term added. The relation we have, \( 2 x_{n+2} - 7 x_{n+1} + 3 x_n = 0 \), is considered homogeneous since the right side equals zero.
This indicates that all terms are dependent on each other, and hence, if you find a solution sequence, it shouldn’t require adding any independent constants. Solving involves manipulating terms so that they balance out to maintain the zero on the right.
Homogeneous equations are pivotal because solutions are derived strictly based on previous terms alone, providing a systematic way to approach these specific types of problems. As shown in the exercise, solutions like \( x_n = 3^n \) satisfy the relation due to their inherent property of cancelling each term, fulfilling the equation's demand for homogeneity.
Difference Equations
Difference equations express relationships between the terms in a sequence by showing how terms differ from one another. In recurrence relations, they are crucial as they describe how a sequence progresses.
The given recurrence relation \( 2 x_{n+2} - 7 x_{n+1} + 3 x_n = 0 \) is a second-order linear difference equation because it relates terms at positions \( n, n+1, \text{ and } n+2 \). This type of equation helps us form sequences where each term depends on the prior two terms.
Understanding difference equations allows you to work through the steps of the exercise, deciding which of the sequences like \( x_n = 2^n \) satisfies the equation by checking if substituting terms results in a consistent relationship that resolves to zero. They provide the framework for how sequences transform over time based on their mathematical dependency defined in the equation. Recognizing these patterns is essential for solving recurrence relations efficiently.

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Most popular questions from this chapter

Newton's recurrence formula for determining the root of a certain equation is $$ x_{n+1}=\frac{x_{n}^{2}-1}{2 x_{n}-3} $$ Taking \(x_{0}=3\) as your initial approximation, obtain the root correct to \(4 \mathrm{sf}\). By setting \(x_{n+1}=x_{n}=\alpha\) show that the fixed points of the iteration are given by the equation \(\alpha^{2}-3 \alpha+1=0\)

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A detergent manufacturer wishes to forecast their future sales. Their market research department assesses that their 'Number One' brand has \(20 \%\) of the potential market at present. They also estimate that \(15 \%\) of those who bought 'Number One' in a given month will buy a different detergent in the following month and that \(35 \%\) of those who bought a rival brand will buy 'Number One' in the next month. Show that their share \(P_{n} \%\) of the market in the \(n\)th month satisfies the recurrence relation $$ P_{n+1}=35+0.5 P_{n}, \quad \text { with } P_{0}=20 $$ Find the values of \(P_{n}\) for \(n=1,2,3\) and 4 and illustrate them on an appropriate diagram.

By considering the sum $$ \sum_{k=1}^{n}\left[(k+1)^{4}-k^{4}\right] $$ show that $$ \sum_{k=1}^{n} k^{3}=\left[\frac{1}{2} n(n+1)\right]^{2} $$

Let \(x\) be a constant such that \(|x|<1\). Find the solution of $$ T_{n+2}-2 x T_{n+1}+T_{n}=0, \quad T_{0}=1, \quad T_{1}=x $$ Find \(T_{2}, T_{3}\) and \(T_{4}\) also directly by recursion and deduce that \(\cos \left(2 \cos ^{-1} x\right)=2 x^{2}-1\) and express \(\cos \left(3 \cos ^{-1} x\right)\) and \(\cos \left(4 \cos ^{-1} x\right)\) as polynomials in \(x\).

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