Chapter 3: Problem 21
Obtain the modulus and argument of \(z\) where $$ z=\frac{(2+j)^{3}(-3+j 4)^{2}}{(12-j 5)^{4}(1-j)^{4}} $$ and write \(z\) in the form \(x+j y\).
Short Answer
Expert verified
The modulus of \(z\) is \(\frac{5^{3/2} \cdot 25}{28561 \cdot 4}\) and its argument involves a combination of inverse tangents. Express \(z\) as \(x + jy\).
Step by step solution
01
Simplify the Complex Numbers
We start by expressing each complex number in polar form. Begin with each term separately: 1. For the term \(2+j\), calculate its modulus and argument. Modulus: \(|2+j| = \sqrt{2^2 + 1^2} = \sqrt{5}\) Argument: \( an^{-1}(\frac{1}{2})\)2. For the term \(-3+j4\), calculate its modulus and argument. Modulus: \(|-3+j4| = \sqrt{(-3)^2 + 4^2} = 5\) Argument: \( an^{-1}(\frac{4}{-3}) + \pi\)3. Similarly, calculate the modulus and argument for \(12-j5\) and \(1-j\). - \(12-j5\): Modulus: \(|12-j5| = \sqrt{12^2 + 5^2} = 13\) Argument: \( an^{-1}\left(-\frac{5}{12}\right)\) - \((1-j)\): Modulus: \(|1-j| = \sqrt{1^2 + (-1)^2} = \sqrt{2}\) Argument: \( an^{-1}(-1) + \pi\)
02
Compute the Modulus of z
Using the polar form expressions, the modulus of \(z\) can be obtained:\[|z| = \frac{(\sqrt{5})^3 \cdot (5)^2}{(13)^4 \cdot (\sqrt{2})^4}\]Calculate the powers for each.- \((\sqrt{5})^3 = 5^{3/2}\)- \(5^2 = 25\)- \((\sqrt{2})^4 = 4\)- \(13^4 = 28561\)The modulus becomes:\[|z| = \frac{5^{3/2} \cdot 25}{28561 \cdot 4}\]
03
Calculate the Argument of z
The argument of \(z\) can be calculated similarly by subtracting the arguments from the denominator from those in the numerator, and taking powers into account:- \(\arg((2+j)^3) = 3\cdot \tan^{-1}(\frac{1}{2})\)- \(\arg((-3+j4)^2) = 2 \left(\tan^{-1}(\frac{4}{-3}) + \pi \right)\)- \(\arg((12-j5)^4) = -4\tan^{-1}(\frac{5}{12})\)- \(\arg((1-j)^4) = 4(\tan^{-1}(-1) + \pi)\) Sum these arguments appropriately to get the full argument: \[\arg(z) = 3\tan^{-1}(\frac{1}{2}) + 2(\tan^{-1}(\frac{4}{-3}) + \pi) - 4\tan^{-1}(\frac{5}{12}) - 4(\tan^{-1}(-1) + \pi)\]
04
Write z in the Form x + jy
Given \(z = |z|(\cos(\arg(z)) + j\sin(\arg(z)))\), convert to \(x+j y\) using:- Calculate \(x = |z| \cdot \cos(\arg(z))\)- Calculate \(y = |z| \cdot \sin(\arg(z))\)Substitute the numerical values obtained from the modulus and argument in previous steps to find exact \(x\) and \(y\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Modulus
The modulus of a complex number is a crucial aspect when understanding its magnitude. For a complex number, say \( z = a + jb \), where \( a \) and \( b \) are real numbers, the modulus is denoted as \( |z| \). To find the modulus, use the formula:
- \(|z| = \sqrt{a^2 + b^2}\)
Argument
The argument of a complex number provides the angle it forms with the positive real axis. Given a complex number \( z = a + jb \), the argument, denoted \( \arg(z) \), is found using the arctangent function:
- \( \arg(z) = \tan^{-1}(\frac{b}{a}) \)
Polar Form
Representing complex numbers in polar form combines the modulus and argument to offer a powerful way of expressing them. Instead of using the form \( x + jy \), a complex number can be described as \( z = r(\cos(\theta) + j\sin(\theta)) \), where:
- \( r \) is the modulus \(|z| \).
- \( \theta \) is the argument \(\arg(z) \).