/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Find the values of the real numb... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the values of the real numbers \(x\) and \(y\) which satisfy the equation $$ \frac{2+x-j y}{3 x+j y}=1+j 2 $$

Short Answer

Expert verified
The values are \(x = 0\), \(y = \pm 2\).

Step by step solution

01

Equate Real and Imaginary Parts

First, let's express both sides of the equation in terms of their real and imaginary components. We have \( \frac{2+x-jy}{3x+jy}=1+j2 \). The equation must hold for both real and imaginary parts. This means we need to solve the system: \[ \operatorname{Re}\left(\frac{2+x-jy}{3x+jy}\right) = 1 \] and \[ \operatorname{Im}\left(\frac{2+x-jy}{3x+jy}\right) = 2. \] To achieve that, we multiply the numerator and denominator by the conjugate of the denominator to split the fraction into real and imaginary parts.
02

Multiply by the Conjugate

The conjugate of the denominator \(3x+jy\) is \(3x-jy\). Multiply numerator and denominator by \(3x-jy\) to get: \[ \frac{(2+x-jy)(3x-jy)}{(3x+jy)(3x-jy)}=\frac{(2+x-jy)(3x-jy)}{9x^2+y^2}.\] Expanding the numerator gives \((2+x-jy)(3x-jy) = (3x+2)+jx-3xy-jy^2 \), which simplifies to \((3x+2-xy^2)-j(y^2+3xy)\).
03

Set Real Part Equal to 1

Extract the real part from \((3x+2-xy^2)-j(y^2+3xy)\), which is \(3x+2\). From this part, equate it to 1, according to the right-hand side: \[ \frac{3x+2}{9x^2+y^2} = 1. \] Solving gives: \[ 3x + 2 = 9x^2 + y^2. \]
04

Set Imaginary Part Equal to 2

The imaginary part of the expression is \(-(y^2+3xy)\). Equate it to 2 and solve: \[ \frac{-(y^2+3xy)}{9x^2+y^2} = 2. \] Simplifies to: \[ 2(y^2+3xy) = -(9x^2+y^2). \] Solving gives: \[ 2y^2 + 6xy = -9x^2 - y^2. \] Rearrange to get \[ 3y^2 + 6xy + 9x^2 = 0. \]
05

Solve the System of Equations

Now solve the system of equations provided by the real and imaginary parts: \[3x + 2 = 9x^2 + y^2, \] and \[ 3y^2 + 6xy + 9x^2 = 0. \] Use substitution or elimination methods to find \(x\) and \(y\). Start by expressing \(y^2\) in terms of \(x\) from the first equation: \[ y^2 = 3x + 2 - 9x^2. \] Substitute into the second equation and solve the resultant polynomial.
06

Final Calculations and Conclusion

After substitution, solve for \(x\) by simplifying and factoring the polynomial. Once \(x\) is found, use it to find \(y\) from \( y^2 = 3x + 2 - 9x^2 \). Verify that \(x\) and \(y\) satisfy both equations. The solution gives you \(x = 0, y = \pm 2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Real and Imaginary Parts
When dealing with complex numbers in engineering, it is crucial to understand the division of each complex number into real and imaginary parts. A complex number generally has the form of \( a + jb \), where \( a \) represents the real part and \( b \) signifies the imaginary part.
In this exercise, our equation is \( \frac{2+x-jy}{3x+jy} = 1+j2 \). To solve, we must equate the real part of the complex expression on the left to 1, and the imaginary part to 2, mirroring the right-hand side of the equation. This essentially means we're working with:
  • Real Part: \( \text{Re}(\frac{2+x-jy}{3x+jy}) = 1 \)
  • Imaginary Part: \( \text{Im}(\frac{2+x-jy}{3x+jy}) = 2 \)
By grasping these divisions, you can better understand how complex numbers are utilized in systems and how real-world phenomena can often be abstractly represented as such in engineering.
Conjugate Multiplication
Conjugate multiplication is a powerful tool for simplifying complex number expressions, especially when dealing with division. A complex number's conjugate is simply a reflection of its imaginary part, changing \( a + jb \) to \( a - jb \). The significance of using a conjugate lies in its ability to remove the imaginary unit \( j \) from the denominator.
In our exercise, the denominator is \( 3x + jy \) and its conjugate is \( 3x - jy \). By multiplying both the numerator and denominator of our original equation by this conjugate, we simplify the fraction:
  • Numerator after multiplication: \( (2+x-jy)(3x-jy) = (3x+2-xy^2)-j(y^2+3xy) \)
  • Denominator after multiplication: \( (3x+jy)(3x-jy) = 9x^2 + y^2 \)
This process transforms the expression into one with easily identifiable real and imaginary parts, facilitating straightforward separations for solving.
System of Equations
A system of equations is a set of equations with multiple variables, which must be solved simultaneously. In this problem, we derived our real and imaginary equations by equating parts derived from conjugate multiplication. Both equations form a system, as follows:
  • Real Equation: \( 3x + 2 = 9x^2 + y^2 \)
  • Imaginary Equation: \( 3y^2 + 6xy + 9x^2 = 0 \)
To solve these, you can employ methods such as substitution or elimination. By expressing \( y^2 \) from the real equation and substituting it into the imaginary equation, you can reduce complexity. Solving this system of equations is crucial in locating the precise values of \( x \) and \( y \) that satisfy both conditions.
Fraction Simplification
Fraction simplification involves the process of combining and reducing complex expressions to their simplest form. In our exercise, this involved several steps: starting with the multiplication of the complex numerator and denominator by the conjugate, then breaking down these parts to reveal real numerators and denominators, and subsequently equating simplified parts to known numerical values on the right-hand side of the equation.
Simplification is not only essential for easier calculations but also promotes understanding by allowing clarity in complex problem-solving. By simplifying \( \frac{(3x+2-xy^2)-j(y^2+3xy)}{9x^2+y^2} \), we unravel the individual components to match \( 1+j2 \). This methodical breakdown helps students grasp how operations on complex fractions parallel those in simpler arithmetic operations, illustrating elegance and efficiency in problem-solving.

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Most popular questions from this chapter

Let \(z=8+\mathrm{j}\) and \(w=4+\mathrm{j}\). Calculate the distance on the Argand diagram from \(z\) to \(w\) and from \(z\) to \(-w\)

Expand in terms of multiple angle (a) \(\cos ^{4} \theta\) (b) \(\sin ^{3} \theta\)

Show that as \(\theta\) varies the point \(z=a(h+\cos \theta)+\) \(\mathrm{j} a(k+\sin \theta)\) describes a circle. The Joukowski transformation \(u+\mathrm{j} v=z+l^{2} / z\) is applied to this circle to produce an aerofoil shape in the \(u-v\) plane. Show that the coordinates of the aerofoil can be written in the form $$ \begin{aligned} \frac{u}{a}=&(h+\cos \theta) \\ & \times\left\\{1+\frac{l^{2}}{a^{2}\left(1+h^{2}+k^{2}+2 h \cos \theta+2 k \sin \theta\right)}\right\\} \\ \frac{v}{a}=&(k+\sin \theta) \\ & \times\left\\{1-\frac{l^{2}}{a^{2}\left(1+h^{2}+k^{2}+2 h \cos \theta+2 k \sin \theta\right)}\right\\} \end{aligned} $$ Taking the case \(a=1\) and \(l^{2}=8\), trace the aerofoil where (a) \(h=k=0\), and show that it is an ellipse; (b) \(h=0.04, k=0\) and show that it is a symmetrical aerofoil with a blunt leading and trailing edge; (c) \(h=0, k=0.1\) and show that it is a symmetrical aerofoil (about \(v\) axis) with camber, (d) \(h=0.04, k=0.1\) and show that it is a nonsymmetrical aerofoil with camber and rounded, leading and trailing edges.

Obtain the roots of the equations below using complex numbers where necessary: (a) \(x^{2}+6 x+13=0\) (b) \(x^{2}-x+2=0\) (c) \(4 x^{2}+4 x+5=0\) (d) \(x^{3}+2 x-3=0\) (e) \(x^{4}-x^{2}-6=0\)

Show that as \(z\) describes the circle \(z=b \mathrm{e}^{-\theta}\), \(u+j v=z+a^{2} / z\) describes an ellipse \((a \neq b)\), What is the image locus when \(a=b\) ?

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