Chapter 2: Problem 97
Sketch the graphs of the functions (a) \(y=\lfloor x\rfloor-\left\lfloor x-\frac{1}{2}\right\rfloor\) (b) \(y=\left|\mathrm{FRACPT}(x)-\frac{1}{2}\right|\)
Short Answer
Expert verified
For (a), the graph consists of segments at y=1 for integers and y=0 otherwise. For (b), the graph is a periodic V-wave with peaks of 0.5 halfway between integers.
Step by step solution
01
Understand the Function Part (a)
The function in part (a) is defined as \( y = \lfloor x \rfloor - \left\lfloor x - \frac{1}{2} \right\rfloor \). The operator \( \lfloor x \rfloor \) represents the greatest integer less than or equal to \( x \). The function \( \left\lfloor x - \frac{1}{2} \right\rfloor \) therefore represents the greatest integer less than or equal to \( x - 0.5 \).
02
Graph Analysis for Part (a)
For any real number \( x \), there are two possibilities: \( x \) is an integer or non-integer. - If \( x \) is an integer, then \( \lfloor x \rfloor = x \) and \( \left\lfloor x - 0.5 \right\rfloor = x - 1 \), so \( y = x - (x - 1) = 1 \).- If \( x \) is not an integer, \( \lfloor x \rfloor = k \) (where \( k \) is an integer such that \( k \leq x < k+1 \)) and \( \left\lfloor x - 0.5 \right\rfloor = k \), so \( y = k - k = 0 \).Hence, the graph consists of horizontal lines with \( y = 1 \) at each integer, and \( y = 0 \) elsewhere.
03
Understand the Function Part (b)
The function in part (b) is defined as \( y = \left| \text{FRACPT}(x) - \frac{1}{2} \right| \). The function \( \text{FRACPT}(x) \) refers to the fractional part of \( x \), i.e., \( x - \lfloor x \rfloor \). This means the expression within the absolute value is the fractional part of \( x \) minus a half.
04
Graph Analysis for Part (b)
The function \( y = \left| \text{FRACPT}(x) - \frac{1}{2} \right| \) can be simplified as follows:- For a number \( x \), the fractional part \( \text{FRACPT}(x) = x - \lfloor x \rfloor \). This value ranges between 0 and 1.- Subtracting \( \frac{1}{2} \) and taking absolute value ensures the result is always positive and reflects symmetrically about \( x = n + 0.5 \) for any integer \( n \). This forms a V-shape with vertices at multiples of \( \frac{1}{2} \).- Each piece linearly increases from 0 to \( \frac{1}{2} \) between consecutive integers' halves, thus creating a wave shape with a peak value of \( \frac{1}{2} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Floor Function
The floor function, denoted as \( \lfloor x \rfloor \), is a mathematical function that maps a real number to the greatest integer less than or equal to that number. This function is integral to understanding the first part of our function \( y = \lfloor x \rfloor - \left\lfloor x - \frac{1}{2} \right\rfloor \). For example:
You will see steps in the graph where it climbs vertically to 1 at integer values and stays at 0 between them.
- \( \lfloor 3.7 \rfloor = 3 \)
- \( \lfloor -2.1 \rfloor = -3 \)
- \( \lfloor 4 \rfloor = 4 \) (since 4 is already an integer)
You will see steps in the graph where it climbs vertically to 1 at integer values and stays at 0 between them.
Fractional Part Function
The fractional part function \( \text{FRACPT}(x) \) gives the non-integer part of a real number, defined as \( x - \lfloor x \rfloor \). This presents a value between 0 and just under 1 for any real number \( x \). Understanding this is key to part (b) of the given exercise with the function \( y = \left| \text{FRACPT}(x) - \frac{1}{2} \right| \). For example:
- \( \text{FRACPT}(3.7) = 3.7 - 3 = 0.7 \)
- \( \text{FRACPT}(-2.3) = -2.3 + 3 = 0.7 \)
- \( \text{FRACPT}(4) = 4 - 4 = 0 \)
Graph Analysis
Graph analysis involves interpreting and visualizing how these functions behave over different domains. For the function \( y = \lfloor x \rfloor - \left\lfloor x - \frac{1}{2} \right\rfloor \), the graph is made of step-like features. This happens because the outcome depends on whether \( x \) is an integer:
In contrast, for \( y = \left| \text{FRACPT}(x) - \frac{1}{2} \right| \), the graph forms a continuous sequence of V-shapes. Each V is symmetric relative to lines \( x = n + 0.5 \). The curve touches 0 at integer values and reaches a maximum \( \frac{1}{2} \) at midpoints, establishing a wave-like appearance that smoothly rises and falls.
- At integers, \( y = 1 \)
- In between integers, \( y = 0 \)
In contrast, for \( y = \left| \text{FRACPT}(x) - \frac{1}{2} \right| \), the graph forms a continuous sequence of V-shapes. Each V is symmetric relative to lines \( x = n + 0.5 \). The curve touches 0 at integer values and reaches a maximum \( \frac{1}{2} \) at midpoints, establishing a wave-like appearance that smoothly rises and falls.
Absolute Value Function
The absolute value function, denoted as \( |x| \), represents the distance of a number from zero on the number line. It ensures that the result is always non-negative. This function is important in part (b) for \( y = \left| \text{FRACPT}(x) - \frac{1}{2} \right| \). Here's why it matters:
- The function \( \text{FRACPT}(x) - \frac{1}{2} \) can be either positive or negative depending on \( x \).
- Taking the absolute value guarantees the result is positive, plotting a symmetrical V-shape between integer values.
- This symmetry results in a consistent pattern across the graph, centered on half-integers.