Chapter 24: Problem 8
One-Dimensional Massive Scalar Field A one-dimensional field theory with scalar potential \(\varphi(x, t)\) is characterized by the action $$ S=\frac{1}{2} \iint d t d x\left[\frac{1}{c^{2}}\left(\frac{\partial \varphi}{\partial t}\right)^{2}-\left(\frac{\partial \varphi}{\partial x}\right)^{2}-m^{2} \varphi^{2}\right] . $$ Find the equation of motion for \(\varphi(x, t)\) by both Lagrangian and Hamiltonian methods.
Short Answer
Step by step solution
Derive the Euler-Lagrange Equation
Compute Derivatives for the Lagrangian Method
Substitute into Euler-Lagrange Equation
Derive Hamiltonian Density
Hamilton's Equation of Motion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Euler-Lagrange Equation
- \( \frac{\partial}{\partial t}\left(\frac{\partial \mathcal{L}}{\partial \dot{\varphi}}\right) + \frac{\partial}{\partial x}\left(\frac{\partial \mathcal{L}}{\partial \varphi'}\right) - \frac{\partial \mathcal{L}}{\partial \varphi} = 0 \)
Lagrangian Method
- \( \mathcal{L} = \frac{1}{2c^{2}}\left(\frac{\partial \varphi}{\partial t}\right)^{2} - \frac{1}{2}\left(\frac{\partial \varphi}{\partial x}\right)^{2} - \frac{1}{2}m^{2} \varphi^{2} \)
- \( \frac{\partial \mathcal{L}}{\partial \dot{\varphi}} = \frac{1}{c^{2}}\dot{\varphi} \)
- \( \frac{\partial \mathcal{L}}{\partial \varphi'} = - \varphi' \)
- \( \frac{\partial \mathcal{L}}{\partial \varphi} = -m^{2}\varphi \)
Hamiltonian Method
- \( \Pi = \frac{\partial \mathcal{L}}{\partial \dot{\varphi}} = \frac{1}{c^{2}}\dot{\varphi} \)
- \( \mathcal{H} = \dot{\varphi}\Pi - \mathcal{L} \)
- This results in \( \mathcal{H} = \frac{1}{2}\left[ \frac{1}{c^{2}}\dot{\varphi}^{2} + \left(\frac{\partial \varphi}{\partial x}\right)^{2} + m^{2} \varphi^{2} \right] \)
- \( \dot{\varphi} = \frac{\partial \mathcal{H}}{\partial \Pi} \)
- \( \dot{\Pi} = -\frac{\partial \mathcal{H}}{\partial \varphi} \)
Scalar Field Theory
- \( \frac{1}{c^{2}}\frac{\partial^{2} \varphi}{\partial t^{2}} - \frac{\partial^{2} \varphi}{\partial x^{2}} + m^{2}\varphi = 0 \)