/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A coding rate of \(2 / 3\) is re... [FREE SOLUTION] | 91Ó°ÊÓ

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A coding rate of \(2 / 3\) is required to manage transmission errors in a 54 Mbit/s data link. That is, the information bit rate is \(54 \mathrm{Mbit} / \mathrm{s} .\) What is the total bit rate required (including data and coding bits)?

Short Answer

Expert verified
81 Mbit/s

Step by step solution

01

Identify the coding rate

Recognize that the coding rate is given as \(\frac{2}{3}\). This means that for every 3 bits transmitted, 2 are information bits, and 1 is an error-correcting code (redundant) bit.
02

Determine the information bit rate

The information bit rate is provided as 54 Mbit/s, meaning 54 million bits of actual data are transmitted every second.
03

Calculate the total bit rate

Use the coding rate to find the total bit rate. Given a coding rate of \(\frac{2}{3}\), for every 2 bits of data, 3 bits are transmitted. The relationship can be expressed as \(\text{Total Bit Rate} = \text{Information Bit Rate} \times \frac{3}{2}\).
04

Apply the calculation

Substitute the information bit rate value to get: \(\text{Total Bit Rate} = 54 \times \frac{3}{2} = 81 \text{ Mbit/s}\). This gives the total bit rate, including both data and coding bits.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

error-correcting code
Error-correcting codes are techniques used in digital communication systems to detect and correct errors that occur during data transmission. The primary goal is to ensure that the information received is accurate, even if some bits are altered during transit.

Error-correcting codes add extra bits to the original data, known as redundant bits. These bits help identify and fix any errors that may occur. Common types of error-correcting codes include Reed-Solomon, Hamming codes, and Convolutional codes.

For instance, in a code with a rate of \(\frac{2}{3}\), out of every three bits transmitted, two are actual data bits (information bits), and one is a redundant bit (error-correcting bit). This redundancy enables the system to detect and correct possible errors, thereby enhancing the reliability of data transmission.
information bit rate
The information bit rate refers to the number of actual data bits transmitted per second in a communication system. It is the 'useful' data rate minus any redundant bits that might be added to help with error correction.

In the given exercise, the information bit rate is 54 Mbit/s. This means that 54 million bits of data per second are being transmitted without considering the redundant bits added for error correction.

Understanding the information bit rate is crucial for evaluating the efficiency and capacity of communication links. It's an important metric in digital communication systems and helps design networks to meet required data throughput specifications.
total bit rate calculation
The total bit rate is the combined rate of both information bits and redundant bits. It's a measure of the total number of bits that need to be transmitted to ensure reliable communication.

To calculate the total bit rate, you need to understand the coding rate. The coding rate is the ratio of information bits to the total number of bits transmitted. In this exercise, the coding rate is \(\frac{2}{3}\), meaning that for every 2 information bits, 3 total bits are sent.

The formula for total bit rate is: \(\text{Total Bit Rate} = \text{Information Bit Rate} \times \frac{3}{2}\). By applying the given information bit rate of 54 Mbit/s: \(\text{Total Bit Rate} = 54 \times \frac{3}{2} = 81 \text{ Mbit/s}\).

This result shows that to transmit 54 million information bits per second reliably, we must actually send 81 million bits per second due to the added error-correcting bits.

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Most popular questions from this chapter

An OFDM system with 12 data subcarriers, uses a coding rate of \(3 / 4,\) and each subcarrier uses \(16-\) QAM modulation (with a modulation efficiency of \(2.7 \mathrm{bit} / \mathrm{s} / \mathrm{Hz})\) with a bandwidth of \(250 \mathrm{kHz}\). What is the maximum data rate supported?

Short answer questions on modulation and spectral efficiency. (a) What is the PMEPR of a phase modulated signal? (b) In five lines explain your understanding of spectral efficiency as it relates to bits per hertz. That is, how can you have a spectral efficiency of \(n\) bit/s/Hz where \(n\) is more than 1? [Note that sometimes this is expressed as bit/s/Hz as well as bit/s/Hz.] (c) What is the modulation efficiency of a QPSK-modulated signal? Ignore the impact of the number of cells in a cluster.

A 10 GHz bistatic radar has a minimum detectable received signal power of \(-150 \mathrm{dBm},\) an antenna gain of \(26 \mathrm{~dB},\) and a required range of \(100 \mathrm{~km}\). What is the transmitted pulse power in dBm needed to detect a (a) conventional fighter aircraft having an RCS of \(5 \mathrm{~m}^{2}\) ? (b) a stealth aircraft with an RCS of \(0.05 \mathrm{~m}^{2}\) ?

A direct sequence spread spectrum code of \(10 \mathrm{Mbit} / \mathrm{s}\) is used to code a \(4 \mathrm{kbit} / \mathrm{s}\) data steam that is modulated using \(3 \pi / 8\) -8PSK modulation to produce an RF signal at \(1900 \mathrm{MHz}\). The modulation efficiency of \(3 \pi / 8\) -8PSK modulation is \(2.7 \mathrm{bit} / \mathrm{s} / \mathrm{Hz}\) (a) What is the bandwidth of the RF signal? (b) What processing gain can be achieved in the receiver?

Consider an OFDM system with 12 subcarriers carrying data and which uses 8-PSK modulation of each subcarrier and a coding rate of \(3 / 4\). Pilot subcarriers they can be ignored in this problem so consider all 12 subcarriers. (a) How many symbols are there for each subcarrier? That is, how many points are there in the constellation diagram for one subcarrier? (b) How many coded bits (code + data) are there on each subcarrier? That is, how many bits per symbol are there for each subcarrier? (c) Considering all of the data subcarriers, how many coded bits are there per OFDM symbol? [Hint, there are 12 subcarriers, so for each OFDM symbol there will be 12 subcarrier symbols.] (d) Considering the coding rate, determine the number of data bits per OFDM symbol. That is, ignore coding bits.

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