Chapter 4: Problem 5
An n-channel MOSFET is biased in the saturation region at a constant \(V_{G S}\). (a) The drain current is \(I_{D}=0.250 \mathrm{~mA}\) at \(V_{D S}=1.5 \mathrm{~V}\) and \(I_{D}=0.258 \mathrm{~mA}\) at \(V_{D S}=3.3 \mathrm{~V}\). Determine the value of \(\lambda\) and \(r_{o}\). (b) Using the results of part (a), determine \(I_{D}\) at \(V_{D S}=5 \mathrm{~V}\).
Short Answer
Step by step solution
Understand the Problem and Concept
Use Drain Current Equations
Solving for \(\lambda\)
Calculate \(I_{D0}\)
Determine Output Resistance \(r_{o}\)
Calculate New \(I_{D}\) at \(V_{DS} = 5 \text{ V}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
drain current
- \(I_{D0}\) is the drain current at zero drain-source voltage \(V_{DS}\).
- \(\lambda\) symbolizes the channel-length modulation parameter, indicating how the drain current increases with higher \(V_{DS}\) even in saturation.
channel-length modulation
- \(\lambda\) introduces a linear dependency of \(I_D\) on \(V_{DS}\). Larger \(\lambda\) values suggest significant changes with \(V_{DS}\), thus representing stronger channel-length modulation.
output resistance
- \(\lambda\) is the channel-length modulation parameter.
- \(I_D\) is the drain current in amperes.
n-channel MOSFET
- Quick response time due to lighter, faster electrons.
- Greater current-carrying capabilities, ideal for digital circuits as well as analog applications.