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Two inverting amplifiers are connected in cascade to provide an overall voltage gain of 500 . The gain of the first amplifier is \(-10\) and the gain of the second amplifier is \(-50\). The unity-gain bandwidth of each op-amp is \(1 \mathrm{MHz}\). (a) What is the bandwidth of the overall amplifier system? (b) Redesign the system to achieve the maximum bandwidth. What is the maximum bandwidth?

Short Answer

Expert verified
(a) The bandwidth is 20 kHz. (b) Maximum bandwidth is 44.73 kHz.

Step by step solution

01

Understanding Inverting Amplifier Gain

The gain of an amplifier is given by the product of the gains of individual amplifiers in cascade. For two amplifiers, the overall gain \( A_{total} = A_1 \times A_2 \). Here, the gain of the first amplifier \( A_1 = -10 \) and the gain of the second amplifier \( A_2 = -50 \). Thus, \( A_{total} = -10 \times -50 = 500 \).
02

Calculate Bandwidth of the Current System

For inverting amplifiers, the gain-bandwidth product (GBP) is constant and equals the unity-gain bandwidth. Both amplifiers have a unity-gain bandwidth of \( 1 \text{ MHz} \). The bandwidth of an individual stage with a specific gain can be calculated using \( \ ext{Bandwidth} = \frac{\text{GBP}}{|A|} \). Therefore, the bandwidth for the first amplifier is \( \frac{1 \text{ MHz}}{10} = 100 \text{ kHz} \), and for the second, \( \frac{1 \text{ MHz}}{50} = 20 \text{ kHz} \). The overall bandwidth is the bandwidth of the slowest stage, which is \( 20 \text{ kHz} \).
03

Redesign Strategy for Maximum Bandwidth

To redesign the system for maximum bandwidth, aim to equalize the gain distribution to have the same gain-bandwidth product for each stage. Let the gain of each amplifier be \( A = \sqrt{500} \approx -22.36 \).
04

Calculate New Bandwidth with Balanced Gain

With each amplifier's gain \( A = -22.36 \), the bandwidth for each stage is \( \text{Bandwidth} = \frac{1 \text{ MHz}}{22.36} \approx 44.73 \text{ kHz} \). Since this bandwidth is shared by both equal-gain stages, the overall bandwidth is \( 44.73 \text{ kHz} \).
05

Conclusion

Originally, the system's bandwidth was \( 20 \text{ kHz} \). By balancing the gain across the stages, the maximum achievable bandwidth is approximately \( 44.73 \text{ kHz} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverting Amplifier Gain
Inverting amplifiers are fundamental elements in analog electronics. They take an input signal and produce an output signal that is inverted and amplified. Understanding the concept of gain is critical when working with these circuits.

The gain of an inverting amplifier is defined as the ratio of the output voltage to the input voltage. It’s given by the formula: \[ A = -\frac{R_f}{R_{in}} \]where \( R_f \) is the resistance of the feedback loop, and \( R_{in} \) is the input resistance. The negative sign indicates that the output is inverted compared to the input.

In a cascaded system, where multiple amplifiers are in series, the total gain is the product of the individual gains. So, for two amplifiers with gains \( A_1 \) and \( A_2 \), the overall gain \( A_{total} \) is calculated by \( A_{total} = A_1 \times A_2 \). When both amplifiers have individual gains of \(-10\) and \(-50\), their combined effect results in a significant total gain of \(500\). Remember, the negative signs signify phase inversion at each stage.
Gain-Bandwidth Product
The gain-bandwidth product (GBP) is a critical parameter of operational amplifiers. It reflects how the gain of an amplifier affects its bandwidth and is a measure of the performance limits of a particular op-amp.

In essence, the GBP states that an amplifier's bandwidth decreases as the gain increases, and vice versa, to maintain a constant product. Mathematically, it’s represented as:\[ GBP = |A| \times BW \]where \( |A| \) is the magnitude of gain and \( BW \) is the bandwidth. Every operational amplifier has a characteristic unity-gain bandwidth, often where its gain equals one.

For the amplifiers discussed in the original exercise, both have a unity-gain bandwidth of \( 1 \text{ MHz} \). As such, for each amplifier, the GBP remains constant even when individual gains change. This fundamental relationship dictates that understanding GBP is key to modifying amplifier designs to meet specific requirements.
Amplifier Bandwidth
Bandwidth in the context of amplifiers refers to the range of frequencies over which the amplifier can operate effectively. It is particularly influenced by the amplifier’s gain and unity-gain bandwidth.

When calculating bandwidth for a specific gain value, use the formula:\[ \text{Bandwidth} = \frac{1 \text{ MHz}}{|A|} \]This equation shows the inversely proportional relationship between gain and bandwidth due to the constant gain-bandwidth product.

In the exercise, the first amplifier with a gain of \(-10\) achieves a bandwidth of \(100 \text{ kHz}\), and the second with a gain of \(-50\) achieves a bandwidth of \(20 \text{ kHz}\). The overall bandwidth of a system with cascaded amplifiers is determined by the slowest amplifier stage. Hence, the system's bandwidth becomes \(20 \text{ kHz}\), set by the second amplifier.
Amplifier Gain Distribution
Distributing gain effectively among amplifier stages can optimize bandwidth, especially in systems requiring specific performance criteria. Central to this concept is redesigning the amplifier stages for balanced gain distribution.

By spreading out gain equally across multiple stages, we can increase the bandwidth of the entire system. This is because each stage contributes a smaller gain maintaining the coherence across gain-bandwidth product constraints.

In the provided exercise, achieving uniform gain for maximum bandwidth was exemplified. Redesign each amplifier to have a gain of approximately \(-22.36\), which is achieved by using the square root of the overall desired gain \( \sqrt{500} \). This arrangement produces an overall bandwidth of \(44.73 \text{ kHz}\), essentially doubling the initial performance. Such strategies illustrate the benefits of balancing gain to enhance system bandwidth.

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Most popular questions from this chapter

An inverting amplifier is fabricated using \(0.1\) percent precision resistors. The nominal resistor values are \(R_{2}=210 \mathrm{k} \Omega\) and \(R_{1}=21.0 \mathrm{k} \Omega\). (a) If the op-amp is ideal, what is the range in the magnitude of voltage gain as a result of the variation in resistor value? (b) Repeat part (a) if the open-loop gain of the op-amp is \(A_{O L}=10^{4}\).

An op-amp is connected in an inverting amplifier configuration with a voltage gain of \(-80\) and is biased at \(\pm 5 \mathrm{~V}\). If the output saturates at \(\pm 4.5 \mathrm{~V}\), what is the maximum rms value of an input sine wave that can be applied without causing distortion in the output signal?

A noninverting amplifier uses 5 percent precision resistors with nominal values of \(R_{2}=150 \mathrm{k} \Omega\) and \(R_{1}=15 \mathrm{k} \Omega\). The op-amp has a low-frequency gain of \(A_{o}=3 \times 10^{4}\) and has a unity- gain bandwidth of \(f_{T}=1.2 \mathrm{MHz}\). (a) What is the nominal low-frequency closed-loop gain and bandwidth? (b) Determine the range in low-frequency closed-loop gain and bandwidth.

(a) An inverting amplifier with resistors \(R_{1}=5.6 \mathrm{k} \Omega\) and \(R_{2}=120 \mathrm{k} \Omega\) is fabricated using an op-amp with an open-loop gain of \(10^{5}\). What is the percent difference between the actual gain and the ideal gain? (b) Repeat part (a) if \(R_{1}\) is changed to \(R_{1}=8.2 \mathrm{k} \Omega\).

Three inverting amplifiers, each with \(R_{2}=150 \mathrm{k} \Omega\) and \(R_{1}=15 \mathrm{k} \Omega\), are connected in cascade. Each op-amp has a low- frequency gain of \(A_{o}=5 \times 10^{4}\) and a unity-gain bandwidth of \(f_{T}=1.5 \mathrm{MHz}\). (a) Determine the low-frequency closed-loop gain and the \(-3 \mathrm{~dB}\) frequency of each stage.

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