Chapter 7: Problem 13
An element in plane stress (see figure) is subjected to stresses \(\sigma_{x}, \sigma_{y},\) and \(\tau_{x y}\) (a) Determine the principal stresses and show them on a sketch of a properly oriented element. (b) Determine the maximum shear stresses and associated normal stresses and show them on a sketch of a properly oriented element. $$\sigma_{x}=100 \mathrm{MPa}, \sigma_{y}=7.5 \mathrm{MPa}, \tau_{x y}=13 \mathrm{MPa}$$
Short Answer
Step by step solution
Calculate Average Normal Stress
Calculate the Radius of the Mohr's Circle
Determine Principal Stresses
Calculate Maximum Shear Stress
Sketch Properly Oriented Elements
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mohr's Circle
To construct Mohr's Circle, follow these steps:
- Calculate the average normal stress \( \sigma_{avg} = \frac{\sigma_{x} + \sigma_{y}}{2} \).
- Determine the radius of the circle through \( R = \sqrt{\left( \frac{\sigma_{x} - \sigma_{y}}{2} \right)^2 + \tau_{xy}^2} \).
- The principal stresses can then be found where the circle intercepts the horizontal axis. These corresponding points reveal the principal stresses' values.
Shear Stress
The maximum shear stress, \(\tau_{max}\), represents the highest value of shear stress that the material element can sustain. In Mohr's Circle, \(\tau_{max}\) is represented by the radius of the circle.
- Maximum shear stress occurs at a 45-degree angle from the principal stress direction.
- This stress is crucial in failure analysis, as materials often fail due to shear rather than direct loading.
Plane Stress
This assumption is particularly common in:
- Thin plates subjected to in-plane loading
- Sheet metal components
- Structural elements like membranes or thin shells
Stress Transformation
Transformation equations help predict how stress components change as the orientation of the plane changes:
- Normal stress on an inclined plane can be calculated by \[ \sigma = \sigma_{avg} + \frac{\sigma_{x} - \sigma_{y}}{2} \cos(2\theta) + \tau_{xy} \sin(2\theta) \]
- Shear stress on an inclined plane is given by \[ \tau = -\frac{\sigma_{x} - \sigma_{y}}{2} \sin(2\theta) + \tau_{xy} \cos(2\theta) \]