Two cables, each having a length \(L\) of approximately \(40 \mathrm{m},\) support
a loaded container of weight \(W\) (see figure). The cables, which have
effective cross-sectional area \(A=48.0 \mathrm{mm}^{2}\) and effective modulus
of elasticity \(E=160 \mathrm{GPa},\) are identical except that one cable is
longer than the other when they are hanging scparately and unloaded. The
difference in lengths is \(d=100 \mathrm{mm}\). The cables are made of steel
having an elastoplastic stressstrain diagram with \(\sigma_{Y}=500\) MPa. Assume
that the weight \(W\) is initially zero and is slowly increased by the addition
of material to the container.
(a) Determine the weight \(W_{Y}\) that first produces yielding of the shorter
cable. Also, determine the corresponding elongation \(\delta_{Y}\) of the
shorter cable.
(b) Determine the weight \(W_{P}\) that produces yielding of both cables. Also,
determine the elongation \(\delta_{P}\) of the shorter cable when the weight \(W\)
just reaches the value \(W_{P}\)
(c) Construct a load-displacement diagram showing the weight \(W\) as ordinate
and the elongation \(\delta\) of the shorter cable as abscissa. (Hint: The load
displacement diagram is not a single straight line in the region \(0 \leq W
\leq W_{Y^{\prime}}\)