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The value \(V\) in the bent tube is initially kept closed. Two soap bubbles \(A\) (smaller) and \(B\) (larger) are formed at the two open ends of the tube. \(V\) is now opened and air can flow freely between the bubbles. (1) There will be change in the size of the bubbles (2) The bubbles will become of equal size (3) \(A\) will become smaller and \(B\) will become larger (4) The sizes of \(A\) and \(B\) will be interchanged

Short Answer

Expert verified
3. Bubble \( A \) will become smaller and bubble \( B \) will become larger.

Step by step solution

01

Understanding Pressure in Soap Bubbles

The internal pressure of a soap bubble is given by the formula \( P = P_{atm} + \frac{4T}{r} \), where \( P_{atm} \) is the atmospheric pressure, \( T \) is the surface tension, and \( r \) is the radius of the bubble. Larger bubbles have less pressure since \( r \) is greater.
02

Determining Air Flow Direction

When the valve \( V \) is opened, air will flow from the bubble with higher internal pressure to the bubble with lower internal pressure. Since the smaller bubble \( A \) has the higher pressure, air will flow from \( A \) to \( B \).
03

Predicting Changes in Bubble Sizes

As air flows from the smaller bubble \( A \) to the larger bubble \( B \), bubble \( A \) will lose air and get smaller, and bubble \( B \) will gain air and get larger.
04

Conclusion on Bubble Behavior

Comparing all options given: 1. There will be a change in size due to air flow.2. They won't become equal in size; \( A \) will lose air to \( B \).3. \( A \) becomes smaller and \( B \) becomes larger, which correctly describes the air flow effect.4. Sizes won't interchange; the larger bubble will get even larger.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Surface Tension
Soap bubbles are a classic example demonstrating the balance of forces acting at the interface of two fluids. One of these forces is surface tension. Surface tension is a property that causes the surface layer of a liquid to behave like a stretched elastic sheet. In the context of a soap bubble, surface tension works against internal pressure to keep the bubble intact.
Surface tension is dependent on the liquid used and its temperature. For soap solutions, the surface tension can be quite different from that of pure water.
Bubbles formed using a soap solution have a surface tension denoted by the symbol \( T \). This tension tries to minimize the surface area of the bubble, leading to their spherical shape, which offers the smallest surface area for a given volume.
Internal Pressure
The internal pressure of a soap bubble is a crucial factor in determining its stability and size. This internal pressure can be expressed by the formula \( P = P_{atm} + \frac{4T}{r} \). Here:
  • \( P \) is the internal pressure.
  • \( P_{atm} \) is the atmospheric pressure outside the bubble.
  • \( T \) is the surface tension of the soap solution.
  • \( r \) is the radius of the bubble.
For smaller bubbles, the radius \( r \) is smaller, leading to a higher internal pressure. Conversely, larger bubbles exhibit lower internal pressure. This difference in pressure between various sizes of bubbles plays a significant role in how they interact with each other.
Air Flow Direction
When two bubbles are connected, as in the scenario with the bent tube, air will flow from one bubble to the other based on the difference in their internal pressures. The fundamental rule is that air flows from a region of higher pressure to a region of lower pressure. In our exercise, the smaller bubble \( A \), having a higher internal pressure due to its smaller radius, forces the air into the larger bubble \( B \) which has a lower internal pressure.
This flow is guided by the principle of reaching equilibrium. However, in this case, equilibrium might not lead to bubbles of equal size since the dynamics of pressure and surface tension balance the act differently for different sizes.
Change in Bubble Size
The direction of air flow resulting from the differences in internal pressures directly influences a change in bubble sizes. As air flows from the smaller, higher-pressure bubble \( A \) to the larger, lower-pressure bubble \( B \), bubble \( A \) decreases in size while bubble \( B \) increases in size. This results in bubble \( A \) becoming smaller and losing air, while bubble \( B \) expands and gains air.
In our exercise, this flow doesn't result in bubbles becoming equal in size but continues until the pressures balance sufficiently, leading to a dynamic yet stable configuration where the bubbles maintain respective sizes until physical constraints or external factors interrupt the balance.

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Most popular questions from this chapter

A space \(2.5 \mathrm{~cm}\) wide between two large plane surfaces is filled with oil. Force required to drag a very thin plate of area \(0.5 \mathrm{~m}^{2}\) just midway the surfaces at a speed of \(0.5 \mathrm{~ms}^{-1}\) is \(1 \mathrm{~N}\). Find the coefficient of viscosity of oil (in \(\times 10^{-3} \mathrm{~kg}-\mathrm{sm}^{-2}\) ).

A hollow sphere has a small hole in it. On lowering the sphere in a tank of water, it is observed that water enters into the hollow sphere at a depth of \(40 \mathrm{~cm}\) below the surface. Surface tension of water is \(7 \times 10^{-2} \mathrm{~N} / \mathrm{m}\). The diameter of the hole is (1) \(\frac{1}{28} \mathrm{~mm}\) (2) \(\frac{1}{21} \mathrm{~mm}\) (3) \(\frac{1}{14} \mathrm{~mm}\) (4) \(\frac{1}{7} \mathrm{~mm}\)

A glass rod of radius \(r_{1}\) is inserted symmetrically into a vertical capillary tube of radius \(r_{2}\) such that their lower ends are at the same level. The arrangement is now dipped in water. The height to which water will rise into the tube will be ( \(\sigma=\) surface tension of water, \(\rho=\) density of water) (1) \(\frac{2 \sigma}{\left(r_{2}-r_{1}\right) \rho g}\) (2) \(\frac{\sigma}{\left(r_{2}-r_{1}\right) \rho g}\) (3) \(\frac{2 \sigma}{\left(r_{2}+r_{1}\right) \rho g}\) (4) \(\frac{2 \sigma}{\left(r_{2}^{2}+r_{1}^{2}\right) \rho g}\)

When a capillary tube is dipped in a liquid, the liquid rises to a height \(h\) in the tube. The free liquid surface inside the tube is hemispherical in shape. The tube is now pushed down so that the height of the tube outside the liquid is less than \(h\). Then (1) the liquid will come out of the tube like in a small fountain (2) the liquid will ooze out of the tube slowly (3) the liquid will fill the tube but not come out of its upper end (4) the free liquid surface inside the tube will not be hemispherical

Match the following: \begin{tabular}{|l|l|} \hline \multicolumn{1}{|c|} { Column I } & \multicolumn{1}{c|} { Column II } \\\ \hline 1. Splitting of bigger drop into small droplets & a. Temperature increases \\ \hline 11. Formation of bigger drop from small droplets & b. Temperature decreases \\ \hline III. Spraying of liquid & c. Surface energy increases \\ \hline & d. Surface energy decrease \\ \hline \end{tabular}

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