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The density of water at the surface of ocean is \(\rho\). If the bulk modulus of water is \(B\), then the density of ocean water at depth, when the pressure is \(\alpha p_{0}\) and \(p_{0}\) is the atmospheric pressure, is (1) \(\frac{\rho B}{B-(\alpha-1) p_{0}}\) (2) \(\frac{\rho B}{B+(\alpha-1) p_{0}}\) (3) \(\frac{\rho B}{B-\alpha_{0}}\) (4) \(\frac{\rho B}{B+\alpha p_{0}}\)

Short Answer

Expert verified
Option (1): \(\frac{\rho B}{B-(\alpha-1)p_{0}}\) is correct.

Step by step solution

01

Understanding the Problem

We need to find the density of ocean water at a certain depth where pressure is different due to the depth. We are given the initial density at the surface, initial pressure at the surface, and the bulk modulus of water.
02

Identify Relevant Equations

The bulk modulus, \(B\), is defined as \(B = -\frac{dP}{dV/V}\), where \(dP\) is the change in pressure and \(dV/V\) is the relative change in volume. We want a formula involving density, so we use the relation \(\rho_2 = \rho_1 \left(1+\frac{\Delta P}{B}\right)\) for small changes, where \(\Delta P = P - p_0\).
03

Calculate the Change in Pressure

Given, \(P = \alpha p_{0}\) and \(p_{0}\) is the atmospheric pressure, the change in pressure \(\Delta P = \alpha p_{0} - p_{0} = (\alpha-1)p_{0}\).
04

Substitute Values into Density Equation

Substitute \(\Delta P\) into the density relation: \(\rho_{new} = \rho \left(1 + \frac{(\alpha-1)p_{0}}{B}\right)\). Simplify the expression to align with the options given.
05

Simplify the Expression

Rewrite \(\rho_{new}\) as follows: \(\rho_{new} = \rho \cdot \frac{B + (\alpha-1)p_{0}}{B}\). Inverting this fraction, you get \(\rho_{new} = \frac{\rho B}{B - (\alpha-1)p_{0}}\).
06

Identify the Correct Option

Compare the expression derived, \(\frac{\rho B}{B-(\alpha-1)p_{0}}\), with the given options. Option 1 matches perfectly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bulk Modulus
The Bulk Modulus is a fundamental concept in fluid mechanics, especially when it comes to understanding how fluids behave under pressure. It is a measure of a substance's resistance to uniform compression. The bulk modulus, denoted as "B," is defined by the equation:\[B = -\frac{dP}{dV/V}\]Here, \(dP\) represents the change in pressure and \(dV/V\) represents the relative change in volume. This relationship helps in understanding how much a fluid compresses or expands under pressure changes.
  • Higher bulk modulus: Indicates that the fluid is less compressible.
  • Lower bulk modulus: Suggests the fluid is more compressible.
By plugging in changes in pressure into the formula, you can predict how the density of a fluid like water will change when it experiences different pressures. This property is crucial in many applications, from underwater construction to the study of natural water bodies.
Density of Water
Density is an important property that describes how much mass of a substance is contained in a given volume. For water, density is commonly expressed as grams per cubic centimeter (g/cm³) and plays a vital role in fluid mechanics. The density of water is affected by temperature and pressure:
  • Temperature: As the temperature increases, the density of water typically decreases. This is because warmer water expands, causing the volume to increase while maintaining the same mass.
  • Pressure: An increase in pressure typically increases density, as found in deeper parts of the ocean where the water is more compressible.
In the context of the exercise, where the pressure at a depth is higher than the atmospheric pressure, the density of ocean water changes accordingly. By understanding the relationship between pressure and density, scientists can predict how fluids behave under various environmental conditions.
Pressure at Depth
The concept of pressure at depth is crucial for understanding how pressures change within a fluid, such as water, with depth. Pressure in a fluid increases with depth due to the weight of the fluid above it. The pressure at a certain depth in a fluid can be calculated with the equation:\[P = P_0 + \rho gh\]Here:
  • \(P\) is the pressure at depth.
  • \(P_0\) is the atmospheric pressure.
  • \(\rho\) is the density of the fluid.
  • \(g\) is the acceleration due to gravity.
  • \(h\) is the depth of the fluid.
When dealing with the depths of the ocean, the increase in pressure affects the water's density, as explored in the original exercise. An understanding of pressure changes is essential not just for oceanography, but also for safety in engineering projects and in the design of submersible devices.

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Most popular questions from this chapter

Two parallel and opposite forces, each of magnitude \(4000 \mathrm{~N}\), are applied tangentially to the upper and lower faces of a cubical metal block \(25 \mathrm{~cm}\) on a side. Find the displacement of the upper surface relative to the lower surface (in \(\times 10^{-5} \mathrm{~cm}\) ). The shear modulus for the metal is \(80 \mathrm{GPa}\).

Two wire \(A\) and \(B\) have equal lengths and are made of the same material, but the diameter of \(A\) is twice that of wire \(B\). Then, for a given load (1) the extension of \(B\) will be four times that of \(A\) (2) the extension of \(A\) and \(B\) will be equal (3) the strain in \(B\) is four times that in \(A\) (4) the strains in \(A\) and \(B\) will be equal

Two wires of the same length and same material but radil in the ratio of \(1: 2\) are stretched by unequal forces to produce equal elongation. The ratio of the two forces is (1) \(1: 1\) (2) \(1: 2\) (3) \(1: 3\) (4) \(1: 4\)

A uniform elastic rod of cross-section area \(A\), natural length \(L\) and Young's modulus \(Y\) is placed on a smooth horizontal surface. Now two horizontal forces (of magnitude \(F\) and \(3 F\) ) directed along the length of rod and in opposite direction act at two of its ends as shown. After the rod has acquired steady state, the extension of the rod will be (1) \(\frac{2 F}{Y A} L\) (2) \(\frac{4 F}{Y A} L\) (3) \(\frac{F}{Y A} L\) (4) \(\frac{3 F}{2 Y A} L\)

An amusement park ride consists of airplane shaped cars attached to steel rods. Each rod has a length of \(20.0 \mathrm{~m}\) and a cross-sectional area of \(8.00 \mathrm{~cm}^{2}\) Young's modulus for steel is \(2 \times 10^{11} \mathrm{~N} /\) \(\mathrm{m}^{2}\). (Assume that each car plus two people seated in it has a total weight of \(2000 \mathrm{~N} .)\) How much is the rod stretched when the ride is at rest? (1) \(0.5 \mathrm{~mm}\) (2) \(1.0 \mathrm{~mm}\) (3) \(0.25 \mathrm{~mm}\) (4) \(2.5 \mathrm{~mm}\)

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