/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 A small but heavy block of mass ... [FREE SOLUTION] | 91Ó°ÊÓ

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A small but heavy block of mass \(10 \mathrm{~kg}\) is attached to a wire \(0.3 \mathrm{~m}\) long. Its breaking stress is \(4.8 \times 10^{7} \mathrm{~N} / \mathrm{m}^{2}\). The area of the cross section of the wire is \(10^{-6} \mathrm{~m}^{2}\). The maximum angular velocity with which the block can be rotated in the horizontal circle is (1) \(4 \mathrm{rad} / \mathrm{s}\) (2) \(8 \mathrm{rad} / \mathrm{s}\) (3) \(10 \mathrm{rad} / \mathrm{s}\) (4) \(32 \mathrm{rad} / \mathrm{s}\)

Short Answer

Expert verified
The maximum angular velocity is \( 4 \, \text{rad/s} \) (option 1).

Step by step solution

01

Calculate the maximum tension in the wire

The breaking force of the wire can be calculated using the formula for stress, which is stress equals force divided by area. Thus, the breaking force \( F \) can be calculated as: \[ F = ext{Stress} \times ext{Area} = (4.8 \times 10^7 \, \text{N/m}^2) \times (10^{-6} \, \text{m}^2) = 48 \, \text{N} \] So, the maximum tension the wire can handle is 48 N.
02

Use centripetal force equation

For rotational motion in a horizontal circle, the tension in the wire provides the necessary centripetal force. Thus, we have: \[ T = m r \omega^2 \] where \( T \) is the tension, \( m = 10 \, \text{kg} \) is the mass, \( r = 0.3 \, \text{m} \) is the radius (length of the wire), and \( \omega \) is the angular velocity.
03

Solve for angular velocity \( \omega \)

We know \( T = 48 \, \text{N} \) from Step 1. Substitute \( T = 48 \, \text{N} \), \( m = 10 \, \text{kg} \), and \( r = 0.3 \, \text{m} \) into the equation \( T = m r \omega^2 \): \[ 48 = 10 \times 0.3 \times \omega^2 \] \[ 48 = 3 \omega^2 \] Solve for \( \omega^2 \): \[ \omega^2 = \frac{48}{3} = 16 \] \[ \omega = \sqrt{16} = 4 \, \text{rad/s} \]
04

Identify the correct choice

The calculated angular velocity \( \omega \) is \( 4 \, \text{rad/s} \), which corresponds to option (1).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a measure of how quickly an object rotates or revolves around a particular point. It's a fundamental concept in physics, especially in topics involving rotational dynamics. For our exercise, angular velocity is represented by the symbol \( \omega \), and it is measured in radians per second (rad/s). This exercise involves calculating the angular velocity of a block swinging in a horizontal circle at the end of a wire. When dealing with circular motion, angular velocity describes how fast the angle in radians changes with time, helping us understand the rotation of objects. To determine the maximum angular velocity, we consider factors such as the tension in the wire and the force required to maintain the circular motion, known as the centripetal force. The centripetal force can be calculated using the formula \( T = m r \omega^2 \), where \( T \) is the tension in the wire, \( m \) is the mass of the block, \( r \) is the radius (equivalent to the length of the wire), and \( \omega \) is the angular velocity. Understanding angular velocity not only helps in solving problems involving rotation but also provides insights into how spinning phenomena occur in nature.
Tension in Wire
Tension in a wire arises when it's subjected to forces attempting to stretch it. In our exercise, understanding the tension in the wire is crucial as its maximum limit defines the maximum speed at which the block can rotate. Let's break it down:
  • Tension is represented by the force \( T \) and is measured in newtons (N).
  • The tension essentially acts as the centripetal force required to keep the block moving in a circular path.
  • As described by the centripetal force equation: \( T = m r \omega^2 \). Here, \( m \) is the mass, \( r \) is the length of the wire, and \( \omega \) is the angular velocity.
  • The maximum tension that the wire can handle is 48 N, as determined by the wire's breaking stress and its cross-sectional area.
Tension plays an essential role in structures and devices where cables, wires, or ropes are used to transmit force.
Breaking Stress
Breaking stress is a critical parameter in material science. It's the stress level at which a material will fracture or break. Understanding this concept is important in scenarios like our exercise, where it determines how much force a wire can withstand before failure. Here's what you need to know:
  • Breaking stress, also known as ultimate tensile stress, is expressed in N/m² (pascals).
  • It is calculated using the formula \( \text{Stress} = \frac{\text{Force}}{\text{Area}} \). In our exercise, the breaking stress of the wire is \( 4.8 \times 10^7 \, \text{N/m}^2 \).
  • The cross-sectional area of the wire is given as \( 10^{-6} \, \text{m}^2 \), which allows the calculation of the maximum force (tension) the wire can support before it breaks.
In this exercise, the maximum tension the wire can handle before reaching breaking stress is 48 N. This information is vital for determining the maximum angular velocity of the block since any force exceeding this tension would break the wire, causing the block to lose its circular path and potentially damaging the setup.

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Most popular questions from this chapter

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