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An iceberg is floating partially immersed in sea water. The density of sea water is \(1.03 \mathrm{~g} \mathrm{~cm}^{-3}\) and that of ice is \(0.92 \mathrm{~g} \mathrm{~cm}^{-3}\). The approximate percentage of total volume of iceberg above the level of sea water is (1) 8 (2) 11 (3) 34 (4) 89

Short Answer

Expert verified
The approximate percentage of the iceberg's volume above sea level is 11%, option (2).

Step by step solution

01

Understand the principle of buoyancy

The principle of buoyancy states that a floating object displaces a weight of fluid equal to its own weight. For the iceberg to float in water, the weight of the displaced sea water is equal to the weight of the iceberg.
02

Set up the equation using densities

Let the total volume of the iceberg be \( V \), and the volume submerged be \( V_s \). The density of the sea water is \( \rho_{water} = 1.03 \, \text{g/cm}^3 \) and the density of ice is \( \rho_{ice} = 0.92 \, \text{g/cm}^3 \). The mass of the iceberg is \( \rho_{ice} \times V \) and the mass of the displaced sea water is \( \rho_{water} \times V_s \). From the principle of buoyancy, these must be equal: \[ \rho_{ice} \times V = \rho_{water} \times V_s \]
03

Solve for the submerged volume

Rearrange the equation from Step 2 to solve for \( V_s \): \[ V_s = \frac{\rho_{ice}}{\rho_{water}} \times V \] Substitute the given values: \[ V_s = \frac{0.92}{1.03} \times V \approx 0.8932 \times V \] This shows that approximately 89.32% of the iceberg's volume is submerged.
04

Find the percentage above the sea level

The percentage of the iceberg volume above sea level is the remainder of the volume not submerged: \[ V_{above} = V - V_s \] As a percentage of the total volume: \[ \text{Percentage above} = \left(1 - \frac{V_s}{V} \right) \times 100 \] Using the value from Step 3: \[ \text{Percentage above} = \left(1 - 0.8932 \right) \times 100 \approx 10.68\% \]
05

Select the closest option

The calculated percentage of volume above sea level is approximately 10.68%, which is closest to option (2), 11%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a fundamental concept when it comes to understanding buoyancy and the behavior of floating objects like icebergs. Density is defined as the mass of an object divided by its volume, expressed mathematically as \( \rho = \frac{m}{V} \), where \( \rho \) is the density, \( m \) is the mass, and \( V \) is the volume.
In the context of floating icebergs, density plays a crucial role in determining how much of the iceberg remains above the waterline. An iceberg floats because its density is less than that of sea water. The densities given in the problem are \( 1.03 \, \text{g/cm}^3 \) for the sea water and \( 0.92 \, \text{g/cm}^3 \) for the ice.
  • Since the ice has a lower density compared to the sea water, it displaces water until the buoyant force equals its weight.
  • The relatively lower density of ice explains why a portion of the iceberg stays above the water.
Understanding density helps in analyzing how different substances interact when placed in fluids, which is foundational for predicting whether objects will float or sink.
Volume Displacement
Volume displacement is a key principle in understanding how objects behave when placed in a fluid. According to Archimedes' principle, an object immersed in a fluid experiences a buoyant force equal to the weight of the fluid displaced by the object. This principle is essential in calculating how much of the iceberg is submerged versus how much is above water.
In step 3 of the solution, we've derived that the submerged volume \( V_s \) is given by:\[ V_s = \frac{\rho_{ice}}{\rho_{water}} \times V \]This equation shows that the volume of sea water displaced (\( V_s \)) is proportional to the ratio of the densities of the ice and the seawater.
  • The iceberg displaces a volume of water equal to its own mass, ensuring equilibrium by the principle of buoyancy.
  • We find that about 89.32% of the iceberg's volume is underwater, which matches our expectation based on their densities.
Volume displacement not only explains floating but also assists in understanding how submarines and ships navigate by controlling their buoyancy.
Floating Objects
The behavior of floating objects like icebergs is a vivid demonstration of buoyancy and density principles in action. An object floats because the upward buoyant force is equal to the downward gravitational force (weight) acting upon it. This balance allows the object to remain partially submerged.
When it comes to icebergs, about 89% of their structure is beneath the surface, with roughly 11% visible above the water. This distribution occurs because the density of ice is lower than that of sea water.
  • The concept of floating relies on the differences in density between the object and the fluid it is in.
  • The percentage of the iceberg visible above water is calculated as the leftover part after subtracting the submerged percentage from 100%. As shown in step 4 of the solution, this amounts to about 10.68%, rounded to the closest estimate of 11%.
Understanding how floating objects interact with fluids provides critical insights into marine studies, construction of floating vessels, and even climate science observations related to icebergs.

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