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A cylindrical vessel contains a liquid of density \(\rho\) up to height \(h\). The liquid is closed by a piston of mass \(m\) and area of cross section \(A\). There is a small hole at the bottom of the vessel. The speed \(v\) with which the liquid comes out of the hole is (1) \(\sqrt{2 g h}\) (2) \(\sqrt{2\left(g h+\frac{m g}{\rho A}\right)}\) (3) \(\sqrt{2\left(g h+\frac{m g}{A}\right)}\) (4) \(\sqrt{2 g h+\frac{m g}{A}}\)

Short Answer

Expert verified
The answer is option (4): \(\sqrt{2 g h + \frac{m g}{A}}\).

Step by step solution

01

Understand the Problem

The problem involves a cylindrical vessel filled with a liquid which is held by a piston. The liquid is escaping from a hole at the bottom, and we need to find the speed of the liquid as it exits.
02

Apply Bernoulli's Principle

Bernoulli's equation relates the pressure, velocity, and height of a fluid in a streamline. At the piston level, the pressure is due to gravity and the piston mass, and at the hole, the pressure is atmospheric. We write Bernoulli's equation as:\[ P + \frac{1}{2}\rho v^2 + \rho g h = \text{constant} \]
03

Simplify Pressure Terms

The pressure at the piston is due to atmospheric pressure and the pressure from the mass of the piston:\[ P = P_0 + \frac{m g}{A} \]The pressure at the hole is just atmospheric pressure \(P_0\).
04

Equate pressures in Bernoulli's Equation

Substitute the pressure terms from step 3 into Bernoulli's equation and solve for velocity \(v\):\[ P_0 + \frac{m g}{A} + \rho g h = P_0 + \frac{1}{2}\rho v^2 \]\[ \frac{m g}{A} + \rho g h = \frac{1}{2}\rho v^2 \]
05

Solve for the velocity v

Rearrange to solve for \(v^2\):\[ v^2 = \frac{2}{\rho} \left( \frac{m g}{A} + \rho g h \right) \]Simplifying gives:\[ v^2 = 2 gh + \frac{2 m g}{A} \]Taking the square root:\[ v = \sqrt{2 gh + \frac{2 m g}{A}} \]
06

Compare with Given Options

The derived expression for \(v\) matches option (4): \(\sqrt{2 g h + \frac{m g}{A}}\), considering alignment in terms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli's Principle
Bernoulli's Principle is a fundamental concept in fluid dynamics that relates the pressure, velocity, and height of a fluid in motion. It is based on the conservation of energy within a fluid flow. When a fluid moves, its energy is distributed among pressure energy, kinetic energy (due to velocity), and potential energy (due to height). Bernoulli's equation is expressed as: \[ P + \frac{1}{2}\rho v^2 + \rho g h = \text{constant} \]- Here, \(P\) stands for pressure energy.- \(\frac{1}{2}\rho v^2\) represents kinetic energy.- \(\rho g h\) symbolizes potential energy.This principle is essential while analyzing fluids in closed systems like pipes or open systems like airflows. In our exercise, it helps calculate the velocity of the liquid as it exits a vessel. By applying Bernoulli’s Principle and considering the piston and atmospheric pressures, along with the potential energy difference, you can solve for the flow velocity.
Cylindrical Vessel
In fluid dynamics, a cylindrical vessel is a tube-like container that is crucial for experiments and solving problems involving fluid flow. It has a uniform cross-sectional area throughout its length, making calculations relatively straightforward.To evaluate fluid behavior in a cylindrical vessel:- Consider the height \(h\) of the liquid inside, which impacts potential energy.- Examine the cross-sectional area \(A\), which relates to the mass influence on the system.For the exercise at hand, the cylindrical design simplifies determining the pressures and forces acting on the piston and liquid. This uniformity aids in deriving the velocity at which liquid exits through the hole based on Bernoulli's equation.
Liquid Density
Liquid density, denoted as \(\rho\), is a key factor in fluid dynamics because it affects the weight of the liquid column and, consequently, the pressure at varying depths in a fluid. Density is often measured in units like kilograms per cubic meter (kg/m³).In the context of the exercise:- High density \(\rho\) implies more mass per unit volume, affecting the pressure exerted by the liquid.- The term \(\rho g h\) from Bernoulli’s equation considers the liquid density to express its potential energy contribution.By understanding how liquid density influences each component of Bernoulli’s equation, you get a clearer picture of how pressure and energy are distributed across a fluid flow.
Velocity of Liquid Flow
The velocity of liquid flow is the speed at which the liquid exits an aperture. This concept is critical in applications where fluid movement and dynamics are involved, like the draining of a container.Velocity is affected by multiple factors:- The gravitational pull \(g\) acting on the fluid.- The vertical height \(h\) that determines the potential energy available to the fluid.- Pressure terms derived from the weight applied by the piston and atmospheric influences.In this specific problem, understanding the velocity helps determine how quickly the fluid leaves the vessel. Applying the modified Bernoulli’s equation, which considers pressure differences due to the piston and liquid height, allows us to accurately calculate the exiting speed: \[ v = \sqrt{2gh + \frac{m g}{A}} \] This formula directly relates fluid velocity to the gravitational pull, potential energy from height, and additional pressure.

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Most popular questions from this chapter

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