/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 An open vessel containing liquid... [FREE SOLUTION] | 91Ó°ÊÓ

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An open vessel containing liquid is moving with constant acceleration \(a\) on a levelled horizontal surface. For this situation mark out the correct statement(s). (1) The maximum pressure is at the leftmost bottom corner. (2) Along a horizontal line within the liquid as we move from left to right the pressure decreases. (3) The pressure at all points on a line making an angle of \(\tan ^{-1}\left(\frac{a}{g}\right)\) with horizontal would be same. (4) Along a horizontal line within the liquid as we move from left to right, the pressure remains same.

Short Answer

Expert verified
Correct statements: (1), (2), and (3).

Step by step solution

01

Understand the Concept

This problem involves the effect of constant acceleration on the pressure distribution within a liquid. When the vessel accelerates, the liquid experiences a pseudo force in the opposite direction of the acceleration. This affects the pressure distribution within the liquid.
02

Determine Pressure Distribution

The pressure in the liquid increases with depth and varies with horizontal accelaration. It can be calculated using the modified hydrostatic pressure formula: \( P = P_0 + \rho(g+a)h \), where \( \rho \) is the density, \( g \) is the gravitational acceleration, \( a \) is the horizontal acceleration, and \( h \) is the depth. The factor \( g+a \) represents the effective gravity in the inclined direction.
03

Analyze Maximum Pressure

The maximum pressure occurs where the depth of the liquid is maximum along the direction opposing the acceleration. In this case, since the acceleration \( a \) is to the right, the liquid levels higher on the left side, making the leftmost bottom corner have the maximum pressure.
04

Evaluate Pressure Variation along Horizontal

When moving along a horizontal line from left to right, since the pressure increases in the direction of the pseudo force (rightward), it actually decreases as you move left to right along the horizontal line.
05

Assess Pressure on an Inclined Line

A line making an angle of \( \tan^{-1}\left(\frac{a}{g}\right)\) with the horizontal aligns with the direction of effective gravitational force (resultant of \( g \) and \( a \)). Thus, pressure remains constant along this line because it's perpendicular to the direction of the resultant gravitational force.
06

Conclude Horizontal Pressure Constancy

Contrary to option 4, due to the acceleration, the pressure does not remain the same along a horizontal line since it varies with the horizontal position due to the effect of the pseudo force.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure Distribution in Fluids
When a fluid is contained in a moving vessel, the distribution of pressure within the fluid is influenced not only by gravity but also by any acceleration of the vessel. This change can be intuitively understood by considering how the fluid "leans" in response to movement. Typically, pressure within a fluid increases with depth, meaning the deeper you go into the fluid, the higher the pressure. This is because of the weight of the fluid pressing downwards.

However, in an accelerating system, such as a vessel moving to the right, the pseudo force acts in the opposite direction, pushing the fluid to one side. As a result, the side where the fluid 'leans' against will experience higher pressure due to this combined effect of gravity and horizontal acceleration.
  • Pressure increases with depth due to fluid weight.
  • Acceleration causes pressure to increase on the side opposite the movement direction.
  • This creates a skewed pressure distribution across the fluid's volume.
Pseudo Force in Physics
Pseudo force is an important concept when analyzing non-inertial frames of reference—situations where objects are accelerating. Unlike real forces, which originate from physical interactions, pseudo forces arise because the observer is in a non-standard (accelerating) reference frame.

In a scenario where a vessel containing a fluid is accelerating horizontally, everything within that frame, including the fluid, feels as if a force acts in the opposite direction of the acceleration. This is the pseudo force, and it affects how pressure distributes throughout the fluid.
  • Pseudo forces appear in accelerating systems.
  • They act opposite to the direction of acceleration.
  • Though not a real force, it must be considered for accurate physical predictions.
Hydrostatic Pressure Equation
The hydrostatic pressure equation is vital for analyzing pressure at various points in a fluid at rest or moving at constant velocity. It is expressed as:
\[ P = P_0 + \rho gh \]

where \( P \) is the pressure at a certain depth \( h \), \( P_0 \) is the surface pressure, \( \rho \) is fluid density, and \( g \) is gravitational acceleration. However, when considering accelerating systems, the equation needs modification. By introducing acceleration \( a \), it changes to:
\[ P = P_0 + \rho (g + a)h \]

This effective gravity \( g + a \) combines both gravitational and pseudo forces, enabling analysis of pressure in such systems.
  • Standard equation: \( P = P_0 + \rho gh \).
  • Modified for acceleration: \( P = P_0 + \rho (g + a)h \).
  • Covers scenarios with additional pseudo forces.
Accelerated Fluid Dynamics
Accelerated fluid dynamics looks at how fluids react when subjected to acceleration. This field incorporates pseudo forces and varying pressure distributions, adding complexity to fluid behavior under acceleration. Such analysis is crucial for understanding both everyday systems, like a moving vessel of water, as well as more complex setups like industrial fluid conduits under dynamic loads.

When acceleration occurs, the fluid assumes a new equilibrium in pressure and distribution, aligning along an angle dictated by the ratio of acceleration to gravity. This angle can be calculated using:
\[ \theta = \tan^{-1}\left(\frac{a}{g}\right) \]
This trigonometric relationship shows where pressure evens out over an inclined line perpendicular to the effective gravitational force—a crucial insight for predicting fluid behavior in accelerating systems.
  • Balances real and pseudo forces.
  • Calculates angles of equilibrium with \( \theta = \tan^{-1}\left(\frac{a}{g}\right) \).
  • Essential for handling fluids in industrial and transportation contexts.

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Most popular questions from this chapter

For Problems 31-32 A U-tube of uniform cross section contains a liquid of density d. Diameter of the tube is \(D\). Height of liquid in the left arm and also in the right arm is \(h\) and length of horizontal portion of the tube and hence the horizontal column of liquid is \(L\). Consider the following situations. (i) The tube is given a uniform acceleration \(a\) towards left. (ii) The tube is mounted on a horizontal table that is made to rotate with a uniform angular speed \(\omega\) with one of the arms (left or right) on the axis of rotation. Take \(M\) as the total mass of the liquid and \(g\) as the acceleration due to gravity. Difference in height between the liquid columns in the vertical arms (left and right) in situation (i) will be (1) \(\sqrt{\frac{L a}{g}} \times h\) (2) \(\frac{L^{2} h^{2} d a}{M g}\) (3) \(\frac{L a}{g}\) (4) \(\frac{L a D}{g h}\)

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