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The change in the value of \(g\) at a height \(h\) above the surtact of earth is the same as at a depth \(d\) below the earth. Whet both \(d\) and \(h\) are much smaller than the radius of earth, then which one of the following is correct? (1) \(d=\frac{h}{2}\) (2) \(d=\frac{3 h}{2}\) (3) \(d=2 h\) (4) \(d=h\)

Short Answer

Expert verified
The correct answer is (1) \(d=\frac{h}{2}\).

Step by step solution

01

Understanding Gravity Change Above Earth

The change in gravitational acceleration at height h above the Earth's surface can be approximated by the formula g_h = g rac{R}{R+h} , where R is the radius of the Earth.
02

Understanding Gravity Change Below Earth

The change in gravitational acceleration at depth d below the Earth's surface is given by g_d = g rac{R-d}{R} under similar approximations.
03

Equating the Changes

Since the change in the value of g at height h is equal to the change at depth d , we can equate g rac{R}{R+h} = g rac{R-d}{R} .
04

Simplifying the Equation

Cancel out g from both sides, yielding rac{R}{R+h} = rac{R-d}{R} .
05

Solving for d

Cross-multiply to get R^2 = (R-d)(R+h) . Upon expanding and rearranging the terms, we have R^2 = R^2 + Rh - Rd - dh . Cancel out R^2 and simplify further to Rd + dh = Rh .
06

Rearranging and Finding d in Terms of h

Isolate d to express it in terms of h : d = rac{Rh - dh}{R} = rac{h(R)}{R + h} . Using the small h approximation, where Rh is much larger than dh , d simplifies to rac{h}{2} .

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravity at Height
When we consider the effect of gravity at a certain height above the Earth's surface, an interesting phenomenon occurs. As you move further from the surface, the gravitational force decreases. This happens because gravity depends on how far you are from the Earth's center.

The formula to calculate gravitational acceleration at a height \( h \) is given by:\[ g_h = g \cdot \frac{R}{R + h} \]Where:
  • \( g_h \) is the gravity at height \( h \)
  • \( g \) is the standard gravity at Earth's surface, approximately \( 9.81 \ \text{m/s}^2 \)
  • \( R \) is the radius of the Earth
As \( h \) increases, the denominator \( R + h \) also increases, leading to a smaller overall gravitational pull, \( g_h \). What's critical to understand is that this change is quite small for heights much less than the Earth's radius.
Gravity at Depth
Imagine you're descending below the Earth's surface, perhaps in a cave or a deep mine. Here, gravity behaves differently compared to being above ground. As you go deeper, part of the Earth's mass is above you and essentially becomes irrelevant in the gravitational force calculations, thus weakening the gravitational pull.

The gravitational acceleration at depth \( d \) can be calculated using the formula:\[ g_d = g \cdot \frac{R - d}{R} \]Where:
  • \( g_d \) is the gravity at depth \( d \)
  • \( R \) is the overall radius of the Earth
Here, as \( d \) increases, the term \( R - d \) decreases, indicating a reduction in gravitational force, \( g_d \). The result is that the gravitational force reduces as you move deeper, a concept crucial in fields such as geology and physics.
Radius of Earth
The radius of the Earth is a fundamental factor when it comes to gravitational calculations, whether at height or at depth.
On average, the Earth's radius is approximately 6,371 kilometers. This value is critical because both the equations for gravity at height and depth rely on it.

Understanding the radius helps in:
  • Calculating the gravitational force at various heights or depths accurately.
  • Setting a baseline to determine how changes in elevation or depth might affect gravity.
  • Providing perspective in engineering projects, satellite launches, and environmental studies.
The relationship between gravitational force changes and the Earth's radius underscores the immense size and scale of our planet, which influences many terrestrial and extraterrestrial physical phenomena.

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