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Two horizontal discs of different radii are free to rotate about their central vertical axes. One is given some angular velocity, the other is stationary. Their rims are now brought in contact. There is friction between the rims. Then (1) the force of friction between the rims will disappear when the discs rotate with equal angular speeds (2) the force of friction between the rims will disappear when they have equal linear velocities (3) the angular momentum of the system will be conserved (4) the rotational kinetic energy of the system will not be conserved

Short Answer

Expert verified
The force of friction disappears when rims have equal linear velocities, angular momentum is conserved, but not rotational kinetic energy.

Step by step solution

01

Understanding the Contact Force of Friction

When two rims come in contact with friction, the frictional force works to equalize their interacting velocities. Initially, the discs have different velocities because one is moving, and one is stationary. The frictional force acts to make their velocities equal where they interact at their rims.
02

Linear Velocity of Rims

For two discs of different radii in contact at their rims, the key to understanding the effects of friction lies in their linear velocities. The linear velocity (v) of a point on the rim of a disc is given by the product of its angular velocity (ω) and its radius (r): v = ω 11. Therefore, for the friction to disappear, the linear velocities at the contact points should be equal (v_1 = v_2).
03

Evaluating Angular Momentum Conservation

Before and after the interaction due to friction, angular momentum conservation applies because there is no external torque acting on the system. So the total angular momentum will be conserved. This implies the initial angular momentum of the system equals the final angular momentum.
04

Evaluating Rotational Kinetic Energy Conservation

Unlike angular momentum, rotational kinetic energy is generally not conserved in this type of interaction. Energy before and after contact changes due to work done by the friction force turning kinetic energy into heat, so the rotational kinetic energy of the system is not conserved.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frictional Force
Frictional force is a fundamental concept in physics, acting as a resistance to the motion of two surfaces sliding against each other. In the scenario where two rotating discs make contact at their rims, friction acts to bring equality between their initially unequal velocities. It plays a crucial role in the interaction at the point of contact. The friction acts until the linear velocities of the contact points on the rims of both discs become equal. This means that if one disc is initially moving faster, the frictional force will slow it down while speeding up the stationary disc until balance is reached.
  • Friction arises due to the microscopic interactions between surfaces.
  • It is dependent on the nature of the surfaces and the normal force pressing them together.
Once the frictional force has equalized the linear velocities, it ceases to act, indicating that relative motion at the contact has stopped. This dynamic understanding of friction allows us to predict how interconnected systems will behave when friction is present.
Linear Velocity
Linear velocity refers to the speed at which a point on the object's surface travels in a straight line. It can be determined when considering rotating objects, as is the case with the two discs in contact. The linear velocity of a point on the rim can be calculated using:\[v = \omega \cdot r\]where \(v\) is the linear velocity, \(\omega\) is the angular velocity, and \(r\) is the radius.
  • The longer the radius, the greater the linear velocity for a given angular velocity.
  • Linear velocity is crucial for understanding how different parts of a rotating object move.
In the context of the exercise, the frictional force aims to make the linear velocities at the contact point of both rims equal. Ensuring this equality causes friction to disappear, as there is no longer a differential in motion for the force to act upon. Understanding this principle is essential for solving problems involving rotating systems.
Rotational Kinetic Energy
Rotational kinetic energy is the energy an object possesses due to its rotation, given by the formula:\[KE_{rot} = \frac{1}{2}I\omega^2\]Here, \(I\) is the moment of inertia and \(\omega\) is the angular velocity. This type of energy is distinguished from linear kinetic energy as it specifically pertains to objects in rotational motion.In the frictional interaction of the two discs, the rotational kinetic energy is not conserved due to energy transformations. As friction works, some of the rotational kinetic energy is converted into thermal energy, resulting in energy loss from the system.
  • Rotational kinetic energy varies with the square of the angular velocity.
  • The moment of inertia is a measure of an object's resistance to changes in its rotational motion.
This conversion is why, even though angular momentum is conserved (due to the absence of external torques), the total kinetic energy decreases. Understanding rotational kinetic energy helps in comprehending how energy changes in systems where rotational motion is pertinent.

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Most popular questions from this chapter

A solid sphere, a hollow sphere and a disc, all having the same mass and radius, are placed at the top of an incline and released. The friction coefficients between the objects and the incline are same and not sufficient to allow pure rolling. The least time will be taken in reaching the bottom by (1) the solid sphere (2) the hollow sphere (3) the disc (4) all will take the same time

A thin uniform rod of mass \(m\) and length \(l\) is kept on a smooth horizontal surface such that it can move freely. At what distance from centre of rod should a particle of mass \(m\) strike on the rod such that the point \(P\) at a distance \(I / 3\) from the end of the rod is instantaneously at rest just after the elastic collision? (1) \(/ / 2\) (2) \(1 / 3\) (3) \(l / 6\) (4) \(l / 4\)

A solid sphere of mass \(3 \mathrm{~kg}\) is kept on a horizontal surface. The coefficient of static friction between the surfaces in contact is \(2 / 7 .\) What maximum force can be applied at the highest point in the horizontal direction so that the sphere does not slip on the surface? (in \(\mathrm{N}\) )

An impulse \(J\) is applied on a ring of mass \(m\) along a line passing through its centre \(O\). The ring is placed on a rough horizontal surface. The linear velocity of centre of ring once it starts rolling without slipping is (1) \(\mathrm{J} / \mathrm{m}\) (2) \(J / 2 m\) (3) \(J / 4 m\) (4) \(J / 3 m\)

A particle of mass ' \(m\) ' is rigidly attached at ' \(A\) ' to a ring of mass ' \(3 m\) ' and radius ' \(r\) '. The system is released from rest and rolls without sliding. The angular acceleration of ring just after release is (1) \(\frac{g}{4 r}\) (2) \(\frac{g}{6 r}\) (3) \(\frac{g}{8 r}\) (4) \(\frac{g}{2 r}\)

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