/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A uniform disc is rotating at a ... [FREE SOLUTION] | 91Ó°ÊÓ

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A uniform disc is rotating at a constant speed in a vertical plane about a fixed horizontal axis, passing through the centre of the disc. A piece of disc from its rim detaches itself from the disc at the instant when it is on the same horizontal with the centre of the disc and moving upwards. Then about the fixed axis, the angular speed of the (1) remaining disc remains unchanged (2) remaining disc decreases (3) remaining disc increases (4) broken away piece decreases initially and later increases

Short Answer

Expert verified
The angular speed of the remaining disc remains unchanged.

Step by step solution

01

Understand the System

The disc is rotating in a vertical plane about a fixed horizontal axis at its center. A piece from its rim detaches itself when it is at the same horizontal level as the center and moving upwards.
02

Conservation of Angular Momentum

Since no external torque acts on the system about the axis, the total angular momentum of the system is conserved. If a piece breaks off, the remaining disc and the detached piece must together maintain the original angular momentum.
03

Analyze Angular Momentum Before Separation

Let the initial angular velocity of the disc be \( \omega_0 \) and the moment of inertia be \( I_0 \). Thus, the initial angular momentum is \( I_0 \omega_0 \).
04

Analyze Angular Momentum After Separation

When the piece detaches, the disc loses a portion of its mass. Suppose the broken piece’s mass is \( m \) and radius is \( R \). The angular momentum of the broken piece is \( mR^2 \omega_0 \). The remaining disc’s angular momentum must be \( I_0 \omega_0 - mR^2 \omega_0 \).
05

Determine the Change in Moment of Inertia

The remaining disc's moment of inertia is reduced by \( mR^2 \) since the piece is at the rim (maximizing its contribution to inertia).
06

Apply Conservation Equation

The new angular velocity \( \omega_1 \) of what is left of the disc is found using: \[ (I_0 - mR^2)\omega_1 = I_0 \omega_0 - mR^2 \omega_0 \]. You solve for \( \omega_1 \).
07

Derive the Result

Simplifying the expression: \( \omega_1 = \omega_0 \). As the loss does not change the direct product of inertia and angular speed, the remaining disc's angular speed remains unchanged.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The concept of "moment of inertia" is crucial in understanding the rotational dynamics of any object. Think of it as the rotational equivalent of mass for linear motion. It determines how much torque (a rotational force) is required for a certain angular acceleration about an axis. The moment of inertia depends on how the mass is distributed with respect to the axis of rotation. For a uniform disc rotating about its central axis, the moment of inertia is calculated using the formula:
  • For a disc of mass \( M \) and radius \( R \), the moment of inertia \( I \) is given by \( I = \frac{1}{2} MR^2 \).
When a piece of the disc detaches, the moment of inertia must be recalculated because the distribution of mass changes. If a piece of mass \( m \) from the rim is removed, the moment of inertia decreases by \( mR^2 \). This change affects how the object will continue to rotate when external forces aren't applied.
Rotational Motion
Rotational motion refers to the motion of an object around a fixed axis. When objects rotate, every point within the object moves in a circle around an axis. This is equivalent to how linearly moving objects exhibit motion along a straight path. Terms like rotational speed and angular displacement describe this motion.
  • The rotational trajectory remains constant when no external torques (forces that cause rotation) act on the system.
  • Rotational motion is an integral part of many mechanical processes, from simple wheels to complex machinery.
In the context of the exercise, the uniform disc experiences rotational motion. This movement is characterized by a constant speed, as no external forces alter the motion at the moment when a piece breaks away.
Angular Velocity
Angular velocity is a measure of how quickly an object rotates or spins. It is the rate at which the angular position changes with time, typically measured in radians per second. The equation for angular velocity \( \omega \) is:
  • \( \theta / t \), where \( \theta \) is the change in angular position and \( t \) is time.
In the case of the rotating disc, the angular velocity is initially \( \omega_0 \). Despite a portion of the mass detaching, the angular velocity of the remaining disc remains unchanged according to the conservation of angular momentum.
When the piece detaches, the angular momentum of the entire system is conserved. That means, even if the moment of inertia changes because of the detached piece, the system adapts by adjusting the angular velocity of the remaining disc to keep the total angular momentum consistent:
  • Initial angular momentum = Final angular momentum,\( I_0 \omega_0 = (I_0 - mR^2) \omega_1 \)
  • Solving the equation gives \( \omega_1 = \omega_0 \), keeping the angular velocity of the rest of the disc the same.

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