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If \(I_{1}\) is the moment of inertia of a thin rod about an arig perpendicular to its length and passing through its centre of mass, and \(I_{2}\) is the moment of inertia (about central axis) of the ring formed by bending the rod, then (1) \(I_{1}: I_{2}=1: 1\) (2) \(I_{1}: I_{2}=\pi^{2}: 3\) (3) \(I_{1}: I_{2}=\pi: 4\) (4) \(I_{1}: I_{2}=3: 5\)

Short Answer

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The correct answer is (2) \(I_{1} : I_{2} = \pi^{2} : 3\).

Step by step solution

01

Define the Moment of Inertia of a Thin Rod about Its Center

The moment of inertia of a thin rod of mass \(m\), length \(L\), about an axis perpendicular to its length and passing through its center is given by the formula: \[ I_1 = \frac{1}{12} m L^2. \]
02

Define the Moment of Inertia of a Thin Ring

When the rod is bent into a ring (circle), its mass distributes along the circumference. If the circumference is \(L\), the radius \(R\) of the ring can be expressed as: \[ 2\pi R = L \Rightarrow R = \frac{L}{2\pi}. \]The moment of inertia of a ring (a circle) of mass \(m\) with radius \(R\) about its axis is: \[ I_2 = m R^2. \]
03

Substitute Radius into the Moment of Inertia of the Ring

Substitute the radius from Step 2 into the ring's moment of inertia formula:\[ I_2 = m \left(\frac{L}{2\pi}\right)^2 = m \frac{L^2}{4\pi^2}. \]
04

Calculate and Compare Moment of Inertia Ratio \(I_1 : I_2\)

Now, compare \(I_1\) and \(I_2\):\[ \frac{I_1}{I_2} = \frac{\frac{1}{12} m L^2}{\frac{m L^2}{4\pi^2}} = \frac{\pi^2}{3}. \]Hence, the ratio \(I_1 : I_2 = \pi^2 : 3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Thin Rod
A thin rod, in physics, is an elongated, slender object with its mass mostly distributed along its length. Such rods are often used in moment of inertia problems to simplify calculations and understand physical behaviors. It has a length, usually denoted as \( L \), and a mass, \( m \).
When considering the moment of inertia, we typically concern ourselves with how the mass is distributed across different points of the object. For a thin rod, the mass distribution is uniform across its length if the rod is of consistent density. This symmetry makes calculations more straightforward.
Moment of inertia for a thin rod about an axis perpendicular to its length and passing through its center is calculated using the formula: \( I_1 = \frac{1}{12} m L^2 \). This formula incorporates the rectangular distribution of mass and provides insight into how easily the rod can rotate around said axis.
Role of the Central Axis
The central axis plays a crucial role in calculating the moment of inertia. It refers to the line that passes through the center mass of an object, such as a rod or sphere, about which it rotates.
Understanding the location of the central axis is important because it affects the calculated resistance against rotational motion. For example, a rod rotating about its central axis (perpendicular to its length) will demonstrate a different moment of inertia than if rotated about one of its ends.
For a thin rod, this central axis is halfway through its length. This symmetry is crucial because it ensures the mass is evenly distributed around the axis during rotation, directly influencing the outcome of the inertia calculations. Thus, the axis choice is pivotal when discussing rotational dynamics.
Bending Into a Ring
When a thin rod bends into a ring, it undergoes a transformation where its linear structure becomes circular. This change significantly affects its physical properties, including the moment of inertia. The process involves reshaping the rod so that it forms a loop or circle, changing its mass distribution from a linear to a circular format.
The key to understanding this transformation lies in how the physical properties of the rod, such as mass and length, convert to properties of the new circular shape. The initial length of the rod becomes the circumference of the ring, giving us a new parameter—radius—calculated as \( R = \frac{L}{2\pi} \).
This radius is crucial in calculating the moment of inertia of the new ring formation. By understanding this relationship, one can draw parallels between the rigidity and rotational behavior of the original rod and its ring counterpart.
Mass Distribution and Its Effects
Mass distribution is a fundamental concept when considering the moment of inertia because it directly impacts an object's rotational dynamics. In a thin rod, the mass is distributed linearly, meaning each part of the rod contributes proportionately to the moment of inertia based on its distance from the axis.
When the rod is bent into a ring, the mass is distributed along the circumference. This results in a different style of mass distribution, requiring different calculations. Each element of the mass travels a circular path, affecting the rotational resistance in new ways.
For this ring, the moment of inertia formula reflects this by using the radius, showing that parts of the ring farther from the axis contribute more heavily to the overall moment of inertia. The formula \( I_2 = m \left(\frac{L}{2\pi}\right)^2 \) highlights the significance of both mass and how it's spread across a physical structure, confirming that without appropriately considering mass distribution, calculations of rotational dynamics would be inaccurate.

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Most popular questions from this chapter

For the same total mass, which of the following will have the largest moment of inertia about an axis passing through the centre of gravity and perpendicular to the plane of body? (1) A ring of radius / (2) A disc of radius / (3) A square lamina of side \(2 l\) (4) Four rods forming square of side \(2 /\)

From a complete ring of mass \(M\) and radius \(R\), a \(30^{\circ}\) sector is removed. The moment of inertia of the incomplete ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is (1) \(\frac{9}{12} M R^{2}\) (2) \(\frac{11}{12} M R^{2}\) (3) \(\frac{11.3}{12} M R^{2}\) (4) \(M R^{2}\)

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For a body having pure rotation motion. The axis of reatil (1) may pass through the centre of mass (2) must pass through the centre of mass (3) may pass through a particle of the body (4) must nass through a particle of the body

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