/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 54 Two identical particles \(A\) an... [FREE SOLUTION] | 91Ó°ÊÓ

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Two identical particles \(A\) and \(B\) of mass \(m\) each are connecte together by a light and inextensible string of length \(l . \mathrm{T}\) particle are held at rest in air in same horizontal level at separation \(l\). Both particles are released simultaneously an one of them (say \(A\) ) is given speed \(v_{0}\) vertically upwan The maximum height attained by the centre of mass of 4 system of \(A\) and \(B\) from initial level is (Ignore air resistanca (1) \(\frac{v_{0}^{2}}{2 g}\) (2) \(\frac{v_{0}^{2}}{8 g}\) (3) \(\frac{v_{0}^{2}}{4 g}\) (4) \(\frac{v_{0}^{2}}{12 g}\)

Short Answer

Expert verified
The maximum height attained by the center of mass is \( \frac{v_0^2}{4g} \), option (3).

Step by step solution

01

Set up the system and concepts

The system consists of two particles connected by a string. Initially, they are at rest at the same horizontal level and separated by a distance \( l \). Particle \( A \) is given an initial velocity \( v_0 \) upwards. We need to determine how high the center of mass of \( A \) and \( B \) rises. We will apply the conservation of energy and center of mass motion concepts.
02

Consider initial conditions

Initially, particle \( A \) has a velocity of \( v_0 \) upward, and particle \( B \) remains at rest. The center of mass of a system of particles is determined by the average position of the masses, weighted by their masses. The initial vertical velocity of the center of mass is determined by the formula \( v_{cm} = \frac{m v_0 + m \cdot 0}{2m} = \frac{v_0}{2} \). Thus, the vertical kinetic energy associated with the center of mass is \( K_{cm} = \frac{1}{2} (2m) \left(\frac{v_0}{2}\right)^2 = \frac{mv_0^2}{4} \).
03

Apply conservation of energy

Since there is no external force doing work on the system in the vertical direction (ignoring air resistance as per the problem statement), the mechanical energy conservation principle applies. Initially, the center of mass has kinetic energy \( \frac{mv_0^2}{4} \) and zero gravitational potential energy. At maximum height, all kinetic energy is converted into potential energy \( U_{cm} \). Using \( U_{cm} = mgh_{cm} \), we have \( mgh_{cm} = \frac{mv_0^2}{4} \).
04

Solve for the maximum height of the center of mass

Rearrange the equation \( mgh_{cm} = \frac{mv_0^2}{4} \) to solve for the maximum height \( h_{cm} \):\[ h_{cm} = \frac{v_0^2}{4g}\]Thus, the maximum height attained by the center of mass of particles \( A \) and \( B \) is \( \frac{v_0^2}{4g} \).
05

Choose the correct option

Referring to the options provided, the correct option corresponding to the calculated maximum height \( \frac{v_0^2}{4g} \) is option (3).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Energy
The conservation of energy principle is an important concept in physics that states that energy cannot be created or destroyed; it can only be transformed from one form to another. In the context of the exercise, we primarily consider two forms of energy: kinetic energy and gravitational potential energy.

Initially, the system has kinetic energy and no potential energy because both particles start at the same level, and potential energy is referenced relative to a height. As particle \(A\) moves upwards with velocity \(v_0\), we observe a conversion of kinetic energy into potential energy.
  • Initial kinetic energy: Due to particle \(A\) moving upwards.
  • Potential energy: This is the energy stored due to the height attained against gravitational force.

The total mechanical energy in the system remains the same, making conservation of energy essential for solving the exercise and determining the height via the center of mass motion.
Kinetic Energy
Kinetic energy refers to the energy that an object possesses due to its motion. It can be calculated using the formula: \( KE = \frac{1}{2}mv^2 \), where \(m\) is the mass and \(v\) is the velocity of the object. Initially, particle \(A\) is given an upward velocity \(v_0\), which imparts kinetic energy to the system.

In the center of mass frame:
  • Only particle \(A\) has an initial velocity, thus possessing kinetic energy \( \frac{mv_0^2}{2} \).
  • The center of mass of the system has reduced kinetic energy because it considers the average velocity of the system, leading us to \( \frac{mv_0^2}{4} \) as part of the center of mass kinetic energy calculation.

Knowing the initial kinetic energy is pivotal because it will convert entirely into potential energy at the peak height of the center of mass, helping us find the solution efficiently.
Potential Energy
Potential energy refers to the energy stored in an object due to its position in a force field, typically gravitational. In this exercise, as particle \(A\) rises, it gains potential energy by converting its kinetic energy.

The gravitational potential energy, \( U \), is calculated by the formula: \( U = mgh \), where \( h \) is the height above the reference point, and \( g \) is the acceleration due to gravity. This conversion is significant because:
  • Initially, the system has zero potential energy, as both particles are considered at a level starting point.
  • At maximum height of the center of mass, the potential energy equals the initial kinetic energy because of energy conservation.
This conversion allows us to equate initial kinetic energy to final potential energy and solve for the height, affirming that as kinetic energy decreases, potential energy increases.
Mechanical Energy
Mechanical energy in a system is the sum of its kinetic and potential energy. For this exercise, mechanical energy is preserved throughout the motion of the system relying on the conservation of energy principle.

This means:
  • Initially, the system has all its mechanical energy as kinetic energy due to particle \(A\).
  • As the motion progresses, kinetic energy transforms into potential energy as \(A\) ascends.

When the center of mass reaches its highest point, the mechanical energy is fully in the form of gravitational potential energy. Thus,
  • Mechanical energy at the start = \(\frac{mv_0^2}{4}\).
  • Mechanical energy at the maximum height = \(mgh_{cm}\)
This constancy allows us to compute the maximum height attained and ensure that mechanical energy remains balanced between kinetic and potential forms throughout the motion.

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Most popular questions from this chapter

An object comprises of a uniform ring of radius \(R\) and its uniform chord \(A B\) (not necessarily made of the same material) as shown. Which of the following can not be the centre of mass of the object? (1) \(\left(\frac{R}{3}, \frac{R}{3}\right)\) (2) \(\left(\frac{R}{3}, \frac{R}{2}\right)\) (3) \(\left(\frac{R}{4}, \frac{R}{4}\right)\) (4) None of these

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