/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 A particle is moving along a cir... [FREE SOLUTION] | 91Ó°ÊÓ

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A particle is moving along a circular path with uniform speed. Through what angle does its angular velocity chan? when it completes half of the circular path? (1) \(0^{\circ}\) (3) \(180^{\circ}\) (2) \(45^{\circ}\) (4) \(360^{\circ}\)

Short Answer

Expert verified
The angular velocity changes by \(180^{\circ}\).

Step by step solution

01

Understanding Angular Displacement in Circular Motion

When a particle moves with uniform speed along a circular path, the angle through which it moves in terms of angular displacement is same as the angle it covers on the circular path.
02

Calculating Angular Displacement for Half the Circle

A full circle corresponds to an angular displacement of \(360^{\circ}\). Therefore, if a particle completes half of a circular path, the angular displacement is \(360^{\circ} \div 2 = 180^{\circ}\).
03

Connecting Angular Displacement to Angular Velocity Change

Since angular velocity is a vector that points in the direction of rotational motion, completing half a circle changes the direction of the velocity vector by \(180^{\circ}\), despite the velocity magnitude staying constant.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is all about how fast something spins around a point or axis. Imagine a wheel on a bike; as you pedal, it spins. The speed at which it spins is its angular velocity. In mathematical terms, angular velocity, often represented by the Greek letter \( \omega \), is the rate of change of angular displacement over time.

It's measured in units like radians per second (rad/s) or degrees per second (°/s). Unlike linear velocity that moves things in a straight line, angular velocity revolves things around a center.
  • Think of it as the spinning speed of objects.
  • It tells you how many angles an object covers in a given time.
When it comes to vector quality, angular velocity has both a magnitude and a direction. The direction depends on the rotational motion and can be determined using the right-hand rule. Simply put, if you curve your right-hand fingers in the direction of rotation, your thumb will point in the direction of the angular velocity. Even when speed is uniform, like in circular motion, the direction of angular velocity can change.
Angular Displacement
Angular displacement refers to the angle through which an object moves on a circular path. It is essentially the angle between the initial and final points of the path. If you imagine starting at some point on a circular track and moving halfway around, that's an angular displacement.

This concept differs from linear displacement, which measures the shortest path between two points. In circular motion, angular displacement is specific to the curve and not a straight line.
  • Measured in degrees (°) or radians.
  • For a complete circle, the angular displacement is \(360^{\circ}\) or \(2\pi\) radians.
  • For half a circle, it's \(180^{\circ}\) or \(\pi\) radians.
In the exercise, when the particle completes half of the circular path, its angular displacement is \(180^{\circ}\). This matches how angular displacement directly affects any changes in motion or direction associated with objects in circular paths.
Uniform Speed
Uniform speed means traveling the same distance in the same amount of time, consistently. Picture a train moving along its track at a steady pace, covering equal segments of distance in equal intervals of time. This is an example of uniform speed. In circular motion, even if the object constantly changes directions, its speed remains the same.

However, the direction of the object's velocity changes because it continues following a circular trajectory. Here's what's important about uniform speed:
  • The speed (not velocity) stays constant along the path.
  • It's expressed in units like meters per second (m/s) or kilometers per hour (km/h).
  • In circular motion, uniform speed pairs with changing direction to form uniform circular motion.
Even when moving at uniform speed, a particle moving in a circular path will change its velocity because of the change in direction, while maintaining speed, like how it was mentioned in the original step by step solution.

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Most popular questions from this chapter

The angular acceleration of a particle moving along a circle is given by \(\alpha=k \sin \theta\), where \(\theta\) is the angle turned by particle and \(k\) is constant. The centripetal acceleration of the particle in terms of \(k, \theta\) and \(R\) (radius of circle) is given by: (1) \(2 k R\left(\sin ^{2} \theta\right)\) (2) \(2 k R(\sin \theta)\) (3) \(2 k R(1+\cos \theta)\) (4) \(2 k R(1-\cos \theta)\)

Two identical particics we string which passes through a hole at the center of a table of the particles is made to move in a circle on that string which passes througit One of the particles is made to move in a circle on the tabl with angular velocity \(\omega\), and the other is made to \(\mathrm{m}\), in a horizontal circle as a contact pendulum with angular velocity pendulum with angular velocity \(\omega_{2} .\) If \(l_{1}\) and \(l_{2}\) are the length of he string over and under the able, then in order that particle under the table neither moves own nor moves up, the ratio \(l_{1} / l_{2}\) is (1) \(\frac{\omega_{1}}{\omega_{2}}\) (2) \(\frac{\omega_{2}}{\omega_{1}}\) (3) \(\frac{\omega_{1}^{2}}{\omega_{2}^{2}}\) (4) \(\frac{\omega_{2}^{2}}{\omega_{1}^{2}}\)

If the angular frequency of the rotation of the plate is \(\omega=\sqrt{\frac{g}{2 R}}\). The friction force acting on coin is (1) \(\frac{3}{4} m g \rightarrow\) (2) \(\frac{m g}{4} \leftarrow\) (3) \(\frac{m g}{2} \leftarrow\) (4) \(\frac{m g}{2} \rightarrow\)

Two particles describe the same circle of radius \(R\) in the same direction with the same speed \(v\), then at the given instant relative angular velocity of 2 with respect to 1 will be (1) \(\frac{2 v \sin \frac{\theta}{2}}{R}\) (2) \(\frac{v}{2 R \sin \frac{\theta}{2}}\) (3) \(\frac{v}{R}\) (4) \(\frac{v \cos \frac{\theta}{2}}{R}\)

A force of constant magnitude \(F=10 \mathrm{~N}\) acts on a particle moving in a plane such that it is perpendicular to the velocity \(\vec{v}(|\vec{v}|=v=5 \mathrm{~m} / \mathrm{s})\) of the body, and the force is always directed towards a fixed point. Then the angle (in radian) turned by the velocity vector of the particle as it covers a distance \(S=10 \mathrm{~m}\) is (take: mass of the particle as \(m=2 \mathrm{~kg}\) )

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