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\(A\) and \(B\) are moving in 2 circular orbits with angular velocity \(2 \omega\) and \(\omega\) respectively. Their positions are as shown at \(t=0 .\) Find the time when they will meet for first time. (1) \(\frac{\pi}{2 \omega}\) (2) \(\frac{3 \pi}{2 \omega}\) (3) \(\frac{\pi}{\omega}\) (4) they will never meet

Short Answer

Expert verified
Option (4): They will never meet at the times listed.

Step by step solution

01

Determine Initial Angular Positions

At time \( t = 0 \), let's assume the initial angular positions of both \( A \) and \( B \) are \( \theta_A(0) = 0 \) and \( \theta_B(0) = 0 \), as no specific initial angles are provided. This is for simplification to find when they next match positions.
02

Establish Angular Displacement Formulas

The angles traversed by \( A \) and \( B \) at time \( t \) are given by \( \theta_A(t) = 2\omega t \) and \( \theta_B(t) = \omega t \) respectively, since \( A \) and \( B \) move with angular velocities \( 2\omega \) and \( \omega \).
03

Set the Condition for Meeting

For \( A \) and \( B \) to meet, their angular positions must be equal, i.e., \( \theta_A(t) = \theta_B(t) \). Therefore, we need to solve the equation \( 2\omega t = \omega t + 2k\pi \), where \( k \) is an integer, to reflect that angles repeat every \( 2\pi \).
04

Solve for Time \( t \)

Simplifying the equation \( 2\omega t = \omega t + 2k\pi \), we get \( \omega t = 2k\pi \). Thus, \( t = \frac{2k\pi}{\omega} \). The first non-zero positive time occurs when \( k = 1 \), giving \( t = \frac{2\pi}{\omega} \).
05

Compare with the Provided Options

Comparing \( t = \frac{2\pi}{\omega} \) with the given options, we notice it is not explicitly listed. Thus, \( A \) and \( B \) will not meet at any of the given answer times, leading to the conclusion they will never meet first at any listed time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Velocity
Angular velocity is a key concept in understanding how fast an object revolves around a circular path. It is defined as the rate of change of angular displacement with respect to time, which can be mathematically expressed as \( \omega = \frac{d\theta}{dt} \), where \( \omega \) represents angular velocity and \( \theta \) represents angular displacement.

For example, consider a point moving in a circular path. If it takes 2 seconds to complete a circle of 360 degrees, then its angular velocity can be calculated by dividing the total angular displacement, 360 degrees, by the time taken, 2 seconds. This yields an angular velocity of \( 180 \) degrees per second.

In the context of the problem, both objects \( A \) and \( B \) are rotating through circular paths but with different angular velocities, specifically \( 2\omega \) for \( A \) and \( \omega \) for \( B \). This implies that for any given time, \( A \) completes its revolution twice as fast as \( B \). Understanding their angular velocities is crucial to predicting when, if ever, their paths cross.
Circular Motion
Circular motion refers to the movement of an object along the circumference of a circle or a circular path. Key characteristics include constant speed along the path, known as uniform circular motion, or varying speed, in which case it's called non-uniform circular motion.
  • In uniform circular motion, the speed remains constant but the direction changes continuously.
  • The change in direction results in a centripetal acceleration directed towards the center of the circle.

The object is effectively constrained to a fixed radius from the center, resulting in predictable angular behavior that can be modeled using angular velocity.

For instance, in our exercise, objects \( A \) and \( B \) are both engaged in circular motion where \( A \) describes its circle twice as rapidly as \( B \) due to its higher angular velocity. Circular motion, particularly harmonious among rotating systems, leads to periodic encounters if the phases align. However, the problem demonstrates an instance where such alignment does not happen within the given options.
Periodic Motion
Periodic motion is a motion that repeats itself at regular time intervals—this repetition is known as the period. Not only can it refer to vibrations and oscillations, but circular motion is a form of periodic motion as well.
  • The period of a circular motion is the time it takes for one complete revolution.
  • Angular velocity directly influences the period since a higher angular velocity results in a shorter period.

In our exercise, since \( A \) has an angular velocity of \( 2\omega \) while \( B \) has \( \omega \), \( A \) completes its circuit in half the time as \( B \), reflecting its shorter period of completion.

Periodic motion ensures consistent and predictable occurrence within each cycle. However, timing differences brought on by dissimilar angular velocities cause the periodic paths of \( A \) and \( B \) not to align for the given times in the multiple-choice options. This reveals how the subtle interplay of angular velocities affects the timing and synchronization of periodic motion.

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Most popular questions from this chapter

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