/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 A block of \(4 \mathrm{~kg}\) ma... [FREE SOLUTION] | 91Ó°ÊÓ

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A block of \(4 \mathrm{~kg}\) mass starts at rest and slides a distance \(d\) down a friction less incline (angle \(30^{\circ}\) ) where it runs into a spring of negligible mass. The block slides an additional \(25 \mathrm{~cm}\) before it is brought to rest momentarily by compressing the spring. The force constant of the spring is \(400 \mathrm{~N} \mathrm{~m}^{-1}\), The value of \(d\) is (take \(g=10 \mathrm{~m} \mathrm{~s}^{-2}\) ) (1) \(25 \mathrm{~cm}\) (2) \(37.5 \mathrm{~cm}\) (3) \(62.5 \mathrm{~cm}\) (4) None of the above

Short Answer

Expert verified
The value of \( d \) is \( 37.5 \text{ cm} \).

Step by step solution

01

Identify Problem Context

We have a block sliding down a frictionless incline, compressing a spring. We need to find an initial distance 'd' that the block slides before impacting the spring.
02

Understand Given Data

Mass of block: \( m = 4 \text{ kg} \), angle of incline: \( \theta = 30^{\circ} \), distance the spring compresses \( x = 0.25 \text{ m} \), spring constant \( k = 400 \text{ N/m} \), acceleration due to gravity \( g = 10 \text{ m/s}^2 \).
03

Use Energy Conservation Principle

The mechanical energy in the system before and during compression must be accounted for. The potential energy lost by the block sliding down converts to kinetic energy and then to potential energy of the spring.
04

Calculate Potential Energy

The potential energy due to gravity when the block has moved a distance \( d + x \) along the incline is \( U_g = mgh = mg(d+x)\sin\theta \).
05

Calculate Spring Potential Energy

The spring potential energy when fully compressed is \( U_s = \frac{1}{2} k x^2 \).
06

Set Up Energy Conservation Equation

Equate the gravitational potential energy to spring potential energy:\[ mg(d+x)\sin\theta = \frac{1}{2} k x^2 \].
07

Substitute and Calculate

Substitute the known values and solve for \( d \): \[ 4 \times 10 \times (d + 0.25) \times \sin 30^{\circ} = \frac{1}{2} \times 400 \times 0.25^2 \].Simplifying, we have:\[ 20(d + 0.25) = 12.5 \].Finally, solve for \( d \):\[ d + 0.25 = 0.625 \Rightarrow d = 0.375 \text{ m} \].
08

Convert To Required Units

Convert the value of \( d \) from meters to centimeters: \( d = 0.375 \text{ m} = 37.5 \text{ cm} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Potential Energy
Potential energy is a type of energy that is stored within an object due to its position or state. In mechanics, it's most commonly associated with gravitational potential energy, which is energy that an object possesses because of its height above a reference point. In our exercise, the gravitational potential energy is initially present due to the block being positioned at a certain height on a frictionless incline.
The formula to calculate gravitational potential energy is: \[ U_g = mgh \]where:
  • \( U_g \) is the gravitational potential energy,
  • \( m \) is the mass of the object,
  • \( g \) is the acceleration due to gravity, and
  • \( h \) is the height of the object above the reference point.
In our problem, the block moves down the incline covering a distance \( d + x \). The height \( h \) is calculated using the incline's angle \( \theta \) by the relation \( h = (d + x) \sin \theta \). Consequently, the potential energy as the block moves is related to both the distance it travels and the angle of the incline.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. When the block slides down the ramp, it transforms potential energy into kinetic energy as it gains speed. Initially, the block has no kinetic energy because it starts at rest. As it slides down the incline, gravitational potential energy is converted to kinetic energy, allowing the block to move faster.The formula for kinetic energy is:\[ KE = \frac{1}{2}mv^2 \]where:
  • \( KE \) is the kinetic energy,
  • \( m \) is the mass of the object, and
  • \( v \) is the velocity of the object.
In our problem, as the block reaches the spring, all of the gravitational potential energy has been converted to kinetic energy. This kinetic energy will eventually be used to compress the spring, illustrating how energy transforms from one form to another.
Spring Force
Spring force is a particular type of force that acts upon a compressed or stretched spring. It follows Hooke’s Law, which states that the force needed to extend or compress a spring by some distance is proportional to that distance. The spring force is responsible for stopping the block by converting kinetic energy into spring potential energy.The formula according to Hooke's Law is:\[ F_s = -kx \]where:
  • \( F_s \) is the force exerted by the spring,
  • \( k \) is the spring constant, a measure of the stiffness of the spring, and
  • \( x \) is the displacement of the spring from its equilibrium position.
When the block compresses the spring, all the moving (kinetic) energy of the block is converted into potential energy of the spring: \[ U_s = \frac{1}{2} k x^2 \]This potential energy is stored in the spring as it compresses, and at the maximum compression, all the energy from the block's descent has transitioned into this form. Thus, the block is momentarily at rest before the process could potentially reverse and move the block back if there were no other forces acting on it.

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Most popular questions from this chapter

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