Chapter 3: Problem 21
In going from one city to another, a car travels \(75 \mathrm{~km}\) north, \(60 \mathrm{~km}\) north-west and \(20 \mathrm{~km}\) east. The magnitude of displacement between the two cities is (take \(1 / \sqrt{2}=0.7\) ) (1) \(170 \mathrm{~km}\) (2) \(137 \mathrm{~km}\) (3) \(119 \mathrm{~km}\) (4) \(140 \mathrm{~km}\)
Short Answer
Step by step solution
Analyze Directions and Components
Calculate Components for the Northwest Direction
Sum North-South Components
Calculate Overall East-West Components
Use Pythagorean Theorem to Find Displacement
Calculate Displacement Magnitude
Determine the Correct Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Components
- The journey is made up of three vectors: north, northwest, and east.
- Each vector can be broken down into its components, which align with the north-south and east-west axes.
Pythagorean Theorem
- The theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
- We have a displacement formed by `north` as one side and `west` as the other.
Directional Vectors
- Vectors in opposite directions, like east-west or north-south, can affect the total distance differently.
- By calculating direction, we can effectively manage the components, such as knowing how much distance is actually gained or lost.