Chapter 1: Problem 44
Using mass \((M)\), length \((L)\), time \((T)\), and electric current \((A)\) as fundamental quantities, the dimensions of permittivity will be (1) \(\left[M L T^{-1} A^{-1}\right]\) (2) \(\left[M L T^{-2} A^{-2}\right]\) (3) \(\left[M^{-1} L^{-3} T^{4} A^{2}\right]\) (4) \(\left[M^{2} L^{-2} T^{-2} A\right]\)
Short Answer
Step by step solution
Understand the Concept
Use Known Equations
Determine Dimensions from Coulomb's Law
Simplify the Dimensions
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dimensional Analysis
- Every physical quantity can be described in terms of these four basic dimensions.
- This approach helps us simplify and understand how different physical ingredients interact within equations.
Coulomb's Law
- \(F\) is the force between charges.
- \(q_1\) and \(q_2\) are the amounts of both charges.
- \(r\) is the distance between their centers.
- \(\varepsilon\) is the permittivity of the medium between the charges.
Fundamental Quantities
- Mass (\(M\)): Represents the amount of matter in an object.
- Length (\(L\)): Refers to the extent of something along its greatest dimension.
- Time (\(T\)): Measures the progression of events from the past to the future.
- Electric Current (\(A\)): The rate at which electric charge flows past a point in a circuit.