/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The frequency \((n)\) of vibrati... [FREE SOLUTION] | 91Ó°ÊÓ

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The frequency \((n)\) of vibration of a string is given as \(n=\frac{1}{2 l} \sqrt{\frac{T}{m}}\), where \(T\) is tension and \(l\) is the length of vibrating string, then the dimensional formula is (1) \(\left[M^{0} L^{1} T^{1}\right]\) (2) \(\left[M^{0} L^{0} T^{0}\right]\) (3) \(\left[M^{1} L^{-1} T^{0}\right]\) (4) \(\left[M L^{0} T^{0}\right]\)

Short Answer

Expert verified
The dimensional formula is \([M^0 L^0 T^{-1}]\).

Step by step solution

01

Identify Dimensional Formula Components

We need to find the dimensional formula of the frequency term \(n\), where the given formula is \(n = \frac{1}{2l}\sqrt{\frac{T}{m}}\). Frequency has the dimensional formula \([T^{-1}]\). We'll find dimensional formulas for each part, like tension \(T\), length \(l\), and mass \(m\), and combine them.
02

Determine Dimensional Formulas for Variables

The tension \(T\) has a dimensional formula of \([M^1 L^1 T^{-2}]\) as it is force. The length \(l\) has a dimensional formula of \([L^1]\). The mass per unit length \(m\) has a dimensional formula of \([M^1 L^{-1}]\).
03

Analyze the Form inside the Square Root

Inside the square root, we have \(\frac{T}{m}\). Substitute the dimensional formulas: \[ \frac{T}{m} = \frac{[M^1 L^1 T^{-2}]}{[M^1 L^{-1}]} \] which simplifies to \([L^2 T^{-2}]\).
04

Calculate the Dimension of Square Root Term

Find the dimension of \(\sqrt{\frac{T}{m}}\) which is \(\sqrt{[L^2 T^{-2}]} = [L^1 T^{-1}]\).
05

Calculate the Complete Frequency Formula Dimension

Now we calculate the dimensional formula of \(n = \frac{1}{2l}\sqrt{\frac{T}{m}}\). Substitute: \[ n = \frac{1}{[L^1]} [L^1 T^{-1}] = [T^{-1}] \]. This represents a pure frequency.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency of Vibration
In physics, frequency of vibration refers to how often a vibrating object completes a full oscillation cycle per unit time. It is crucial in understanding how strings produce sound in musical instruments. The frequency \(n\) is typically measured in Hertz (Hz), where one Hertz is one cycle per second. In vibrating strings, frequency is influenced by several factors such as the tension in the string, the mass per unit length, and the length of the string itself.
Organizations optimize these three aspects to produce desired sound pitches. The formula given in our problem \(n = \frac{1}{2l}\sqrt{\frac{T}{m}}\) captures these relationships, indicating how tension and mass per unit length directly impact vibrational characteristics.
  • Higher tension \(T\) or shorter length \(l\) results in a higher frequency.
  • Increased mass per unit length \(m\) decreases frequency.
Tension in String
Tension is a force that stretches a string and significantly impacts its vibration. It plays a crucial role in determining the frequency of vibration explained in the problem. For strings, this tension \(T\) is part of the equation \(n = \frac{1}{2l}\sqrt{\frac{T}{m}}\), illustrating that as the tension increases, the frequency of vibration also increases.
The dimensional formula for tension is expressed as \([M^1 L^1 T^{-2}]\), showing that its dimensions are equivalent to those of force. This is because tension essentially results from applying force.
  • Higher tension typically means a tauter string, leading to faster visible oscillations.
  • Musicians adjust tension to tune their instruments to the desired pitch.
Dimensional Formula
A dimensional formula expresses a physical quantity in terms of its basic dimensions (Mass, Length, and Time). It helps to understand and confirm the relationship between different physical quantities, serving as a check for equations.
For frequency \(n\), it is essential to determine its dimensional formula from the given formula \(n = \frac{1}{2l}\sqrt{\frac{T}{m}}\). The final dimensional formula for frequency is \([T^{-1}]\), indicating it is an event occurring over time.
  • Dimensional analysis verifies units on both sides of an equation to ensure it is dimensionally consistent.
  • It helps in deriving formulas and converting units.
Using dimensional analysis in this context ensures the formula confidently represents a frequency characteristic.
Mass per Unit Length
Mass per unit length \(m\) is a notable factor in the vibration of strings. It relates to how mass is distributed along the length of the string, crucial for understanding vibrations and sound production.
In the formula \(n = \frac{1}{2l}\sqrt{\frac{T}{m}}\), \(m\) is inversely proportional to frequency: as the mass per unit length increases, frequency decreases.
The dimensional formula for mass per unit length is derived as \([M^1 L^{-1}]\), signifying mass spread across a segment of string length.
  • Thin strings (less mass per unit length) typically produce higher frequencies and sound pitches.
  • Heavier strings (more mass per unit length) are generally utilized for lower pitch sounds.
Understanding mass per unit length is fundamental for tasks like designing and playing musical instruments.

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