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If \(\left(A+\frac{B}{C^{2}}\right)(D-x)=y\), then (1) dimensions of \(A\) and \(B\) must be same (2) dimensions of \(A\) and \(B\) may be same (3) dimensions of \(D\) and \(x\) must be same (4) dimensions of \(A D\) and \(y\) must be same

Short Answer

Expert verified
Statements 1, 3, and 4 are correct interpretations based on the equation.

Step by step solution

01

Understand the Equation

We start with the given equation \(\left(A+\frac{B}{C^{2}}\right)(D-x)=y\). The goal is to analyze the dimensional consistency of the terms involved in this equation.
02

Analyze the Term Inside Parentheses

First, consider the term \(A+\frac{B}{C^{2}}\). For this term to be dimensionally consistent, \(A\) and \(\frac{B}{C^{2}}\) must have the same dimensions. Therefore, the dimensions of \(A\) and \(B\) must be the same if \(C\) is dimensionless. Thus, statement (1) is correct.
03

Consider Dimensions of \(D-x\)

When subtracting two terms, they must have the same dimensions. Therefore, the dimensions of \(D\) and \(x\) must be the same. This makes statement (3) correct.
04

Dimensional Analysis of the Whole Expression

Simplifying, we have \(\left(A+\frac{B}{C^{2}}\right)(D-x) = y\). The initial term \(A+\frac{B}{C^{2}}\) must be dimensionless or must multiply by \((D-x)\) to match the dimensions of \(y\). Thus, the product of the dimensions of \(A\) and \(D\) must match \(y\), making statement (4) correct.
05

Evaluate Optionality of Step 2

In Step 2, we determined \(A\) and \(B\) must have the same dimensions when \(C\) is dimensionless. If \(C\) were to carry units, it might be possible for \(\frac{B}{C^{2}}\) to have different dimensions than \(A\), in which case the statement is not as strict. However, from the options we have, this analysis wasn't given more context, so we use the stricter solution rendering statement (2) partially accurate when not simplifying \(C\) to dimensionless. Nevertheless, for clarity and correctness adhering to the problem as originally simplified, we agree with statement (1) on most occasions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dimensions in Physics
In physics, the term 'dimensions' refers to the physical nature of a quantity. Dimensions express how a particular physical quantity relates to fundamental measurements such as length, mass, time, etc. Represented typically by notations like \([L]\) for length, \([M]\) for mass, and \([T]\) for time, dimensions help articulate the nature of physical quantities without focusing on numerical values or units like meters or seconds.

By considering dimensions, physicists can better understand relationships between quantities instead of getting bogged down by units. For example, in the exercise, when considering terms like \(A\) or \(B\), analyzing their dimensions helps confirm if they could logically interact within the equation \((A+\frac{B}{C^{2}})(D-x)=y\). Understanding and evaluating these dimensions is crucial to ensuring an equation retains physical meaning.
Dimensional Consistency
Dimensional consistency is a fundamental concept to ensure the correctness of a mathematical equation in physics. It implies that every term in a physical equation should have the same dimensions. Objects that can be added, subtracted, or set equal to each other must share identical dimensions.

In the given problem, analyzing \(A+\frac{B}{C^{2}}\) shows the necessity for \(A\) and \(\frac{B}{C^{2}}\) to match dimensionally. This requirement ensures we are mathematically combining quantities of the same physical nature. The success of computations involving physics heavily relies on this principle to maintain accurate representation of reality.
  • A term like \(D-x\) must also adhere to this principle, ensuring \(D\) and \(x\) are dimensionally identical before subtraction.
  • The product of dimensions must align similarly with the output or derived dimensions such as \(y\).
Mathematical Equations
Mathematical equations in physics use symbols to denote mathematical operations and relationships between variables. They are essential in translating physical phenomena into a quantifiable format.

In the problem \( (A+\frac{B}{C^{2}})(D-x)=y\), we see a standard algebraic expression, where terms are involved in addition, division, multiplication, and subtraction. Each operation implies a relationship, and the equation captures an interaction within the physical system that maintains its validity through dimensional consistency.

Understanding these equations, particularly ensuring all calculations respect dimensionally consistent terms, creates a robust framework. This is crucial for solving physics problems effectively and demonstrates how mathematical tools harmonize with physical concepts.
JEE Advanced Physics
JEE Advanced is a highly competitive examination in India for aspiring engineers. Physics problems encountered in this exam demand a strong grasp of fundamental concepts, including dimensional analysis.

Questions like the exercise presented, which involve dimensional consistency, are vital for students to tackle effectively. Such problems refine students' ability to logically dissect an equation and develop an intuitive understanding of underlying physical principles. Reflecting on these aspects:
  • Understanding dimensions aids in eliminating incorrect options swiftly.
  • Mastering dimensional analysis can illuminate methods to solve even complex problems under time constraints.
Becoming adept with these techniques prepares students for both current challenges and future scenarios in engineering and science fields.

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Most popular questions from this chapter

If in a new hypothetical system of units, the new unit of mass is \(5 \mathrm{~kg}\), new unit of length is 10 meter and new unit of time is 20 seconds, choose the correct statement(s). (1) 1 SI unit of velocity is equal to 2 new units of velocity. (2) 1 SI unit of power is equal to 16 new units of power. (3) 1 SI unit of energy is equal to \(5 / 4\) new unit of energy. (4) I SI unit of force is equal to 10 new units of force.

The length \(l\), breadth \(b\), and thickness \(t\) of a block of wood were measured with the help of a measuring scale. The results with permissible errors (in \(\mathrm{cm}\) ) are \(l=15.12 \pm 0.01, b=10.15 \pm 0.01\), and \(t=5.28 \pm 0.01\) The percentage error in volume up to proper significant figures is (1) \(0.28 \%\) (2) \(0.35 \%\) (3) \(0.48 \%\) (4) \(0.64 \%\)

In a new system of units, the net force applied on a block of mass \(10 \mathrm{~kg}\) moving with acceleration \(10 \mathrm{~m} / \mathrm{s}^{2}\) is given as 100 unit of force. When the same block is moving at a speed of \(20 \mathrm{~m} / \mathrm{s}\), its kinetic energy become 20 unit of energy. A liquid has a surface tension of 10 SI units. What is the magnitude of its surface tension in new system? (Dimensional formula of surface tension is \(\left.M L^{0} T^{-2} .\right)\)

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A spherical body of mass \(m\) and radius \(r\) is allowed to tall in a medium of viscosity \(\eta\). The time in which the velocity of the body increases from zero to \(0.63\) times the terminal velocity \((v)\) is called time constant \((\tau)\). Dimensionally, \(\tau\) can be represented by (2) \(\sqrt{\frac{6 \pi m r \eta}{g^{2}}}\) (1) \(\frac{m r^{2}}{6 \pi \eta}\) (3) \(\frac{m}{6 \pi \eta r v}\) (4) None of these

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