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Energy-angular momentum relation for a satellite. Express in terms of the angular momentum \(J\) the kinetic, potential, and total energy of a satellite of mass \(M\) in a circular orbit of radius \(r\).

Short Answer

Expert verified
The energies expressed in terms of angular momentum include \( KE = \frac{J^2}{2Mr^2} \), with potential energy less directly & total energy simplified to gravitational related forms.

Step by step solution

01

Define Angular Momentum

The angular momentum of a satellite in a circular orbit is given by \( J = Mvr \) where \( M \) is the satellite's mass, \( v \) is the orbital speed, and \( r \) is the orbit radius.
02

Express Orbital Speed in Terms of Angular Momentum

Using the equation from Step 1, we can solve for the orbital speed \( v \). Thus, \( v = \frac{J}{Mr} \).
03

Determine Kinetic Energy

The kinetic energy of a satellite in orbit is given by \( KE = \frac{1}{2} Mv^2 \). Substituting \( v = \frac{J}{Mr} \), we find \( KE = \frac{1}{2} M \left(\frac{J}{Mr}\right)^2 = \frac{J^2}{2Mr^2} \).
04

Calculate Potential Energy

The gravitational potential energy for a satellite in a circular orbit is expressed as \( PE = -\frac{G M M_e}{r} \), where \( M_e \) is the Earth's mass and \( G \) is the gravitational constant. Potential energy does not depend on \( J \) directly, but can be expressed by using orbital speed that is derived from gravitational force equilibrium if needed.
05

Derive Total Energy

In a circular orbit, the total energy \( E \) is: \( E = KE + PE \). Using \( KE = \frac{J^2}{2Mr^2} \) and \( PE = -\frac{G M M_e}{r} \), we can express the total energy. However, if simplified using gravitational force relations, we find \( E = -\frac{G M M_e}{2r} \), which can be related back to kinetic expression post-evaluation of specific conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Momentum
Angular momentum is a fascinating concept when we talk about satellites orbiting around planets, like Earth. It is a property of any rotating object and is defined as the product of the object's mass, velocity, and the radius of rotation. For a satellite in a circular orbit, the angular momentum (J) can be expressed as:
  • J = Mvr
Here, \( J \) represents the angular momentum, \( M \) is the mass of the satellite, \( v \) is its velocity, and \( r \) is the radius of its orbit. This relationship shows us that if we know two of the variables, we can find the third. Angular momentum is crucial because it remains constant in an orbit if no external torque acts on the satellite.
Kinetic Energy
Kinetic energy in the context of satellite mechanics refers to the energy associated with the motion of the satellite. It's given by the formula:
  • KE = \( \frac{1}{2} Mv^2 \)
Substituting the expression for orbital velocity in terms of angular momentum, \( v = \frac{J}{Mr} \), we can rewrite the kinetic energy as:
  • \[ KE = \frac{J^2}{2Mr^2} \]
This formula illustrates how kinetic energy depends on both the angular momentum and orbit radius. The larger the angular momentum, the higher the kinetic energy, as the satellite moves faster or has more mass. Understanding this is important because kinetic energy comparison often helps in assessing the satellite's speed and energy management in its orbit.
Potential Energy
Potential energy in orbital mechanics refers primarily to gravitational potential energy. For a satellite orbiting Earth, this is affected by the gravitational force between the satellite and the planet. It is calculated by the formula:
  • PE = \(-\frac{G M M_e}{r}\)
Where \( G \) is the gravitational constant, \( M \) is the satellite's mass, \( M_e \) is Earth's mass, and \( r \) is the orbit's radius. This formula shows the energy due to the satellite's position in the gravitational field. Notably, potential energy is always negative, reflecting that work must be done against gravity to move the satellite further away from Earth. Although potential energy isn't directly expressed in terms of angular momentum, it is vital when considering the full energy dynamics of an orbit.
Satellite Mechanics
Satellite mechanics encompass the study of satellites' motion and the forces acting upon them. Key elements include calculations of speed, energy, and orbital stability. In a circular orbit, these themes intertwine seamlessly with angular momentum, kinetic, and potential energy.Total energy (E) in an orbit is the sum of kinetic and potential energy, giving us a sense of the satellite's energy status. For circular orbits, although derived from a different approach, it is expressed technically by:
  • \(E = KE + PE\)
  • \(E = -\frac{G M M_e}{2r}\)
Such a simplified expression reflects a balance: while kinetic energy is positive, potential energy is negative and larger in magnitude making the total energy negative. This negative total energy signifies a bound orbit, meaning the satellite is gravitationally tied to its planet and moves smoothly along its orbit. Reviewing satellite mechanics holistically helps us ensure the satellite remains functional, efficiently consumes energy, and doesn't drift erratically.

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Most popular questions from this chapter

Frictional effects on satellite motion (a) What is the effect of atmospheric friction on the motion of a satellite in a circular (or nearly circular) orbit? Why does friction inerease the satellite velocity? (b) Does friction increase or decrease the angular momentum of the satellite measured with respect to the center of the earth? Why?

Ice skaters retolving on end of a rope. Two ice skaters, each weighing \(70 \mathrm{~kg}\), are traveling in opposite directions with speed \(650 \mathrm{~cm} / \mathrm{s}\) but separated by a distance of \(1000 \mathrm{~cm}\) perpendicular to their velocities. When they are just opposite each other, each grabs one end of a \(1000-\mathrm{cm}\) -long rope. (a) What is their angular momentum about the center of the rope before they grab the ends? After? (b) Each now pulls in on his end of the rope until the length of the rope is \(500 \mathrm{~cm}\). What is the speed of each? (c) If the rope breaks just as they get to \(500 \mathrm{~cm}\) apart, what mass would it hold up against the force of gravity? (d) Calculate the work done by each skater in decreasing their separation and show that this is equal to his change in kinetic energy.

Angular momentum of tetherball. The object of the game tetherball (Fig. 6.24) is to hit the ball hard enough and fast enough to wind its tether cord in one direction about the vertical post to which it is tied before the opposing player can wind it in the opposite direction. The game is exciting, and the dynamics of the ball's motion are complicated. Let us examine a simple type of motion in which the ball moves in a horizontal plane in a spiral of decreasing radius as the cord winds round the post after a single blow that gives the ball an initial speed \(v_{i 0}\). The length of the cord is \(l\) and the radius of the post is \(a \ll l\). (a) What is the instantaneous center of revolution? (b) Is there a torque about the axis through the center of the post? Is angular momentum conserved? (c) Assume that kinetic energy is conserved and calculate the speed as a function of time. (d) What is the angular velocity after the ball has made five complete revolutions?

Falling chain. A chain of mass \(M\) and length \(l\) is coiled up on the edge of a table. A very small length at one end is pushed off the edge and starts to fall under the force of gravity, pulling more and more of the chain off the table. Assume that the velocity of each element remains zero until it is jerked into motion with the velocity of the falling section. Find the velocity when a length \(x\) has fallen off. When the entire length \(l\) is just off the table, what fraction of the original potential energy has been converted into the kinetic energy of translation of the chain?

Electron bound to a proton. An electron moves about a proton in a circular orbit of radius \(0.5 \AA \equiv 0.5 \times 10^{-8} \mathrm{~cm}\). (a) What is the orbital angular momentum of the electron about the proton? (b) What is the total energy (expressed in ergs and in electron volts)? (c) What is the ionization energy, that is, the energy that must be given to the electron to separate it from the proton?

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