Chapter 7: Problem 2
Find the indefinite integral without using a table: \(\int \frac{1}{x(x-a)} d x\).
Short Answer
Expert verified
The integral \(\int \frac{1}{x(x-a)} dx\) is \(ln|\frac{x}{x-a}|\) when simplified.
Step by step solution
01
Perform Partial Fraction Decomposition
To start the problem, rewrite the integral in a more manageable form by using partial fraction decomposition. The integral \(\int \frac{1}{x(x-a)} dx\) can be written as \(\int \frac{A}{x} + \frac{B}{x-a} dx\), where A and B are constants that can be found by setting the sum of the fractions equal to the original fraction.
02
Solve for A and B
By setting \(\frac{1}{x(x-a)}\) equal to \(\frac{A}{x} + \frac{B}{x-a}\) and clearing the denominators, you get the equation 1=A(x-a)+Bx. By comparing coefficients, you can see that B=-A. Substituting the value of A=1 (which was obtained by setting x=0), B is also found to be -1.
03
Substitute A and B into the Integral
Substitute the values of A and B that were found in Step 2 into the integral. This gives \(\int \frac{1}{x} - \frac{1}{x-a} dx\).
04
Integrate Each Term
Now, it is straightforward to integrate each term of the integral. The integral of \(\frac{1}{x} dx\) is \(ln|x|\), and the integral of \(-\frac{1}{x-a} dx\) is \(- ln|x-a|\). This gives \(ln|x| - ln|x-a|\).
05
Simplify by Using Logarithmic Properties
Using the logarithmic property \(ln(a) - ln(b) = ln(\frac{a}{b})\), the final answer is simplified to \(ln|\frac{x}{x-a}|\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Partial Fraction Decomposition
Partial fraction decomposition is a technique used to integrate rational functions more easily. It takes a complex fraction and breaks it down into simpler fractions. In the exercise, we want to decompose \( \frac{1}{x(x-a)} \).
This is accomplished by expressing the fraction as a sum of two simpler fractions: \( \frac{A}{x} + \frac{B}{x-a} \).
Here’s how it works:
This is accomplished by expressing the fraction as a sum of two simpler fractions: \( \frac{A}{x} + \frac{B}{x-a} \).
Here’s how it works:
- First, rewrite the original fraction under consideration as a sum of partial fractions. In our case, it is set up as \( \frac{A}{x} + \frac{B}{x-a} \).
- Then, find A and B by multiplying both sides by the denominator, \( x(x-a) \), to get rid of the fractions. This yields the equation \( 1 = A(x-a) + Bx \).
- After deciding on strategic values for x, like \( x = 0 \) and \( x = a \), you can solve for A and B.
Integration Techniques
Integration techniques are fundamental methods used to solve integrals that are not straightforward. Once the partial fraction decomposition is complete, the integral can be approached in a simpler format. In this case, we are left with \( \int \frac{1}{x} - \frac{1}{x-a} \, dx \). There are some key techniques for integrating such functions:
- Direct Integration: Once resolved into simpler parts, direct integration is often the easiest method. Each simple fraction is integrated independently.
- The integral of \( \frac{1}{x} \, dx \) results in \( \ln|x| \), a common result because the derivative of \( \ln|x| \) is \( \frac{1}{x} \).
- With \( \frac{1}{x-a} \, dx \), you integrate it as if it were \( \frac{1}{u} \, du \), resulting in \( \ln|x-a| \).
Logarithmic Properties
Logarithmic properties can be powerful tools for simplifying expressions after integration. Once we integrate and obtain \( \ln|x| - \ln|x-a| \), we can simplify it further using properties of logarithms.
Some key properties are:
Some key properties are:
- One important property is \( \ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) \). This simplifies the expression from two logarithmic terms into a single term.
- This property helps to condense and make the solution more elegant and interpretable.
- In the given problem, applying this property gives us \( \ln\left|\frac{x}{x-a}\right| \) as the final result.