Chapter 8: Problem 6
Given $$ y=a+b \mathrm{e}^{-t} $$ where \(a\) and \(b\) are constants, state the value that \(y\) approaches as \(t\) increases.
Short Answer
Expert verified
As \( t \) increases, \( y \) approaches \( a \).
Step by step solution
01
Understand the expression
You are given the expression: \( y = a + b \mathrm{e}^{-t} \). Here, \(a\) and \(b\) are constants, and \(\mathrm{e}^{-t}\) is an exponential term where \(\mathrm{e}\) is the base of the natural logarithm.
02
Analyze the behavior of the exponential term
As \( t \) increases, the exponent \( -t \) becomes more negative. Therefore, \( \mathrm{e}^{-t} \), which is \( e \) raised to a large negative number, approaches zero. Mathematically, \( \lim_{{t \to \infty}} \mathrm{e}^{-t} = 0 \).
03
Determine the limiting value of \(y\)
Since \( \mathrm{e}^{-t} \) approaches zero as \( t \) increases, the term \( b \mathrm{e}^{-t} \) will also approach zero. Consequently, \( y \) simplifies to \( a + 0 \), which is \( a \).
04
Conclude the limit
Therefore, the value that \( y \) approaches as \( t \) increases is \( a \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Decay
Exponential decay is a fascinating concept where a quantity reduces at a rate proportional to its current value. In the context of the given function, this is represented by the term \( b\mathrm{e}^{-t} \). At its core, exponential decay indicates how rapidly the quantity diminishes over time. The negative exponent in \( t \) means the value of \( e^{-t} \) decreases swiftly as \( t \) becomes larger.
This is because \( e^{-t} \) is calculated by raising \( e \), approximately equal to 2.718, to the power of a negative number. As \( t \) increases, \( -t \) heads towards negative infinity, thus making \( e^{-t} \) approach zero rapidly.
This is because \( e^{-t} \) is calculated by raising \( e \), approximately equal to 2.718, to the power of a negative number. As \( t \) increases, \( -t \) heads towards negative infinity, thus making \( e^{-t} \) approach zero rapidly.
- This process is critical in natural settings, such as radioactive decay or cooling of hot objects.
- Understanding exponential decay helps in predicting how quickly the effects of initial conditions wane.
- It is used extensively in various fields, including physics, finance, and engineering.
Long-term Behavior
Understanding long-term behavior is essential when analyzing functions, as it provides insight into what happens to a function as time progresses or as variables approach infinity. In our function \( y = a + b\mathrm{e}^{-t} \), the long-term behavior tells us what value \( y \) will gravitate towards as \( t \) keeps increasing.
As \( t \to \infty \), the exponential term \( b\mathrm{e}^{-t} \) diminishes towards zero. Hence, the function simplifies to \( y = a \). This means, no matter the initial value of \( b\mathrm{e}^{-t} \), over time, its influence vanishes, leaving \( y \) constantly equal to \( a \).
As \( t \to \infty \), the exponential term \( b\mathrm{e}^{-t} \) diminishes towards zero. Hence, the function simplifies to \( y = a \). This means, no matter the initial value of \( b\mathrm{e}^{-t} \), over time, its influence vanishes, leaving \( y \) constantly equal to \( a \).
- This is crucial in systems that stabilize over time, such as temperatures equalizing in a room.
- Recognizing long-term behavior helps in making predictions and understanding the future state of the system.
Calculus Concept
In calculus, limits are a foundational concept used to study the behavior of functions as they approach specific points or infinity. The given exercise employs this concept by investigating what \( y \) approaches as \( t \to \infty \).
By calculating \( \lim_{{t \to \infty}} y \), we use calculus to discern the steady state or equilibrium value of \( y \). In this case, employing the limit shows that \( y \) approaches \( a \) due to the term \( b\mathrm{e}^{-t} \) tending towards zero.
The application of limits is crucial in many fields to predict long-term outcomes.
By calculating \( \lim_{{t \to \infty}} y \), we use calculus to discern the steady state or equilibrium value of \( y \). In this case, employing the limit shows that \( y \) approaches \( a \) due to the term \( b\mathrm{e}^{-t} \) tending towards zero.
The application of limits is crucial in many fields to predict long-term outcomes.
- Limits help us model behaviors in natural and applied sciences.
- They are indispensable in defining derivatives and integrals.