Chapter 8: Problem 4
The charge on a capacitor, \(C(t)\), decays according to the law $$ C(t)=100 \mathrm{e}^{-0.2 t} \quad t \geq 0 $$ (a) Calculate the charge when \(t=3\). (b) Calculate the charge when \(t=5\).
Short Answer
Expert verified
The charge at \(t=3\) is 54.88, and at \(t=5\) it is 36.79.
Step by step solution
01
Understanding the Problem
We are given a function for the charge on a capacitor, \(C(t) = 100 \mathrm{e}^{-0.2t}\). Our task is to find the charge at specific times: when \(t=3\) and when \(t=5\).
02
Substitute Time for Part (a)
For part (a), we need to find the charge \(C\) when \(t=3\). Substitute \(t=3\) into the equation: \(C(3) = 100 \mathrm{e}^{-0.2 \times 3}\).
03
Calculate the Exponent for Part (a)
Calculate the exponent: \(-0.2 \times 3 = -0.6\).
04
Evaluate the Exponential for Part (a)
Substitute the exponent into the exponential function: \(C(3) = 100 \mathrm{e}^{-0.6}\). Compute \(\mathrm{e}^{-0.6} \approx 0.5488\).
05
Calculate the Charge for Part (a)
Now calculate the charge: \(C(3) = 100 \times 0.5488 = 54.88\).
06
Substitute Time for Part (b)
For part (b), we need to find the charge \(C\) when \(t=5\). Substitute \(t=5\) into the equation: \(C(5) = 100 \mathrm{e}^{-0.2 \times 5}\).
07
Calculate the Exponent for Part (b)
Calculate the exponent: \(-0.2 \times 5 = -1.0\).
08
Evaluate the Exponential for Part (b)
Substitute the exponent into the exponential function: \(C(5) = 100 \mathrm{e}^{-1.0}\). Compute \(\mathrm{e}^{-1.0} \approx 0.3679\).
09
Calculate the Charge for Part (b)
Now calculate the charge: \(C(5) = 100 \times 0.3679 = 36.79\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Decay
Exponential decay is a fundamental concept in understanding how the charge on a capacitor decreases over time. At its simplest, exponential decay describes a process where a quantity decreases at a rate proportional to its current value. In this context, our charge function, \( C(t) = 100 e^{-0.2t} \) illustrates exponential decay.
The term \( e^{-0.2t} \) is what makes the function decay exponentially. Here, the base \( e \) is a constant approximately equal to 2.718, often called Euler's number. As time \( t \) increases, the exponent \( -0.2t \) becomes more negative, making the whole expression \( e^{-0.2t} \) smaller. Thus, the charge on the capacitor decreases, demonstrating exponential decay.
Understanding this process is key, as it appears in many natural phenomena where a quantity lessens quickly at first, and then slows over time. In a capacitor, it means that the charge will drop substantially initially, before leveling out more slowly.
The term \( e^{-0.2t} \) is what makes the function decay exponentially. Here, the base \( e \) is a constant approximately equal to 2.718, often called Euler's number. As time \( t \) increases, the exponent \( -0.2t \) becomes more negative, making the whole expression \( e^{-0.2t} \) smaller. Thus, the charge on the capacitor decreases, demonstrating exponential decay.
Understanding this process is key, as it appears in many natural phenomena where a quantity lessens quickly at first, and then slows over time. In a capacitor, it means that the charge will drop substantially initially, before leveling out more slowly.
Calculating Charge
Calculating the charge on a capacitor at a given time is a matter of evaluating the exponential function at that point. The exercise provides the function \( C(t) = 100 e^{-0.2t} \), and you simply substitute the desired time value of \( t \) into the equation.
For example, to find the charge at \( t=3 \):
Similarly, for \( t=5 \):
For example, to find the charge at \( t=3 \):
- First, substitute \( t = 3 \) into the function: \( C(3) = 100 e^{-0.2 \times 3} \).
- Calculate the exponent: \( -0.2 \times 3 = -0.6 \).
- Evaluate the exponential expression: \( e^{-0.6} \approx 0.5488 \).
- Finally, calculate the charge: \( C(3) = 100 \times 0.5488 = 54.88 \).
Similarly, for \( t=5 \):
- Substitute \( t = 5 \) into the function: \( C(5) = 100 e^{-0.2 \times 5} \).
- Calculate the exponent: \( -0.2 \times 5 = -1.0 \).
- Evaluate the exponential expression: \( e^{-1.0} \approx 0.3679 \).
- Calculate the charge: \( C(5) = 100 \times 0.3679 = 36.79 \).
Capacitor Function
The capacitor function describes how a capacitor stores and releases electrical energy. Fundamentally, a capacitor is a device that can store energy in an electric field by separating positive and negative charges on two conductive plates.
When charged, a capacitor holds a potential difference (voltage) between its plates. The charge it holds is dependent on this voltage and the capacitance, a characteristic of the capacitor that defines how much charge it can store at a given voltage.
Understanding how a capacitor functions not only helps in calculating decay, but also in designing circuits that efficiently manage electrical energy, which is crucial in electronics.
When charged, a capacitor holds a potential difference (voltage) between its plates. The charge it holds is dependent on this voltage and the capacitance, a characteristic of the capacitor that defines how much charge it can store at a given voltage.
- Capacitance is usually measured in farads (F).
- The energy stored in a capacitor is proportional to the square of the charge and inversely proportional to the distance between the plates.
Understanding how a capacitor functions not only helps in calculating decay, but also in designing circuits that efficiently manage electrical energy, which is crucial in electronics.