/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 Given three vectors \(\boldsymbo... [FREE SOLUTION] | 91Ó°ÊÓ

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Given three vectors \(\boldsymbol{a}, \boldsymbol{b}\) and \(\boldsymbol{c}\), their triple scalar product is defined to be \((\boldsymbol{a} \times \boldsymbol{b}) \cdot \boldsymbol{c}\). It can be shown that the modulus of this is the volume of the parallelepiped formed by the three vectors. Find the volume of the parallelepiped formed by the three vectors \(\boldsymbol{a}=3 \boldsymbol{i}+\boldsymbol{j}-2 \boldsymbol{k}, \boldsymbol{b}=\boldsymbol{i}+2 \boldsymbol{j}-2 \boldsymbol{k}\) and \(\boldsymbol{c}=2 \boldsymbol{i}+5 \boldsymbol{j}+\boldsymbol{k}\)

Short Answer

Expert verified
The volume of the parallelepiped is 49 cubic units.

Step by step solution

01

Setup the Vectors

Define the vectors as follows: \(\boldsymbol{a} = 3\boldsymbol{i} + \boldsymbol{j} - 2\boldsymbol{k}\), \(\boldsymbol{b} = \boldsymbol{i} + 2\boldsymbol{j} - 2\boldsymbol{k}\), and \(\boldsymbol{c} = 2\boldsymbol{i} + 5\boldsymbol{j} + \boldsymbol{k}\).
02

Compute the Cross Product \(\boldsymbol{a} \times \boldsymbol{b}\)

Use the determinant method for the cross product:\[\boldsymbol{a} \times \boldsymbol{b} = \begin{vmatrix}\boldsymbol{i} & \boldsymbol{j} & \boldsymbol{k} \3 & 1 & -2 \1 & 2 & -2\end{vmatrix}\]= \(\boldsymbol{i}(1 \cdot (-2) - (-2) \cdot 2) - \boldsymbol{j}(3 \cdot (-2) - 1 \cdot 2) + \boldsymbol{k}(3 \cdot 2 - 1 \cdot 1)\)= \(-2\boldsymbol{i} + 4\boldsymbol{i} + 6\boldsymbol{j} + 2\boldsymbol{j} + 6\boldsymbol{k} - \boldsymbol{k}\)= \(2\boldsymbol{i} + 8\boldsymbol{j} + 5\boldsymbol{k}\).
03

Compute the Dot Product \((\boldsymbol{a} \times \boldsymbol{b}) \cdot \boldsymbol{c}\)

The dot product of the result from the previous step with \(\boldsymbol{c}\):\[(2\boldsymbol{i} + 8\boldsymbol{j} + 5\boldsymbol{k}) \cdot (2\boldsymbol{i} + 5\boldsymbol{j} + \boldsymbol{k}) = 2\cdot2 + 8\cdot5 + 5\cdot1\]= \(4 + 40 + 5 = 49\).
04

Find the Magnitude

Since the result of the dot product is already a scalar, the magnitude is the absolute value of the scalar:\[|49| = 49\].
05

Conclude the Volume

The volume of the parallelepiped is the absolute value from Step 4. Therefore, the volume is \(49\) cubic units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Triple Scalar Product
The triple scalar product is a key concept in vector calculus. It involves three vectors, say \( \boldsymbol{a} \), \( \boldsymbol{b} \), and \( \boldsymbol{c} \). The triple scalar product is defined as \((\boldsymbol{a} \times \boldsymbol{b}) \cdot \boldsymbol{c}\). Here, the cross product \( \boldsymbol{a} \times \boldsymbol{b} \) results in a vector that is perpendicular to both \( \boldsymbol{a} \) and \( \boldsymbol{b} \), while the dot product with vector \( \boldsymbol{c} \) then gives a scalar value.
This scalar quantifies how much the vector \( \boldsymbol{c} \) influences the area spanned by \( \boldsymbol{a} \) and \( \boldsymbol{b} \). In geometric terms, the absolute value of this scalar represents the volume of the parallelepiped defined by these vectors. Essentially, the triple scalar product helps in finding the volume without directly constructing the solid.
Cross Product
The cross product, commonly symbolized by \( \times \), is a way to multiply two vectors in three-dimensional space, resulting in a new vector. For vectors \( \boldsymbol{a} = a_1\boldsymbol{i} + a_2\boldsymbol{j} + a_3\boldsymbol{k}\) and \( \boldsymbol{b} = b_1\boldsymbol{i} + b_2\boldsymbol{j} + b_3\boldsymbol{k}\), the cross product \(\boldsymbol{a} \times \boldsymbol{b}\) can be computed using the determinant of a \(3 \times 3\) matrix:
\[\boldsymbol{a} \times \boldsymbol{b} = \begin{vmatrix}\boldsymbol{i} & \boldsymbol{j} & \boldsymbol{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix}\].
The result is a vector perpendicular to both \( \boldsymbol{a} \) and \( \boldsymbol{b} \). The magnitude (length) of this vector is equal to the area of the parallelogram formed by \( \boldsymbol{a} \) and \( \boldsymbol{b} \). The cross product is pivotal in finding the orientation and scaling factor within the context of the triple scalar product.
Dot Product
The dot product, represented by \( \cdot \), is a fundamental operation where two vectors are multiplied to obtain a scalar. Given two vectors, \( \boldsymbol{u} = u_1\boldsymbol{i} + u_2\boldsymbol{j} + u_3\boldsymbol{k} \) and \( \boldsymbol{v} = v_1\boldsymbol{i} + v_2\boldsymbol{j} + v_3\boldsymbol{k} \), the dot product is calculated as:
\[\boldsymbol{u} \cdot \boldsymbol{v} = u_1v_1 + u_2v_2 + u_3v_3\].
This operation measures how much one vector extends in the direction of another, and is central to finding projections. In the triple scalar product, after finding a perpendicular vector to two original vectors via the cross product, the dot product with a third vector gives direct insight into geometric properties of the system. Specifically, the scalar value reflects the volume influence.
Parallelepiped Volume
A parallelepiped is a six-faced geometrical figure (also known as a polyhedron) where each face is a parallelogram. When defined by three vectors, its volume can be calculated using the triple scalar product. The formula \(|(\boldsymbol{a} \times \boldsymbol{b}) \cdot \boldsymbol{c}|\) reveals the volume when \( \boldsymbol{a} \), \( \boldsymbol{b} \), and \( \boldsymbol{c} \) are vectors that represent three edges meeting at one vertex.
The absolute value encompasses both the measure and direction of the volume, ensuring a non-negative result. Understanding this connection allows learners to transition from simple area calculations in two dimensions to more complex volume calculations in three dimensions, grasping how vector operations translate into these practical applications. This clarity is essential for visualizing multidimensional problems and their physical representations.

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Most popular questions from this chapter

Use the definition of the scalar product to show that, if two vectors are perpendicular, their scalar product is zero.

State, or find out, which of the following are scalars and which are vectors: (a) the volume of a petrol tank, (b) a length measured in metres, (c) a length measured in miles, (d) the angular velocity of a flywheel, (e) the relative velocity of two aircraft, (f) the work done by a force, (g) electrostatic potential, (h) the momentum of an atomic particle.

Line I has equation $$ r_{1}=\left(\begin{array}{l} 2 \\ 3 \\ 5 \end{array}\right)+k\left(\begin{array}{l} 1 \\ 2 \\ 4 \end{array}\right) $$ Line II has equation $$ r_{2}=\left(\begin{array}{c} -5 \\ 8 \\ 1 \end{array}\right)+l\left(\begin{array}{c} -6 \\ 7 \\ 0 \end{array}\right) $$ Different values of \(k\) give different points on line I. Similarly, different values of \(l\) give different points on line II. If the two lines intersect then \(r_{1}=r_{2}\) at the point of intersection. If you can find values of \(k\) and \(l\) which satisfy this condition then the two lines intersect. Show the lines intersect by finding these values and hence find the point of intersection.

Write down the definition of the scalar product of two vectors and illustrate your definition with a diagram.

If the triple scalar product \((\boldsymbol{a} \times \boldsymbol{b}) \cdot c\) is equal to zero, then (i) \(\boldsymbol{a}=\mathbf{0}\), or \(\boldsymbol{b}=\mathbf{0}\), or \(\boldsymbol{c}=\mathbf{0}\) or (ii) two of the vectors are parallel, or (iii) the three vectors lie in the same plane (they are said to be coplanar).

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