Chapter 9: Problem 11
Show \(\tan \left(180^{\circ}-\theta\right)=-\tan \theta\)
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Chapter 9: Problem 11
Show \(\tan \left(180^{\circ}-\theta\right)=-\tan \theta\)
These are the key concepts you need to understand to accurately answer the question.
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Convert the following angles to radians, giving your answer to 4 d.p.: (a) \(40^{\circ}\) (b) \(100^{\circ}\) (c) \(527^{\circ}\) (d) \(-200^{\circ}\)
If \(\tan \phi<0\) and \(\sin \phi>0\), state the quadrant in which \(\phi\) lies.
Convert the following angles in radians to degrees: (a) \(0.3609\) (b) \(0.4771\) (c) \(1.3692\) (d) \(\frac{\pi}{3}\) (e) \(\frac{2 \pi}{3}\) (f) \(6 \pi\) (g) \(\frac{\pi}{5}\) (h) \(\frac{3 \pi}{2}\)
A voltage source, \(v(t)\), varies with time, \(t\), according to $$ v(t)=50 \sin (\pi t+10) $$ State (a) the angular frequency, (b) the phase, (c) the amplitude, (d) the period, (e) the time displacement, (f) the frequency of the voltage.
Simplify $$ (\sin \theta+\cos \theta)^{2}-\sin 2 \theta $$
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