Chapter 23: Problem 4
The diameters of ball bearings produced in a factory follow a normal distribution with mean \(6 \mathrm{~mm}\) and standard deviation \(0.04 \mathrm{~mm}\). Calculate the probability that a diameter is (a) more than \(6.05 \mathrm{~mm}\), (b) less than \(5.96 \mathrm{~mm}\), (c) between \(5.98\) and \(6.01 \mathrm{~mm}\).
Short Answer
Step by step solution
Identify the given values
Calculate the z-score
Calculate probabilities using the standard normal table
Write the answers
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Z-score Calculation
- \( x \) is the value in the distribution
- \( \mu \) is the mean of the distribution
- \( \sigma \) is the standard deviation of the distribution
Standard Deviation
Probability Calculations
- The probability of a ball diameter being more than \(6.05\, \mathrm{mm}\) is \(1 - 0.8944 = 0.1056\), or \(10.56\%\).