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Vdraround the boundary of the square with vertices(1,0),(0,1),(1,0),(0,1) , ifV=x2i+5xj

Short Answer

Expert verified

The solution isVdr=10

Step by step solution

01

Given Information.

The given information is,V=x2i+5xj

02

Definition of Green’s Theorem.

Green's theorem connects a line integral around a simple closed curve C to a double integral over the plane region D circumscribed by C in vector calculus. Stokes' theorem has a two-dimensional special case.

03

Find the solution.

For, V=x2i+5xj

Vdx=x2dx+5xdy

Use Green鈥檚 theorem AQxPydxdy=APdx+Qdy, where Ais the boundary of the area A.

It can be seen that

P=x2Py

=0

role="math" Q=5xQx

=5

Since the contour is the boundary of the square with the given vertices, the area Ais then the area of the square.

Vdr=5(10)2+(01)22

=10

Hence, the solution is Vdr=10.

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